top left and bottom right always have to have 1 mole bottom left goes the molar mass of what you start with and the top right has to have the molar mass of what your solving for in the middle section goes the coefficients of the chemicals from the balanced reaction
Thank you so much, We can even short down it. The above equation 2C8H18. Gives. 16CO2 then 228grams of 2C8H18. Gives 704 grams of 16CO2 THEN 2800 grams gives 2800×704÷228 Which gives 8600 grams of CO2
Thank you very, very much for your explanation on Stoichiometry. After weeks of trying everyone, I never knew I would find someone like you to help me. I am so happy because I have my exam coming up later today. Thank you.
1) Write down the balanced chemical equation 2) Calculate the molar masses of the chemicals 3) Convert mass to moles of what you know 4) Convert moles of what you know to moles of what you want to know 5) Convert moles to mass of what you want to know 1 Mole This tells us the other part of the fraction is a molar mass conversion factor 00723
top left and bottom right always have to have 1 mole bottom left goes the molar mass of what you start with and the top right has to have the molar mass of what your solving for and the middle section is the coefficients of the chemicals from the balanced reaction 00410
the balanced reaction is used between the 2 unit conversions of mols and grams. The thing you're solving for is multiplied at the top and the thing you have is divided and the 2 numbers are used as coefficients. 00205
The conversion factor between one chemical I another is the balanced chemical decided by the other chemical. A trick I learned from this is the mole divided by the molar mass of the chemical mirror each other on each side.
The balanced reaction is used to convert the molar mass of the chemical we were starting with, in this example octane, to the chemical we were looking for, carbon dioxide. The balanced reaction is needed to take into consideration how many of each molecule is needed in the complete combustion. 00115
1 mol is always in the top left and bottom right. This figure reminds us that the other half of the fractions are molar masses. The number on the bottom left is the molar mass of what we're starting with, while the number on the top right is the molar mass of what we're solving for.
The chemical that you are solving for goes on top and the balanced reaction goes on the bottom, using numbers of elements, from a balanced reaction, 00421 (Elijah Tull)
The middle fraction are the numbers from the balanced reaction the chemical we are solving for goes on top and the one we are starting with goes on the bottom 00802
1 mole is always in the top left and the bottom right, this tells us that everything in between are molar masses. the fraction in the middle comes from the balanced equation itself. 00823
00403: Bottom left- molar mass of what you are starting with, important because it corresponds to what you start with Top Right- molar mass of what you are solving for, important because numbers on top correspond to what you are solving for
1) Write down the balanced chemical equation 2) Calculate the molar masses of the chemicals 3) Convert mass to moles of what you know 4) Convert moles of what you know to moles of what you want to know 5) Convert moles to mass of what you want to know Grams to moles 00407
@@ketzbook What's up with all the repetitive comments in this comment block?? Are they your students?? By the way nice videos, and website. You are a natural bro. 👨🎓👨💻🔬🔎📚✏👍💯🎓🤓
"Here's 12 of these questions, you have 15 minutes to complete the quiz" -Chemistry teachers
Sounds like my Steel design professor but with problems way harder and longer
top left and bottom right always have to have 1 mole
bottom left goes the molar mass of what you start with and the top right has to have the molar mass of what your solving for
in the middle section goes the coefficients of the chemicals from the balanced reaction
Thank you so much,
We can even short down it.
The above equation
2C8H18. Gives. 16CO2 then
228grams of 2C8H18. Gives 704 grams of 16CO2
THEN
2800 grams gives
2800×704÷228
Which gives 8600 grams of CO2
Anyways, your videos are always helpful! And your voice does not makes me feel sleepy.
Thank you very, very much for your explanation on Stoichiometry. After weeks of trying everyone, I never knew I would find someone like you to help me. I am so happy because I have my exam coming up later today. Thank you.
1) Write down the balanced chemical equation
2) Calculate the molar masses of the chemicals
3) Convert mass to moles of what you know
4) Convert moles of what you know to moles of what you want to know
5) Convert moles to mass of what you want to know
1 Mole
This tells us the other part of the fraction is a molar mass conversion factor
00723
I learned more in 6 minutes than 2 hours worth of BS video lectures from my professor. you are a god send!
Ok I wish I'd found this videos earlier.
A new trick I learned was that when a number in a balanced equation is not whole multiply the whole thing by 2 - 00401
The balanced equation is used between two unit conversions of moles to grams, 00415
Thank You So much
you are the best thank you so much
THANKYOU SO MUCH SIR THIS VIDEO HELP ME ALOT TO SOLVE SO MANY TRICKY QUESTIONS THANKYOU
you're welcome!
This is the reason I won’t fail my quiz tmr
He's sooo underrated
top left and bottom right always have to have 1 mole bottom left goes the molar mass of what you start with and the top right has to have the molar mass of what your solving for and the middle section is the coefficients of the chemicals from the balanced reaction 00410
the balanced reaction is used between the 2 unit conversions of mols and grams. The thing you're solving for is multiplied at the top and the thing you have is divided and the 2 numbers are used as coefficients. 00205
The conversion factor between one chemical I another is the balanced chemical decided by the other chemical. A trick I learned from this is the mole divided by the molar mass of the chemical mirror each other on each side.
It is used between the conversions of moles and grams, 00715
The balanced reaction is used to convert the molar mass of the chemical we were starting with, in this example octane, to the chemical we were looking for, carbon dioxide. The balanced reaction is needed to take into consideration how many of each molecule is needed in the complete combustion. 00115
1 mol is always in the top left and bottom right. This figure reminds us that the other half of the fractions are molar masses. The number on the bottom left is the molar mass of what we're starting with, while the number on the top right is the molar mass of what we're solving for.
Thank you for saving ma life
you're welcome!
@@ketzbook omg can't believe it's you. Thank you once again
It's used between the two unit conversions of moles and grams. The thing you are solving for is multiplied and the thing u have is divided.
I absolutely love you
The chemical that you are solving for goes on top and the balanced reaction goes on the bottom, using numbers of elements, from a balanced reaction, 00421 (Elijah Tull)
The middle fraction are the numbers from the balanced reaction the chemical we are solving for goes on top and the one we are starting with goes on the bottom 00802
00815: You use the balanced reaction in stoichiometry to determine the relative number of reactants and products
the numbers from the balanced reaction, the chemical solving for goes on the top and the balanced reaction is on the bottom
1 mole is always in the top left and the bottom right, this tells us that everything in between are molar masses. the fraction in the middle comes from the balanced equation itself. 00823
1 mol always goes in the top left and the bottom right because it reminds us that the other portion is the molar mass, 00418
Thank youuuuuuuu
Balanced reaction is in the middle of the three parentheses
I learned how to combine the three equations into one large conversion ; 00101
you put the balanced reaction into the middle of the three parentheses
008334
You lost me at “welcome” lol
00403: Bottom left- molar mass of what you are starting with, important because it corresponds to what you start with
Top Right- molar mass of what you are solving for, important because numbers on top correspond to what you are solving for
1) Write down the balanced chemical equation
2) Calculate the molar masses of the chemicals
3) Convert mass to moles of what you know
4) Convert moles of what you know to moles of what you want to know
5) Convert moles to mass of what you want to know
Grams to moles
00407
1 mole always goes in the top left and bottom right. This tells us the other part of the fraction is a molar mass conversion factor. 00213
ID:00404 The excess mass of the Carbon Dioxide came from the Oxygen; this is why its mass is larger than Octane's.
I learned how to combine three equations into one big step, 00806
Why I get 8632 and something when I calculate it? What could be the problem?
Me to even the scientific calculator agreed
Sir, I think that should be 8, 632 and not 8, 600?
You use the balanced reaction as your conversion factor, 00110
1 mol. Reminds us the other half of the fractions are molar masses, 00103
1mole is at the top left and the bottom right. Reminds us that the other half are molar masses
❤️ u........thank u soo much 🙏
we use the chemical we start with on the bottom and the chemical we are solving for goes on the top, 00417
Life saver
:)
In the middle of the fraction, the Chemical we are going for goes on top, and chemical we start out with goes on bottom, 00217
00803]
1) 1 mol in TL and BR
2) this "reminds us that the other half of those fractions are molar masses"
oh god oh god oh god oh god , this is so helpfulll !! i believe u can beat khan academy way more better ! u solv 6 yeas problemmssss. thanksssssss
1 mole is always in the top left and also the bottom right. This tells us that everything in between is considered the molar masses. 00818
1 mol goes in top left and bottom right conversions, 00416
the coefficients of the chemicals from the balanced reaction. 00412
Your balanced equation is the conversion factor in the moles to moles equation
I learned how to put 3 fractions into one to make the problems easier., 00821
The numbers from the bottom reaction, 00702
1 mol goes in the top left and bottom right. This tells us that everything in between are molar masses - 00108
Instead of having three separate calculations, you can combine the three conversions., 00811
The chemical that's getting solved goes on the top and the balanced reaction goes on the bottom right, 00608
In the middle fraction, the chemical we are going for goes on the top and the chemical we have goes on the bottom, 00607
Why the O becomes 25 please explain
1 mol, this reminds us that the other half of those fractions are molar masses. 00813
1 mole it reminds us that the other half of the problems are molar masses, 00703
because octane was being burned in excess air, the mass of oxygen made the mass of CO2 larger than Octane, 00824
love the trick!! Too many steps makes me not want to do it. Much thanks! xoxo
you're welcome!
the chemical you are solving for on top and the balanced reaction on the bottom,984311
Balanced reaction, 00707
did someone else solve the balance equation diffrent?
Igot
C8H8 + 10O2 = 8CO2 + 4H2O
How he get 44.01 ?
i learned to combine 3 equations into 1 big one, 00206
The mass of Co2 is larger than the mass of octane bc of the large amounts of oxygen compared to hydrogen in octane, 00409
i learned to combine 3 equations into 1 big one, 50678
The percent Yield is 0.8 percent, 00606
Balanced Reaction 00107
The mass of CO2 is larger than the mass of octane because of the excess air, O2, 00114
the mass of carbon dioxide is larger than the mass of octane. 00111
The mass of CO2 is larger because when the 2 Octane molecules are burned it creates 16 CO2 molecules (a much larger amount) 00610
Anyone else here cuz their teacher made them watch this vid then do notes?? Smfhhhhh😭💀😂😂
balanced reaction, 00812
00716 I learned to use 3 steps in one
Because octane is being burned in excess air, 00609
Balance reaction 00112
because CO2 has the higher molar mass in the equation
00224
Chad 🧡
The mass of CO2 is larger than the mass of octane because of the large amount of oxygen compared to the hydrogen in Octane. 00814
It is more oxygen in octane than hydrogen, 00209
CO2 is larger due to the amount of oxygen which makes it 3 times bigger than the mass of octane, 00214
1 mole, and tells us that half of the other factors are moler mass
The mass of CO2 is larger than the mass of octane because the extra mass came from the oxygen, 00119
oxygen makes the mass larger for carbon dioxide while octane is burned excess air. 00104
because of the oxygen in the carbon dioxide, 00204
00414
Hydrogen weighs less than oxygen
Its larger becuase CO2 has such a bigger mass, which is why it overrules octane, 00724
it is not 8600g co2 it is 8624g of co2
significant figures my friend, significant figures. There are only 2 significant figures, so it is 8600.
@@ketzbook What's up with all the repetitive comments in this comment block?? Are they your students?? By the way nice videos, and website. You are a natural bro. 👨🎓👨💻🔬🔎📚✏👍💯🎓🤓
@@waltersobchak7275 yes, some of these were my students answering a hw in the comments.
@@ketzbook Thanks Professor Ketz.
CO2 is larger than octane because of the excess air, 00419
Because CO2 has a larger molar mass 00709
FIRST!!!!
CO2 is larger because of the amount of oxygen compared to octane. 00719
Anyone from India!!
Anyone else get 8632g of CO2??