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Physix Daily
Приєднався 3 бер 2021
I am Prottoy.
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
Переглядів: 111
Відео
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
Переглядів 315 місяців тому
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
Переглядів 13611 місяців тому
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
Переглядів 36411 місяців тому
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
Problem 2.5: Introduction to Quantum Mechanics by David Griffiths
Переглядів 45711 місяців тому
Problem 2.4 : ua-cam.com/video/GdTpK418Ppo/v-deo.html
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
Переглядів 42111 місяців тому
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
Переглядів 11011 місяців тому
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
Переглядів 85611 місяців тому
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
Allowed Energy of particle trapped in the Infinite Square Well
Переглядів 154Рік тому
Here is the link to the Derivation of the Wave Function of particle in the Infinite Square Well: ua-cam.com/video/Ho-iJ-iR6lE/v-deo.html
The Infinite Square Well: Deriving the Wave Function
Переглядів 232Рік тому
The Infinite Square Well: Deriving the Wave Function
The Photoelectric Effect - Introduction
Переглядів 1582 роки тому
The Photoelectric Effect - Introduction
Derivation of the Mirror / Lens Equation
Переглядів 1152 роки тому
Derivation of the Mirror / Lens Equation
How to derive displacement function of Simple Harmonic Motion
Переглядів 1,2 тис.2 роки тому
How to derive displacement function of Simple Harmonic Motion
Deducing Lorentz Transformation Equations
Переглядів 1882 роки тому
Deducing Lorentz Transformation Equations
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
Переглядів 7062 роки тому
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
Springs, Mechanisms, Time Period and Work
Переглядів 1,4 тис.3 роки тому
Springs, Mechanisms, Time Period and Work
Potential and Kinetic Energy in SHM
Переглядів 4,9 тис.3 роки тому
Potential and Kinetic Energy in SHM
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
Переглядів 64 тис.3 роки тому
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
Heat Engine | Mechanism and Efficiency
Переглядів 383 роки тому
Heat Engine | Mechanism and Efficiency
Carnot's Engine | Mechanism and Work Done
Переглядів 833 роки тому
Carnot's Engine | Mechanism and Work Done
The Second and Third Law of Thermodynamics Explained in 6 mins
Переглядів 583 роки тому
The Second and Third Law of Thermodynamics Explained in 6 mins
Change in Entropy in Different Thermodynamics Processes
Переглядів 3913 роки тому
Change in Entropy in Different Thermodynamics Processes
Classic Problem 5 | Calculating "g" from time of flight
Переглядів 2543 роки тому
Classic Problem 5 | Calculating "g" from time of flight
Classic Problem 4 | Use of 1st Law of Thermodynamics
Переглядів 993 роки тому
Classic Problem 4 | Use of 1st Law of Thermodynamics
Why is Adiabatic Curve steeper than Isothermal Curve
Переглядів 14 тис.3 роки тому
Why is Adiabatic Curve steeper than Isothermal Curve
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
Переглядів 1313 роки тому
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
Relationship between Thermodynamics Variables in Adiabatic Process
Переглядів 1543 роки тому
Relationship between Thermodynamics Variables in Adiabatic Process
Why in the beginning x =ct ! Why there is c isn't x =vt , why every explanation someone had to do something looks wrong ?
W
In the letter a of the question, you use the propriety of kronecker delta to solve those integrals, and i got that. But explain to me why, on letter c you can't use the same propriety as doing the integrals by parts. For example, can't you use x=u implies du=dx, and dv= |psi1|^2dx implies v=1? I did by this and had the expect value equal 0. I know that is wrong because it doesn't make any sense physically, but i don't got why i can't use integration by parts :( Nice video, by the way! Very very good (sorry for my poor English).
How c= 1/2 A^2w^2
nice video
Correct me if im wrong but in part d for <p> isnt the answer (8/3)*(h bar/a)*sin(3ωt) ? also at 20:40 and 12:10 its stated that the ω=n^2*π^2*hbar^2/2ma^2 but h bar constant is h bar not h bar squared in ω equals
Thank you for your feedback. You're exactly right. What I missed in the very last line was the omega factor which I forgot to add. If you add in omega in the last line, you should be able to simplify to whatever you have.
omg this was so helpful thank you.
What’s c mean
That's an integration constant
Nice explanation bro
0:40 Isnt x away from the equilibrium position
Isn't it cos
you can use cos or use sine. Both works.
But isn't it cos??
I saw other videos but this one mad most sense to me
Wooooooooooooooowwwww❤❤❤❤❤❤🥰🥰🥰🥰🥰🥰🥰😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍😍📸📸😍😍📸📸😍😍 so beautiful it feels like im high or somthing
Thank you for this Protty. It was really helpful.
You're welcome Fatuma. I'm glad my videos reached you
Sir can you please make a video on derivation of wave motion. Plzz sir
Cool thank you!
Thanks dude <3
4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?
No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c
At 03:20, he mentioned about the chain rule. Which part is it? Why dv/dt = dv/dx*dx/dt? Can someone explain?
Part of chain rule the dx and dx cancel out and we get dv/dt
Thanks.
Thanks brother
Thanks a lot 😃
Amazing video!!!😍 I had a question in pendulum which I couldn't figure out🥺. How can I send it to you?😇
Hi! Email me at prottoymahdisamir@gmail.com
@@physixdaily6223 Thanks a lot for the assistance!!!! Just mailed u😁.
At last, somone who explains it... Thank u!!!
A song like this will definitely have international appeal. Just look at the comments.
This video is helpful 😀 thank sir
Thanks you sir in this concept is completed 😀 simple harmonic motion
A=amplitude X=Amplitude X=A Sqrt(A^2 - X^2) Sqrt(0)?????
Please to solve the problems 2.11,2.12
Thank you. I'll post the solutions of those then!
2.12 and 2.13 Ka solution
I'll post them too!
Thanks
Unbelievable.! You taught the topic very easily within a few minutes.
Well done sir. Thank you
Best video so far
Im amazed by this form, thanks a lot bro !
Please sir which software did you used to record your videos🙏
How ω² = k/m , can anyone explain
the w itself is root of k/m then k/m equals to the ω²
@@eymendediler5357but how do you derive w = k/m? is this purely definitional?
@@mailingbox F = mw^2x = kx
@@mailingboxIt is purely definitional.
To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m
It is best on you tube 🎉
I WANT TO KNOW THE LOGIC OF ? IS THIS A CONVENTION ? OR WE CAN PROVE IT BY TAKING INTO 2D
THNX FOR RESOLVING MY DOUBT
your channel need to make SEO
isnt it suppose to be Acos(wt+Ö)
If the particle starts from its mean position we take sine as position is 0 but when the particle in shm starts from its maximum displacement A then we say it as cos
@@suchitawasnik3633thanks
Iam realy doubt on adiabatic process bcz we all know that heat is flow from lower temperature to higher temprature that is heat depends on temprature diffrence. So at constant temprture the heat will become constant. But in the case of adiabatic process the heat is constant but temprature is not constant why? Plz... Reply
Hi, I know this is three months later, but hopefully this answers your question. Heat is not temperature. Heat is a form of energy, temperature is a measure of hotness in a body. they have different measurements, different parameters. Therefor heat and can increase/decrease without temperature increase or decrease. This is seen as we heat water. Water boils at 100C, so adding heat until boiling temperature increases the heat, but at phase changes, temperature DOES NOT CHANGE. This is known as latent heat, i.e. the heat required to change heat from one phase to another. This is because heat is required to break the bonds, and the heat is not used to increase the temperature. For this reason, temperature can change due to heat, but are not always dependant on one another. heat=mass*specific heat capacity*difference in temperature, which means you can add heat by increasing the amount of the substance you have, even if temperature of the bodies are the same. Don't let this formula confuse you, as latent heat has its own formula as latent heat=specific latent heat of (vaporisation or fusion)*mass. Maybe you have figured by now, that for this reason adiabatic processes and isothermal processes are not the same. Isothermal the temperature remains constant, adiabatic the heat of the system remains constant. That means isothermal processes can have phase changes, where heat is added or removed. Adiabatic processes can't have phase changes as heat cannot enter or exit the system therefor changing the phase. In short your statement "So at constant temperature the heat will become constant", is incorrect, as temperature and heat have different parameters, as they measure different quantities, and can change somewhat independently. I hope this answers your question!
why adiabatic is pv^r=k?
Please make a video about RLC AC circuit
Thank you so much for the suggestion. I myself struggled with this when I was learning electronics. I will for sure in the near future
Thanks 😘 my way back now
sin(sin^-1(x/A)) =/= x/A ??
It is
Sin*(Sin^-1) is Sin*(1/Sin) by considering basic maths , you will get the rest X/A .
How is this easier than adding? You teach well. Thank you.
Thank you sir!
These vdos are so good mann