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Adeyanju Mercy
Nigeria
Приєднався 9 січ 2024
Best and well explained tutorials on all chemistry, physics and mathematics related questions and topics. Also, preparations for exams such as: WASSCE, NECO, GCE, JAMB, and etc. Do well to subscribe to keep yourself alert.
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Special tutorial sessions are also available. Join our Telegram channel for communications.
t.me/adeyanju_mercy
or search for adeyanju_mercy on telegram.
Zn + H2SO4 → ZnSO4 + H2. In the above reaction, how much zinc will be left undissolved if 2.00g of..
Hello everyone, in this video, we'll be solving the question below;
Zn + H2SO4 → ZnSO4 + H2
In the above reaction, how much zinc will be left undissolved if 2.00g of zinc is treated with 10cm^3 of 1.0 M of H2SO4? [Zn = 65, S = 32, O = 16, H = 1]
moles, molarity, molarity and concentration, molarity problems, molality, molar, molar mass, find moles, molarity stoichiometry, grams to moles, molarity chemistry, molarity practice problems, moles to grams, mole & volume calculation, stoichiometry, stoichiometry problems, stoichiometry mole to mole, stoichiometry moles to grams, stoichiometry problem, mass-volume relationship, jamb chemistry, chemistry, jamb, jamb chemistry videos, jamb chemistry exam lessons, jamb past questions, jamb chemistry questions, score 300+ in jamb, likely chemistry questions.
telegram channel: t.me/adeyanju_mercy
Zn + H2SO4 → ZnSO4 + H2
In the above reaction, how much zinc will be left undissolved if 2.00g of zinc is treated with 10cm^3 of 1.0 M of H2SO4? [Zn = 65, S = 32, O = 16, H = 1]
moles, molarity, molarity and concentration, molarity problems, molality, molar, molar mass, find moles, molarity stoichiometry, grams to moles, molarity chemistry, molarity practice problems, moles to grams, mole & volume calculation, stoichiometry, stoichiometry problems, stoichiometry mole to mole, stoichiometry moles to grams, stoichiometry problem, mass-volume relationship, jamb chemistry, chemistry, jamb, jamb chemistry videos, jamb chemistry exam lessons, jamb past questions, jamb chemistry questions, score 300+ in jamb, likely chemistry questions.
telegram channel: t.me/adeyanju_mercy
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Відео
30cm^3 of 0.1M Al(NO3)3 solution is reacted with 100cm^3 of 0.15M of NaOH solution. Which reactant..
Переглядів 2Годину тому
Hello everyone, in this video, we'll be solving the question below; 30cm^3 of 0.1M Al(NO3)3 solution is reacted with 100cm^3 of 0.15M of NaOH solution. Which reactant is in excess, and by how much? moles, molarity, molarity and concentration, molarity problems, molality, molar, molar mass, find moles, molarity stoichiometry, grams to moles, molarity chemistry, molarity practice problems, moles ...
For the reaction NH4NO2 → N2 + 2H2O, calculate the volume of nitrogen that would be produced at...
Переглядів 21День тому
Hello everyone, in this video, we'll be solving the question below; For the reaction NH4NO2 → N2 2H2O, calculate the volume of nitrogen that would be produced at S. T. P from 3.20g of the dioxonitrate(iii)salt. (Relative atomic masses: N = 14, O = 16, H = 1) mole, volume, moles and volume of gas, relation between moles and volume of gas, mole concept and stoichiometry, mole to volume, volume to...
The ratio of the number of molecules in 2g of hydrogen to that in 16g of oxygen is ________
Переглядів 14День тому
Hello everyone, in this video, we'll be solving the question below; The ratio of the number of molecules in 2g of hydrogen to that in 16g of oxygen is . number of molecules, molecules, how to calculate the number of molecules, find the number of molecules, how to calculate the number of molecules in a mole, jamb chemistry, chemistry, jamb, jamb chemistry videos, jamb chemistry exam lessons, jam...
manganese(IV)oxide reacts with concentrated hydrochloric acid according to the equation MnO2 + xHCl.
Переглядів 24День тому
Hello everyone, in this video, we'll be solving the question below; manganese(IV)oxide reacts with concentrated hydrochloric acid according to the equation MnO2 xHCl = MnCl2 Cl2 yH2O. X and Y are . balancing chemical equations, balancing equations, how to balance chemical equations, chemical equations, chemical equation, balancing chemical equations for beginners, balancing chemical reactions, ...
The balanced equation for the reaction of tetraoxosulphate(VI)acid with aluminium hydroxide...
Переглядів 23День тому
Hello everyone, in this video, we'll be solving the question below; The balanced equation for the reaction of tetraoxosulphate(VI)acid with aluminium hydroxide to give water and aluminium tetraoxosulphate(VI) is . balancing chemical equations, balancing equations, how to balance chemical equations, chemical equations, chemical equation, balancing chemical equations for beginners, balancing chem...
Pure sulphuric acid is a liquid of 1.84 density. What volume of it would be required to prepare...
Переглядів 257 місяців тому
Hello everyone, in this video, we'll be solving the question below; Pure sulphuric acid is a liquid of 1.84 density. What volume of it would be required to prepare 250cm^3 of 0.2M solution? (H = 1, S = 32, O = 16) telegram channel: t.me/adeyanju_mercy density, volume, how to find density, density and volume, density mass and volume, density formula, how to calculate density, stoichiometry, stoi...
Na2CO3 + 2HCl = 2NaCl + H2O + CO2. Using this equation, what volume of carbon dioxide, measured at..
Переглядів 1567 місяців тому
Hello everyone, in this video, we'll be solving the question below; Na2CO3 2HCl = 2NaCl H2O CO2. Using this equation, what volume of carbon dioxide, measured at s.t.p is liberated when 53g of sodium carbonate is dissolved in hydrochloric acid? (1 mole of gas occupies 22.4dm^3 at s.t.p.) (Na = 23, C = 12, O = 16) telegram channel: t.me/adeyanju_mercy molar gas volume, mole & volume calculation, ...
How many grams of hydrogen gas will be liberated when 6g of magnesium ribbon dissolves in 500cm^3...
Переглядів 557 місяців тому
Hello everyone, in this video, we'll be solving the question below; How many grams of hydrogen gas will be liberated when 6g of magnesium ribbon dissolves in 500cm^3 of 6M HCl? (Mg = 24, H = 1, Cl = 35.5) telegram channel: t.me/adeyanju_mercy molar gas volume, mole & volume calculation, stoichiometry, stoichiometry problems, stoichiometry mole to mole, stoichiometry moles to grams, stoichiometr...
If 1 litre of 2.2M sulphuric acid is poured into a bucket containing 10 litres of water, and the...
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Hello everyone, in this video, we'll be solving the question below; If 1 litre of 2.2M sulphuric acid is poured into a bucket containing 10 litres of water, and the resulting solution mixed thoroughly, the resulting sulphuric acid concentration will be telegram channel: t.me/adeyanju_mercy dilution, dilutions, dilution ratio, dilution problems, solution, dilution examples, dilution and concentr...
On heating, under suitable conditions, 1 litre of a monoatomic gas X combines with 1.5 litres of...
Переглядів 217 місяців тому
Hello everyone, in this video, we'll be solving the question below; On heating, under suitable conditions, 1 litre of a monoatomic gas X combines with 1.5 litres of oxygen to form an oxide. What is the formula of the oxide? telegram channel: t.me/adeyanju_mercy molecular formula, empirical formula, molecular formula and empirical formula, molecular formulas, molecular formula problems, molecula...
10cm^3 of CO is mixed and sparked with 100cm^3 of air containing 21% of O2. If all volumes are...
Переглядів 1307 місяців тому
Hello everyone, in this video, we'll be solving the question below; 10cm^3 of CO is mixed and sparked with 100cm^3 of air containing 21% of O2. If all volumes are measured at S.T.P. the volume of resulting gases would be telegram channel: t.me/adeyanju_mercy gas laws, gas laws chemistry, gas laws chemistry problems, gas law, jamb chemistry, chemistry video, gas volume calculation, gay-lussac's ...
Phosphorus burns in oxygen according to the equation P4 + 5O2 = P4O10 How many litres of oxygen...
Переглядів 777 місяців тому
Hello everyone, in this video, we'll be solving the question below; Phosphorus burns in oxygen according to the equation P4 5O2 = P4O10. How many litres of oxygen will be required at S.T.P. for complete oxidation of 12.4g of phosphrus? (P = 31, O = 16 and molar volume of a gas at S.T.P. = 22.4 litres) mole, volume, moles and volume of gas, relation between moles and volume of gas, mole concept ...
The oxidation state of manganese in potassium permanganate is
Переглядів 157 місяців тому
Hello everyone, in this video, we'll be solving the question below; The oxidation state of manganese in potassium permanganate is oxidation state, oxidation, oxidation number, oxidation states, oxidation numbers, oxidation number rules, how to calculate oxidation state, oxidation state chemistry, oxidation state for 12 class, oxidation no. oxidation state, oxidation and reduction reactions, oxi...
The oxidation state of chlorine in potassium chlorate is
Переглядів 287 місяців тому
Hello everyone, in this video, we'll be solving the question below; The oxidation state of chlorine in potassium chlorate is oxidation state, oxidation, oxidation number, oxidation states, oxidation numbers, oxidation number rules, how to calculate oxidation state, oxidation state chemistry, oxidation state for 12 class, oxidation no. oxidation state, oxidation and reduction reactions, oxidatio...
0.07g of a hydride of carbon occupies 56cm^3 at S.T.P. when vapourized and contains 14.29% by mass..
Переглядів 427 місяців тому
0.07g of a hydride of carbon occupies 56cm^3 at S.T.P. when vapourized and contains 14.29% by mass..
The empirical formula of an oxide of nitrogen containing 30.4 percent of nitrogen is ...
Переглядів 1788 місяців тому
The empirical formula of an oxide of nitrogen containing 30.4 percent of nitrogen is ...
How many grams of HBr would exactly be required to react with 2g of propyne?(C = 12, H = 1, Br = 80)
Переглядів 538 місяців тому
How many grams of HBr would exactly be required to react with 2g of propyne?(C = 12, H = 1, Br = 80)
50cm^3 of hydrogen are sparked with 20cm^3 of oxygen at 100C and 1 atmosphere. The total volume...
Переглядів 1468 місяців тому
50cm^3 of hydrogen are sparked with 20cm^3 of oxygen at 100C and 1 atmosphere. The total volume...
The molarity of a 2% by weight of aqueous solution of H2SO4 (molecular weight = 98) is
Переглядів 888 місяців тому
The molarity of a 2% by weight of aqueous solution of H2SO4 (molecular weight = 98) is
The empirical formula of a compound is C5H7N. If its relative molecular mass is 162, what is its...
Переглядів 368 місяців тому
The empirical formula of a compound is C5H7N. If its relative molecular mass is 162, what is its...
Calculate the molecular formula of a compound with empirical formula CH2O and relative molecular...
Переглядів 1258 місяців тому
Calculate the molecular formula of a compound with empirical formula CH2O and relative molecular...
An hydrocarbon has an empirical formula CH and a vapour density of 39. Determine its molecular...
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An hydrocarbon has an empirical formula CH and a vapour density of 39. Determine its molecular...
An organic compound contains 60% carbon, 13.3% hydrogen, 26.7% oxygen. Calculate the empirical ...
Переглядів 1448 місяців тому
An organic compound contains 60% carbon, 13.3% hydrogen, 26.7% oxygen. Calculate the empirical ...
An organic compound has an empirical formula CH2O and vapour density of 45. What is its molecular...
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An organic compound has an empirical formula CH2O and vapour density of 45. What is its molecular...
A hydrocarbon X with a molar mass 26 consists of 92 3% carbon What is its molecular formula
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A hydrocarbon X with a molar mass 26 consists of 92 3% carbon What is its molecular formula
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound
Переглядів 3869 місяців тому
A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound
A compound contains 31.91% potassium, 28.93% chlorine and the rest oxygen. What is the chemical...
Переглядів 989 місяців тому
A compound contains 31.91% potassium, 28.93% chlorine and the rest oxygen. What is the chemical...
A gaseous metallic chloride MCl consists of 20.22% of M by mass. The formula of the chloride is
Переглядів 239 місяців тому
A gaseous metallic chloride MCl consists of 20.22% of M by mass. The formula of the chloride is
An organic compound containing 40.1% carbon and 6.67% hydrogen has an empirical formula of...
Переглядів 339 місяців тому
An organic compound containing 40.1% carbon and 6.67% hydrogen has an empirical formula of...
Thanks a lot❤ You made this really easy to understand Sending lots of hugs and 💕😘 God bless you 🙏
You're welcome I'm glad you find it helpful
I don't understand how u got 4
4 is gotten from the ratio in which both hydrogen and oxygen ( that is, a ratio of 2:1). According to the question solved above, x is the unknown and it is also being made the subject (by taking the ratio sign to be an equal sign and cross multiplying indirectly as said in the explanation)
Thanks
You're welcome
Thanks a lot 😊
You're welcome
Thank you
You're welcome
thank yu
You're welcome
If the symbol for mass conc. Is g/dm³ but in the question it's only grams Does that mean it's the same??
It depends on the information given in the question asked
Thanks 👍
You're welcome
Thanks for the explanation
You're welcome
😊
You didn't convert the 0.11g to kg in the solution which gives us 110kg but it's still gives the same answer as well
There is no need for conversion since other values we worked with are in cm^3 (the volume of the gas and molar volume of a gas). Also, I'll like you to note that converting 0.11g to kg won't give 110kg. 0.11g = 0.00011kg. For the solution in the video above, all values are in their expected unit for easier calculations.
Thankyou for explaining it in such an easy way,I'm truly grateful 😊
My pleasure 😊
Thanks❤
You're welcome
This has really helped me out, exact question Thank you so much ❤
I'm glad it helped, do well to subscribe if you haven't subscribed
Very helpful. Thanks 🙏😊
Glad it was helpful!
I totally get it now
Good
Rate of diffusion? More like "Really good knowledge infusion!" 👍
Thank you 😊
You're welcome 😊
Amazing explanation ❤❤❤
Thanks a lot 😊
This video was so helpful. I understood immediately. Thanks so much
Glad it was helpful!
Thank you
You're welcome
Pls l don't understand
do you watch the video through? because it's well explained. Perhaps it's a part you don't understand, please say.
Thank you very much!
You're welcome!
Thanks ma'am But in some context i.e calculation in chemistry by ewelukwa. The formula for calculating residual gas= volume of unreacted gas +volume of the product. Why is it not related here
You're welcome. Yes, you're right with the formula for calculating residual gas that you stated, but there could be an exception to that depending on the nature of the question just as in the one above. In the question above, we're made to understand that the resulting mixture was passed over calcium chloride which is a drying agent. This implies that the product is being dried up, making it not to be part of the residual gases. We are then left with the hydrogen and oxygen gases ( the reactants). For the reactants, hydrogen gas is the limiting reagent (gas being used up), while oxygen gas is the one in excess. Thus, making oxygen gas the residual gas because it is not used up in the reaction, which is gotten to be 10cm^3 from the solution in the video above. Summarily, based on the formula YOU presented (The formula for calculating residual gas= volume of unreacted gas +volume of the product), the volume of the product will automatically be ZERO because it is being dried up, so we're left with the volume of the unreacted gas only. I hope you find this useful, thanks.
Thank u so much Your channel will grow...#AMEN
Thank you too
Thank love
It's my pleasure
Keep up the good work
Thanks
Thank you very much for this detailed explanation
Glad it was helpful!
You are welcome!
Nice... just what I needed❤
Glad it could help
Where did you get 13g
13g is gotten from the mass of the empirical formula of the compound CH, which can also be referred to as the empirical formula mass. CH = 12 + 1 = 13g [Atomic mass of C=12, H=1]