ILIEKMATHPHYSICS
ILIEKMATHPHYSICS
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Prove that sin2x - sin2y = 2sin(x-y)cos(x+y) and cos2x - cos2y = -2sin(x-y)sin(x+y)
This video is part of the “Real Analysis” series I am making.
Thanks and enjoy the video!
Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html
Proof that cosine is even and sine is odd video: ua-cam.com/video/Zea-Yf3FVbk/v-deo.html
Prove the sine and cosine addition formulas video: ua-cam.com/video/tOAmJkv3YWE/v-deo.html
Переглядів: 34

Відео

Prove that |sin x| ≤ |x| (ILIEKMATHPHYSICS)
Переглядів 40220 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that 2^n xn converges (definition of arctan) video: ua-cam.com/video/41mHRdnpp7o/v-deo.html Prove if x ﹥ 0, then x/sqrt(1 x^2) ﹤ arctan(x) video: ua-cam.com/video/seEyryvLOJk/v-deo.html Prove that |arctan x| = arctan|x| v...
Prove that cos(2arctanx) = 1-x^2 / 1+x^2 and sin(2arctanx) = 2x / 1+x^2 (ILIEKMATHPHYSICS)
Переглядів 1292 години тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that 2^n xn converges (definition of arctan) video: ua-cam.com/video/41mHRdnpp7o/v-deo.html Prove that e^2iarctanx = 1 ix / 1-ix video: ua-cam.com/video/9vzCYkw_oFs/v-deo.html Prove that cos(x) = Re(e^ix) and sin(x) = Im(...
Prove that |sin x| ≤ 1 and |cos x| ≤ 1 (ILIEKMATHPHYSICS)
Переглядів 1,1 тис.2 години тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that cos(x) = Re(e^ix) and sin(x) = Im(e^ix) video:
Prove that sin^2(z) + cos^2(z) = 1 (ILIEKMATHPHYSICS)
Переглядів 2644 години тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Proof that cosine is even and sine is odd video: ua-cam.com/video/Zea-Yf3FVbk/v-deo.html Prove the sine and cosine addition formulas video: ua-cam.com/video/tOAmJkv3YWE/v-deo.html
Prove the sine and cosine addition formulas for complex numbers (ILIEKMATHPHYSICS)
Переглядів 3444 години тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Proof of Euler's Formula video: ua-cam.com/video/m_LyzngvLpE/v-deo.html Proof that cosine is even and sine is odd video: ua-cam.com/video/Zea-Yf3FVbk/v-deo.html
Prove that cos(-z) = cos(z) and sin(-z) = -sin(z) (ILIEKMATHPHYSICS) (cos is even and sine is odd)
Переглядів 5147 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html
Prove Euler's Formula e^iz = cos(z) + isin(z) (ILIEKMATHPHYSICS)
Переглядів 5227 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html
Prove that cos(x) = Re(e^ix) and sin(x) = Im(e^ix) (ILIEKMATHPHYSICS)
Переглядів 4239 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html
Prove that the conjugate of e^z is equal to e^conjugate of z (ILIEKMATHPHYSICS)
Переглядів 4769 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html
Prove if zn converges to z, then zn conjugate converges to z conjugate (ILIEKMATHPHYSICS)
Переглядів 18812 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Proof of basic properties of complex numbers (includes properties of complex conjugate): ua-cam.com/video/6GA2UoULyiM/v-deo.html
Prove that arctan(1) = π/4 (ILIEKMATHPHYSICS) (Real Analysis)
Переглядів 84312 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that 2^n xn converges (definition of arctan) video: ua-cam.com/video/41mHRdnpp7o/v-deo.html Proof of xy ﹤ 1 arctan addition formula video: ua-cam.com/video/vQtV3aBX26E/v-deo.html Prove that arctan is increasing video: ua-...
Prove that arctan : R → (-π/2, π/2) is onto (ILIEKMATHPHYSICS) (definition of tan(x))
Переглядів 31114 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that 2^n xn converges (definition of arctan) video: ua-cam.com/video/41mHRdnpp7o/v-deo.html Prove that arctan is increasing video: ua-cam.com/video/tC28dwXQBDA/v-deo.html Prove that arctan is continuous video: ua-cam.com/...
Prove that lim{x→∞} arctan(x) = π/2 and lim{x→-∞} arctan(x) = -π/2 (ILIEKMATHPHYSICS)
Переглядів 39316 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Preliminary results are in the following videos: Prove that 2^n xn converges video (introduces arctan): ua-cam.com/video/41mHRdnpp7o/v-deo.html Prove that arctan is strictly increasing video: ua-cam.com/video/tC28dwXQBDA/v-deo....
Prove that arctan(x) is bounded (ILIEKMATHPHYSICS) (includes a definition of pi)
Переглядів 30819 годин тому
This video is part of the “Real Analysis” series I am making. Thanks and enjoy the video! Real Analysis Playlist: ua-cam.com/play/PLDiddIbnOEOWLbdQ4DoC8bfaV_y4VyOsS.html Prove that 2^n rn converges video: ua-cam.com/video/41mHRdnpp7o/v-deo.html Prove arctan is an odd function video: ua-cam.com/video/j1Hx8D_xg1Y/v-deo.html Proof if x ﹥ 0, then x/sqrt(1 x^2) ﹤ arctan(x) ﹤ x video (contains the ot...
Prove that arctan(x) is continuous (ILIEKMATHPHYSICS)
Переглядів 47321 годину тому
Prove that arctan(x) is continuous (ILIEKMATHPHYSICS)
arctan(x) is an increasing function (Proof) (ILIEKMATHPHYSICS)
Переглядів 483День тому
arctan(x) is an increasing function (Proof) (ILIEKMATHPHYSICS)
If xy ﹤ 1, then arctan(x) + arctan(y) = arctan((x+y)/(1-xy)) (Proof) (ILIEKMATHPHYSICS)
Переглядів 338День тому
If xy ﹤ 1, then arctan(x) arctan(y) = arctan((x y)/(1-xy)) (Proof) (ILIEKMATHPHYSICS)
If x ﹥ 0, then x/sqrt(1+x^2) ﹤ arctan(x) ﹤ x Proof (and other properties) (ILIEKMATHPHYSICS)
Переглядів 558День тому
If x ﹥ 0, then x/sqrt(1 x^2) ﹤ arctan(x) ﹤ x Proof (and other properties) (ILIEKMATHPHYSICS)
Prove that arctan is an odd function, arctan(-x) = -arctan(x) for all real x (ILIEKMATHPHYSICS)
Переглядів 221День тому
Prove that arctan is an odd function, arctan(-x) = -arctan(x) for all real x (ILIEKMATHPHYSICS)
Prove that lim_{x→c} x^n = c^n using epsilon-delta (ILIEKMATHPHYSICS)
Переглядів 520День тому
Prove that lim_{x→c} x^n = c^n using epsilon-delta (ILIEKMATHPHYSICS)
Prove that e^x is continuous (Second Proof) (ILIEKMATHPHYSICS)
Переглядів 44114 днів тому
Prove that e^x is continuous (Second Proof) (ILIEKMATHPHYSICS)
Prove that e^z maps onto the nonzero complex numbers (ILIEKMATHPHYSICS)
Переглядів 57614 днів тому
Prove that e^z maps onto the nonzero complex numbers (ILIEKMATHPHYSICS)
Prove that e^2iarctan(x) = (1 + ix)/(1 - ix) (ILIEKMATHPHYSICS)
Переглядів 22214 днів тому
Prove that e^2iarctan(x) = (1 ix)/(1 - ix) (ILIEKMATHPHYSICS)
If |a + bi| = 1 and a ≠ -1, then a + bi = (1 + iy)/(1 - iy) where y = b/(1 + a) (Proof)
Переглядів 55014 днів тому
If |a bi| = 1 and a ≠ -1, then a bi = (1 iy)/(1 - iy) where y = b/(1 a) (Proof)
Prove if lim(zn) = z, then lim(1 + zn/2^n)^2^n = e^z (ILIEKMATHPHYSICS)
Переглядів 20714 днів тому
Prove if lim(zn) = z, then lim(1 zn/2^n)^2^n = e^z (ILIEKMATHPHYSICS)
Prove that lim(2^n xn) converges where x0 = x, xn+1 = xn / (1 + sqrt(1 + xn^2)) definition of arctan
Переглядів 45614 днів тому
Prove that lim(2^n xn) converges where x0 = x, xn 1 = xn / (1 sqrt(1 xn^2)) definition of arctan
Prove lim(xn) = 0 for the sequence x0 = x, xn+1 = xn / (1 + sqrt(1+xn^2)) (ILIEKMATHPHYSICS)
Переглядів 47014 днів тому
Prove lim(xn) = 0 for the sequence x0 = x, xn 1 = xn / (1 sqrt(1 xn^2)) (ILIEKMATHPHYSICS)
Prove that e^x maps onto the positive real numbers (ILIEKMATHPHYSICS)
Переглядів 64214 днів тому
Prove that e^x maps onto the positive real numbers (ILIEKMATHPHYSICS)
Prove that e^x is continuous (First Proof) (ILIEKMATHPHYSICS)
Переглядів 2,4 тис.14 днів тому
Prove that e^x is continuous (First Proof) (ILIEKMATHPHYSICS)

КОМЕНТАРІ

  • @mstarsup
    @mstarsup 37 хвилин тому

    nice proof, but why make it so overly complicated? just define f(x)=|x|-|sin(x)| and analyse that function... if |x|>=1, it's clear that f(x)>=0, so we'll restrict the analysis for |x|<1 (actually it's not strictly necessary, as we can easily show that f is increasing on R+, but for simplicity's sake i'll just write it like this). f is even (so you only need to check f(x)>=0 for x>=0), and for 0<=x<=1, f is differentiable and f'(x)=1-cos(x)>=0, so f is increasing on [0,1], and since f(0)=0, f(x)>=0 for x in [0,1] (and thus for all x in [-1,1] since f is even, and then on R since f(x)>=0 in R\(-1,1)).

  • @tsunningwah3471
    @tsunningwah3471 58 хвилин тому

    weird background noise.

  • @frog-d9w
    @frog-d9w Годину тому

    easier proof:both abs(sinx) and abs(x) are symmetric about the y axis, so we only have to look at x>=0. The derivative of sinx is cosx, and the derivative of x is just 1, and since cosx has a maximum value of 1 when x=2npi, and abs(sin0)=0, we can say that abs(sinx) won't exceed abs(x).

  • @erfanmohagheghian707
    @erfanmohagheghian707 2 години тому

    I'm still looking forward to the derivation of arctan :) Thank you.

  • @mismis3153
    @mismis3153 2 години тому

    Since the function is mirrored, we can just prove it for 0 < x < pi/2. Then we can probably use the taylor expansion to show that sin(x) is always less or equal to x on that interval. (fundamental theorem of engineering works too)

  • @JoFo_music
    @JoFo_music 6 годин тому

    Bro just draw out a triangle and it pops right out

  • @Maykon2022
    @Maykon2022 9 годин тому

    It's a great video, I don't have the basics to fully understand the video yet. But, I really liked how you proved it using the definitions.

  • @samdaman2510
    @samdaman2510 10 годин тому

    Why can’t you just use the unit circle and why is there an absolute value. I feel like I am misreading the question or something

    • @garfungled7093
      @garfungled7093 5 годин тому

      real analysis is a lot more rigorous than that

  • @jackorton2707
    @jackorton2707 11 годин тому

    Why not just use calculus? It would be much easier

  • @devotion7890
    @devotion7890 11 годин тому

    I think someone can learn a lot from these proofs, but when it comes to memorizing proofs for various sentences and then reconstructing them from memory, “shorter” proofs that don't go into so much detail would be easier. Perhaps something along these lines could be introduced in the future, that would be great :)

  • @leif1075
    @leif1075 12 годин тому

    Why is arctan involved at all ? Why not just use eulers identity e^ix and be done? Thanks for sharing

  • @kennethluo4934
    @kennethluo4934 День тому

    I am a first year so this may be an elementary question. Is this actually the most fundamental way to prove this result?

    • @iliekmathphysics
      @iliekmathphysics 18 годин тому

      it really is nothing but |sin x| = sqrt(sin^2(x)) <= sqrt(sin^2(x) + cos^2(x)) = sqrt(1) = 1 and similarly for cos(x). This way might be more fundamental. But interestingly, this proof is also modeled the same way as the proof of |Re(z)| <= |z| and similarly for |Im(z)| <= |z|.

  • @pratheesh.
    @pratheesh. День тому

    Wow. Bro really is speed running analysis.

  • @malik-h2e
    @malik-h2e День тому

    Great

  • @maitripatel7466
    @maitripatel7466 День тому

    Great video! Keep up the good work

  • @chaosredefined3834
    @chaosredefined3834 2 дні тому

    I'm still waiting to see how you tie this to triangles :)

  • @mtaur4113
    @mtaur4113 2 дні тому

    If you only need proof for the case z and w are real, then writing e^(i(z+w)) = (e^(iz) e^(iw)) and collecting like terms proves both formulas all-in-one. I'm not sure if there's a way to formalize "collect like terms" so that the shortcut still functions a rigorous proof. In any case, if one takes for granted that the identities exist but forgets what they are, the two-for-one will spit out the correct answers by simple follow-your-nose computation.

    • @bennetdiesperger4080
      @bennetdiesperger4080 День тому

      I think aplying Re(...) or Im(...) to both sides is the way to formalize "collecting like terms". This works since two complex numbers α and β are equal if and only if Re(α)=Re(β) and Im(α)=Im(β). For this to work you would also have to prove that sin(x) and cos(x) are always real so long as x is real though, which would require another step.

    • @mtaur4113
      @mtaur4113 День тому

      @bennetdiesperger4080 But the identities we want to prove are still true for z and w complex. That's where I don't see how to make the proof automatically work, neither of the two identities is strictly real or imaginary anymore, even though "there is an i in front of sin" via the proof method. Somehow the identity for real z,w has to continue through the complex plane.

  • @m_c_8656
    @m_c_8656 2 дні тому

    You good dawg!

  • @Marcus-y1m
    @Marcus-y1m 2 дні тому

    Amazing explanation ! Thank you so much

  • @goncalofreitas2094
    @goncalofreitas2094 2 дні тому

    I like it! Unexpected

  • @ait528
    @ait528 2 дні тому

    I feel like the property at 2:42 is derived from this exact equality, so doesn't that mean its proving itself, and hence not really a proof? I can solve x^2 = 25 by "recalling" 25 is the square of 5, that doesn't make that a proof does it? A beautiful proof if this exact problem is using the taylor expansion of e^x, and substituting (ix) for x, and seeing that the real part is equal to the taylor series for cos(x) and the imaginary part the taylor series of sin(x).

  • @euloge996
    @euloge996 2 дні тому

    uuuuuuuuum actually the first thing you wrote in red is false, the first thing is a number while the secon is a function

  • @justyours8766
    @justyours8766 3 дні тому

    Who let this third grader on UA-cam and make math videos? Bro this is a circular argument....

  • @lorenzosaudito
    @lorenzosaudito 3 дні тому

    I knew you were gonna make a video about this property ! 😂

  • @erfanmohagheghian707
    @erfanmohagheghian707 3 дні тому

    I'm interested to see a proof or derivation for the limit definition of arctan(x) using that sequence you noted. Do you have any reference to share by chance? Thank you. P.S. I could never imagine it would take 16 minutes to peove that tan of 45 deg is 1 lol.

  • @oraz.
    @oraz. 3 дні тому

    Nice and quick one

  • @Reptar0RAWR0
    @Reptar0RAWR0 3 дні тому

    can you prove sin(x) = x and cos(x) = 1 for small x

    • @AntoshaPushkin
      @AntoshaPushkin 2 дні тому

      It's the fundamental theorem of engineering

  • @afesfrytuykjhyj
    @afesfrytuykjhyj 3 дні тому

    I'm pretty sure the definitions of cos z and sin z are based on the identity and this is just circular reasoning hence not being a valid proof. A taylor series proof is a much better way to prove this.

  • @Rifat_Here
    @Rifat_Here 3 дні тому

    Great

  • @biscuit_6081
    @biscuit_6081 3 дні тому

    Bro proved nothing 😭

    • @saj_f0
      @saj_f0 3 дні тому

      It is true for all real numbers but you need to prove it for Complex numbers.

    • @chaosredefined3834
      @chaosredefined3834 3 дні тому

      @@saj_f0 Nah, this proof is valid for all complex numbers. The problem is, he began with a definition that gets us to the outcome pretty quickly.

  • @Keithfert490
    @Keithfert490 4 дні тому

    Are there any non-over-the-top cases where we can show there exists a bijection between two sets but can't construct it?

  • @lorenzosaudito
    @lorenzosaudito 4 дні тому

    I'm curious to see if we will get to prove that cos and sin are related to pi (the one defined from circles and not the one defined in the previous videos, even if of course they are the same) !

    • @frog-d9w
      @frog-d9w 3 дні тому

      it's just a unit thing, cuz we use radians for angles, and 2pi radians is a full revolution.

    • @lorenzosaudito
      @lorenzosaudito 3 дні тому

      @frog-d9w yeah but the pi in radians is the same pi we use to get the perimeter of a circle

  • @salmandajani8536
    @salmandajani8536 4 дні тому

    First

  • @edcoad4930
    @edcoad4930 5 днів тому

    What is the process by which delta is suddenly set to be x^2+1/ xo-x??

    • @edwardjames625
      @edwardjames625 5 днів тому

      In the proof, the delta is a choice you make (that can have some dependency on epsilon). Since x is fixed and the x_0 is fixed but depends on the epsilon, you can choose to set the delta to whatever combination of these value that you wish.

    • @edcoad4930
      @edcoad4930 5 днів тому

      @@edwardjames625 sure....but why? seems an awfully specific format. Why not x^3+x^2-1/xo - ln(x)??

    • @Mathguy1729
      @Mathguy1729 5 днів тому

      Assume that the theorem is true, solve for delta, then do everything in reverse. Of course you will only show the part that you do things in reverse.

    • @edcoad4930
      @edcoad4930 4 дні тому

      @Mathguy1729 which is why I am always uncomfortable with these proofs. Solve and work backwards. Seems that the epsilon/delta is the biggest con trick in mathematics.

    • @edwardjames625
      @edwardjames625 4 дні тому

      @edcoad4930 it's not very intuitive at first as to why it makes sense but it's not a con.... I remember it being illustrated as a game between two students when I was in uni. Since the proof goes "for any epsilon, there exists a delta..." the first student picks any epsilon they want. And they challenge the second student find a delta that works. And they go back a forth this way. Every time the first student states an epsilon the second student is tasked with finding a delta. If the second student can always do that, they win and the limit is proven. In reality, you can't check all infinitely many epsilon for a delta that works so you have to come up with a formula in the end that calculates what the delta is each time an epsilon is stated. That is why the proof goes "fix any epsilon > 0, choose delta = [formula he figured out]...."

  • @devotion7890
    @devotion7890 5 днів тому

    or you ask yourself the question: For which x is tan(x) = 1 and if you are a little familiar with trigonometry, you know that tan(Pi/4) = 1 and you are done in a few seconds ;-)

    • @t.b.4923
      @t.b.4923 5 днів тому

      very nice proof

    • @chaosredefined3834
      @chaosredefined3834 5 днів тому

      Except that he has defined arctan(x) in a different way, and hasn't shown that the inverse function has anything to do with triangles yet.

    • @Rikri
      @Rikri 5 днів тому

      the point of these exercises is to derive results in ways that teach us something or illustrate a tool; obviously arctan(1)=pi/4, in the same way that many results from analysis seem "trivial" but are insightful to try and prove using several differing methods

  • @edcoad4930
    @edcoad4930 5 днів тому

    These proofs always do my head in. I was thinking what is it in this proof that means you can't apply the same logic to sin(x) limit doesn't exist by saying epsilon = 2 and setting x = k.pi or even setting epsilon = 1? By eliminating the "one over" everywhere gets the same....or is it the archimedian step that is actually key. Sometimes these videos need (possibly) stupid examples to show the value of these proofs.

  • @gmcenroe
    @gmcenroe 5 днів тому

    I could have saved you a lot of time by simply showing that the sequence 8,9,10 is a consecutive sequence of positive integers that are not prime numbers.

  • @Keithfert490
    @Keithfert490 5 днів тому

    I look forward to these videos every day

    • @lorenzosaudito
      @lorenzosaudito 5 днів тому

      Same, since he started with this series which gradually builds up a lot of properties of the usual functions, these videos have became super interesting !

  • @GreenMeansGOF
    @GreenMeansGOF 6 днів тому

    My immediate instinct was to integrate the derivatives and immediately prove it. If t > 0, 1/(1+t^2)^(3/2) < 1/(1+t^2) < 1 and integrate from 0 to x.

  • @kennethvalbjoern
    @kennethvalbjoern 6 днів тому

    You shouldn't speed up parts of your videos. People need time to think, while they are watching. Otherwise great stuff you are producing!

  • @granth6542
    @granth6542 6 днів тому

    make a vid on why that sequence converges to arctan 😂 i love these vids btw!!

  • @goncalofreitas2094
    @goncalofreitas2094 6 днів тому

    Such a nice proof!

  • @Keithfert490
    @Keithfert490 6 днів тому

    I'm hooked to this series. Thank you for the effort of putting together these videos!

  • @razvanprodan1842
    @razvanprodan1842 6 днів тому

    I appreciate this series of real analysis and your channel overall because it gives me another perspective in math. Did u learn this things in college or u read about them for yourself? I am curious because i didnt saw arctan as a limi before.

  • @carloshernandez8150
    @carloshernandez8150 7 днів тому

    great video. i just finished a calc class with infinite series (not sure if commonly referred to as calc 2 or 3) and was super grateful for the development of the ratio test thanks for taking your time to go back and explain what’s going on! it’s super helpful looking forward to seeing more vids!

  • @yousefidris1195
    @yousefidris1195 7 днів тому

    Keep up the great work

  • @rebbecawitt581
    @rebbecawitt581 7 днів тому

    THIS VID REALLY HELPED TY!!

  • @Niloctronic
    @Niloctronic 7 днів тому

    For 2 seconds I thought you would forget the second therefore conclusion hehe! Great video, thanks!

  • @aRealAndHumanManThing
    @aRealAndHumanManThing 7 днів тому

    The yt algorithm hid this from me bc i used x and y in the search prompt. Just pieced it together from your earlier proofs before finding this, but I'm glad I had to do it since this channel is exactly how I need it explained. Not too long, but with all necessary info for formal proofs

  • @aRealAndHumanManThing
    @aRealAndHumanManThing 7 днів тому

    Really helps catching up on early uni math, thx :)