Thank you very much ma'am...but I just have one doubt. When considering the current source, why does the current in the right loop remain as 'i' ?... please clear my doubt ma'am
@@rashmiagnihotritiwari8211 Thanks for quick update i need to develop cut -sets for the graph of a network and develop fundamental cut -set matrix for that i have to send network image.
Mam why we cannot apply KVL if current source present.? Or can you suggest any book for This topic... Because whenever i apply eq. It gives different different results.
@@rashmiagnihotritiwari8211 thank you mam.☺ Please mam,i have one more doubt. How can we replace a current source in superpostion theorem if it has internal resistance. Is this still replaced by open circuit ?
@@rashmiagnihotritiwari8211 mam current ki direction anticlock wise h jo given h quest m. Ap n kvl jb second source k ly apply kia tu durection neg rkhi but ist step m apnye q posi le?
Mam here how can u tell that the i in the dependent source is equal to the mesh current u have taken for a single source, beacouse here i is the current flowing through the 2ohm resistor when all the sources are connected all together.
mam just in case if we have two loops and in 1st loop we have resistors and dependent sources and in other loop we have only current source can we take the whole loop equation ???
In case of current source, it is must to apply KCl at that node and find current in first loop in terms of current source.Then apply KVL in first loop.
Its a Supermesh problem.To solve it using loop currents ,apply KVL in outer loop and KCL at any common junction between two meshes. Or pls refer my video on supermesh analysis ..
KVL can not be applied in inner meshes only if a single current source element is in common branch of two meshes. Also prefer KCL if current source is in outer loop and if voltage across current source is not known.
Thanks a lot Ma'am
Really helping a lot.
Keep it up!!
THANK YOU MAm
Thanks ma'am
THANK YOU MAM
Thanks
🔥🔥🔥🔥
Very nice!!
Good work
Thank you very much ma'am...but I just have one doubt. When considering the current source, why does the current in the right loop remain as 'i' ?... please clear my doubt ma'am
I started with notation i which is current in 2 Ohm resistor due to 2A current source .It is actually ic which I mentioned later.
Okay ma'am...I got it. Thank you very much for clearing the doubt ma'am..👍👍👍
@@rashmiagnihotritiwari8211 tnx ma'am
Thanks alot, if you talk in English it will be wonderful
Thank you Ma'am...👍👍👍
Thankyou so much
Good maam
Mam see last step.
8/5.5 how it is being
calculated such 16/11 how 5(5 becomes 11??
Thanks mam
And plz use long size of black board
Current will not be i when using superposition theorem it must be somether current but u considered it as same current i in all three cases
Mam 3rd source current ki smjh nhi ayi. K kstra input or output consider krna hai?? Kia formula h kch nh smjh ai last step ki
Dear Mam I have some query for fundamental cut set matrix please let me know best time to ask
You can ask here anytime. I rarely check my e-mails.
@@rashmiagnihotritiwari8211 Thanks for quick update i need to develop cut -sets for the graph of a network and develop fundamental cut -set matrix for that i have to send network image.
Please advice how can i send Image so you can guide me for it.
Ok. My e-mail id is rashmitiwari.jbp@gmail.com
@@rashmiagnihotritiwari8211 Hi Mam,Thanks a lot for email i already sent mail with Query please so required guidance on it.
How you have taken i current in loop due all sources
After removing 2 Amp current source, in this circuit only one outer loop remained. Thats why one current i is assumed.
Mam, please upload more maximum power transfer theorem curcit problem.
mam, third equation we need to consider the 3v voltage source, why you are not considered
Here 3V is considered as first ,secondly 4V and 2A as third souce.
@@rashmiagnihotritiwari8211 WHY DEPENDENT VOLTAGE SOURCE NOT CALCULATING AS A ANOTHER SOURCE
We consider only independent sources as they are actual energy sources.
Mam y u f taking -ve sign u r considering the currents in the same direction na
While applying KVL,take -ve sign if moving across loop in the direction of current, as it is drop across resistance ie + to -
mam in case:1 after applying kvl we get -6.5i but u wrote -5.5i
Mam why we cannot apply KVL if current source present.?
Or can you suggest any book for This topic...
Because whenever i apply eq. It gives different different results.
Don't apply KVl in the loop with current source, as voltage drop across current source is not known.
@@rashmiagnihotritiwari8211 thank you mam.☺
Please mam,i have one more doubt.
How can we replace a current source in superpostion theorem if it has internal resistance.
Is this still replaced by open circuit ?
When you taking 4v then you do mistake in sign when yo displace 4v from left side to right side
No,check it once more.I changed sign of both 5.5 i and 4v.
Haa..
@@rashmiagnihotritiwari8211 mam current ki direction anticlock wise h jo given h quest m.
Ap n kvl jb second source k ly apply kia tu durection neg rkhi but ist step m apnye q posi le?
Nice
Isn't that 3 when shifted to right side becomes minus -3
In that case it is -5.5i+3=0 ie i= 3/5.5= 6/11amp
Ma'am how can you take i current in both loop in the case of 2A current source
After removing 2 Amp current source,as in the new circuit only one loop is remained.Thats why this one current i in one outer loop.
When 2 Amp current source is present then applying Junction rule in mid branch lower jn, two currents in the loops are i and i+2.
Nice mam 👍👍
Mam here how can u tell that the i in the dependent source is equal to the mesh current u have taken for a single source, beacouse here i is the current flowing through the 2ohm resistor when all the sources are connected all together.
Voltage 0.5 i in the dependent source is dependent on current flowing through 2 Ohm resistor,either there is single source or multiple sources.
Mam pls make a video on superposition theorem using nodal or mesh analysis....pls mam😵😑
ua-cam.com/video/eMIywjuCx-s/v-deo.html
mam just in case if we have two loops and in 1st loop we have resistors and dependent sources and in other loop we have only current source can we take the whole loop equation ???
In case of current source, it is must to apply KCl at that node and find current in first loop in terms of current source.Then apply KVL in first loop.
See this link also:
ua-cam.com/video/HnXsG3ewCLw/v-deo.html
@@rashmiagnihotritiwari8211 thank you mam
She is the reason of my russian accent
I=-24/10.5 A
I need more problems
how to solve it using loop current.
Its a Supermesh problem.To solve it using loop currents ,apply KVL in outer loop and KCL at any common junction between two meshes.
Or pls refer my video on supermesh analysis ..
ua-cam.com/video/jTpvYs1Pm3s/v-deo.html
ua-cam.com/video/bSiJ64v5iMI/v-deo.html
Do you agree that we cannot use kvl in the smaller loops.
KVL can not be applied in inner meshes only if a single current source element is in common branch of two meshes. Also prefer KCL if current source is in outer loop and if voltage across current source is not known.
Using superpostion Theorem Find Current Ix... ?
aapne 0.5 current ke lie galat symbol banaya hai.... Vo dependet source ka symbol hai
0.5i is a voltage source, as it is shown in the diagram with + - sign. If arrow were there then it is taken as current source.
Two source simple method me ek bar banaye mame
It is 2 souce superposition problem....ua-cam.com/video/bokVdcUbHh0/v-deo.html
are you from madhya pradesh mam
Yes.
2nd step me 6.5i hoga apne galt kiya hai
At which moment. Mention the time.
..
0.5i ?? it should be 0.5V
it is dependent voltage source i.e. 0.5i .
😒😒