Yes! That is an error in my square brackets, but it doesn't change the rest of the question, as I used the calculator to evaluate the limits! I will pin your comment.
Blud is saving my mocks. Have you ever thought about starting a discord server where everyone who watches your videos can come together and help each other with homework or whatever else?
I have a Discord that I interact with a lot for the top tier of my memberships, but hadn't considered one for open access... mostly because I thought it would be a lot of admin... have you experience of joining a study Discord before?
At 11:20 when you vhanged the bounds of the integral it's still wrong because you've got 0^-1 = 1/0 in there, you just said it was 0 which is not right.
Make sure that you find the gradient first by differentiating, and then subbing in the x coordinate to that - that gives you the m part of y-y1=m(x-x1). Hope that helps!
You'd need to differentiate the curve, then find the gradient when x = 1, then use that gradient plus the coordinate (1, 3) to find an equation of a straight line!
can you do one for year2 integration i am struggling so much and i really want to be able to do my homework while its due after half term which is next sunday😩😩😩😩
I don't think I'll have the video done by then... however, I do have this video series which will be helpful for you: ua-cam.com/video/L6UkjiDVmWk/v-deo.htmlsi=o4QJvB5W1FAI86zy
For the last question, doesn't -8x^1/2 differentiate to -16/3x^3/2??
Yes! That is an error in my square brackets, but it doesn't change the rest of the question, as I used the calculator to evaluate the limits! I will pin your comment.
I've got an end of unit test tomorrow and you've posted this at just the right time. Thank you!
How did it go?
btw guys the di method for integration is allowed now, its in the 2024 june mark scheme so maybe learn that too
I'll do a video on this soon!
Blud is saving my mocks. Have you ever thought about starting a discord server where everyone who watches your videos can come together and help each other with homework or whatever else?
I have a Discord that I interact with a lot for the top tier of my memberships, but hadn't considered one for open access... mostly because I thought it would be a lot of admin... have you experience of joining a study Discord before?
@@BicenMaths yeah I have, you just need to add bots to the server that can help with a lot of the admin like censoring
At 11:20 when you vhanged the bounds of the integral it's still wrong because you've got 0^-1 = 1/0 in there, you just said it was 0 which is not right.
Yes, correct, my mistake! I will change it on the original question and this PDF so that it is a value that actually works!
when u find the tangent, is it not y - 3 = 2x - 4x^ -1/2 (x -1) ? but how would u get 2x+y-5 = 0
Make sure that you find the gradient first by differentiating, and then subbing in the x coordinate to that - that gives you the m part of y-y1=m(x-x1). Hope that helps!
@ oh ye thanks, forgot to sub in x=1
Hi quick question it says you will need to work it out but how do you know the equation of the line
You'd need to differentiate the curve, then find the gradient when x = 1, then use that gradient plus the coordinate (1, 3) to find an equation of a straight line!
can you do one for year2 integration i am struggling so much and i really want to be able to do my homework while its due after half term which is next sunday😩😩😩😩
I don't think I'll have the video done by then... however, I do have this video series which will be helpful for you: ua-cam.com/video/L6UkjiDVmWk/v-deo.htmlsi=o4QJvB5W1FAI86zy
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