Відео

Can this be done by implicit differentiation?

Tq sir ❤...

Subscribed to your channel and like 👍 your explanation to sir.. tq sir ❤ love you Teacher.

Sir tangent slope finding question please

Love you sir ❤ thanks a lot...

Thanks for the video 😊

Tabular method?

I memories that sin^2 equals to 1/2(1-cox2x) and just do it from there

Very useful tutorial.Thank you

thanks bro

Chain rule

Easy, it's x.x^(x-1), done.

Isn't it ILATE instead of LIATE

I never use this method. I use the D-I method. Much, much easier. And much easier to learn.

We can use the limit definition to...

J=-ln(cosx)+k

To simplify one can for final answer: 1/xln(lnx^2)

Sir! Please, explain once and for all the difference between logx and lnx. I get so many confused pieces of information and even on YT you see mathematicians saying that logx is 1/x. Also, I hear the word e for exponential in some videos where I try to explain that e is a number which can be used as a base for a logarithm but by itself it is not any exponential (or is it?) and it's called Euler's number. Thank you.

Great

Very nice, I've learned something new! Thank You!

The easiest way is to just use the definition of tanx as the ratio of sine to cosine. U-sub cosine and then that gives du=-sinxdx. Then you get -ln|cosx| or ln|secx|+C.

Not the simplified form, but you can pull out the factor of 4 as 199(4)(x+1)(2x^2+4x-3)^198=796(x+1)(2x^2+4x-3).

The third method is multiply sec(x)/sec(x). The integral should be sec(x)tan(x)/sec(x)dx. If you let u=sec(x) and du=sec(x)tan(x), the integral is du/u. The answer to this integral is ln(|u|)+C=ln(|sec(x)|)+C. If you want in terms of cos(x), then the answer is -ln(|cos(x)|)+C.

ur so underated omg

Help me in his question Cos^3xdx by using integration by party

J=xlnx-x+k

dy/dx=(lnx+1)x^x

I didn't know we could solve it using the chain rule . Thanks , pal !

I’ve always used product rule here but this is awesome!

Nice!!!😉

You say Laun, I say Alan.

Wow

A third way: Multiply by secx/secx then let u=secx...

very nice video! thanks for sharing

One more way is integration by parts

ln ❌️ lawn ✅️

Tanx for uploading video😁

Damn daniel did you really think that I am going to click to your video just because of that cat png?

What is the diference between d/dx and dy/dx?

This video is great it was explained so well tysm

You are making circular reasoning. Aren't you? When you calculate the derivative of ln(x) you use the derivative of the exponencial función and viceversa. I mean, in another video,when you calculate the derivative of the exponencial función you use the derivative of the logarithmic función.

If you use this method with: y = log,a,(x) You also get 1/x but thats wrong

Awesome, these are two fundamental methods everyone should know about Now differentiate x^^3 = x^(x^x) B)

Can you make a video on series and sequences , i want to learn about that

I can't believe how could someone like you have so less subscribers you helped me a lot in calculus

If u try to differentiate a^x by definition, you will encounter a limit expression which is not related to x. You differentiate it with respect to a and you will get 1/a

Ln sec = ln 1- ln cos=-ln cos

Not completely different honestly.

I hear Sam Cooke: Ooh! Ah! Ooh! Ah! That's the sound of the kids workin' on the cha-a-ain ru-u-ule ...

I know it doesn't work, but I'd've liked to have had at least a brief discussion about why using the exponent function derivative doesn't work, e.g., we know y = x ^ n has derivative y' = nx^(n-1) If we attempt this with y = x^x, we get y' = x(x^(x-1)) * dx/dx = x^(x-1+1) * 1 = x^x I guess my question here is, _exactly what rule is it we're violating when we attempt this?_