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ThoughtThrill
United States
Приєднався 24 лис 2022
a guy who loves skydiving, reading history and sci-fi books, listening to music, and watching movies.
Every Proof that 0.999 equals 1 but they get increasingly more complex
Thanks for watching!
Timestamps:
0:00 Fractions test
0:46 Simple algebraic test
1:34 Infinite series test
4:44 Inequality and limit arguments
11:49 Proof method
14:36 Hyperreal numbers
- DISCLAIMER -
This video is intended for entertainment and educational purposes only. It should not be your sole source of information. Some details may be oversimplified or inaccurate. My goal is to spark your curiosity and encourage you to conduct your own research on these topics.
Timestamps:
0:00 Fractions test
0:46 Simple algebraic test
1:34 Infinite series test
4:44 Inequality and limit arguments
11:49 Proof method
14:36 Hyperreal numbers
- DISCLAIMER -
This video is intended for entertainment and educational purposes only. It should not be your sole source of information. Some details may be oversimplified or inaccurate. My goal is to spark your curiosity and encourage you to conduct your own research on these topics.
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Me llamo es Arturo 👹
Except they don't, or we automatically have free energy in closed systems. These aren't proofs, they are sophistry.
The duplicates are far from being a quirk of decimal expansion. In fact, _any_ representation of the real numbers by infinite strings over a finite alphabet that can be used to compute computable functions _must_ have multiple representations of some numbers. If it didn't, either some real numbers are unrepresentable and so it's not really a representation at all, or functions that should be computable can't be computed using that representation. "Computable" means "computable by a halting algorithm" for a function whose result is finite; when the output may be infinitely large, such as an infinite decimal expansion, we mean instead "computable by a productive algorithm", where "productive" means _the next character of the output_ can be computed by a halting algorithm. Since reading the input takes time, this implies that each digit of the result depends on a finite amount of the input. Therefore for real numbers the functions that are computable in this sense are precisely the uniformly continuous ones. A representation maps each finite prefix to an interval. For the representation to be complete and unique, the interval can't be open (because it would leave out the end points), nor closed (because the intervals would overlap in at least one point, so representations wouldn't be unique). But if they are half-open (as those who deny that 0.99.. = 1 believe), some uniformly continuous functions become uncomputable, because when approaching the open end of an interval, a finite amount of input can get you arbitrarily close to the boundary but cannot give you the boundary point itself.
wrong. saying 0.999 equals 1, is like saying 1=2 idiot
also. you are a far more boring and uncreative reddit rip off, of sam o nella
Now try paying 99% of your taxes.
0.999… isnt a real number and thus equality isn’t possible and you can’t simply preform algebra with it, you can look at it as an infinite equation and say it approaches one which is true but it just isn’t a number so it isn’t one.
The first two attempts are just trash and nobody should accept them.
The hyperreal numbers one is so silly, like it’s just mathematicians declaring “if you believe this, you’re breaking the rules, and the number you believe in is 0”
The best part is that there's an entire video about proofs that 1 = 1
My grandparents had an old barometer with a mercury thermometer built in that was in Reaumur. It drove me nuts because it was so hard to compare to Celsius. I wonder what became of it after the death of my grandparents...
I think the main issue is the assumption that 1/3 = 0.33333... The imperfection of decimal system just does not allows to place the equals sign between these two numbers.
You have only dealt with the weakest proof of the lot. You in turn made an unfounded assertion about decimals. 10 * 0.333... = 3.333... = 3 + 0.333... => 9 * 0.333... = 3 => 0.333... = 3/9 = 1/3. You might like to have a think about what 1 - 0.333... equals. (Hint: it's 0.666... and that leads to two arguments that 0.333... = 1/3).
@Chris-5318 You know what? My mistake, I was thinking one thing and I wrote another. What I means is that the problem is putting an equal sign between 1 and 0.9999... because they are two different notations. And this is not even a problem for us as humans because we realize that the nines in 0.999... go on forever and as a result the total result of this notation tends to 1 in infinity. However, a computer will never be able to understand this because it is impossible to achieve such precision of data to calculate it in decimal notation. For a computer 0.999... (no matter how many nines follow) will never equal 1, unless it is rounded off, or the fraction is written using two variables, one for the numerator and one for the denominator. And sorry if something is unclear, English is not my native language so there might be another mistake in words I used.
@@rafal.qwerty Computers are irrelevant. However Wolfram alpha understands it. 0.999... := lim n->oo 0.999...9 (n 9s) = lim n->oo 1 - 1/10^n = 1. " := " means is equal by definition.
It's ironic how the first and last proof are basically the same but with about 15~ years of studying between them.
Why do you say that they are basically the same argument?
Reading people arguing about this is giving me brain damage
0.9r ≠ 1 0.9r < 1 or 0.9r ≈ 1 All Good?
Nope. All bad. 0.999... = 1 is good.
stupid, this is just circle arguments, using infinity to prove that infinity exists.
No it isn't. The video is not about "proving" that infinity exists. The video has simply used the fact that infinity is a valid mathematical concept.
Well if infinity exists in math then it exists in math. I don't see the point you are making here.
10:43 Portal in a portal is weird
0:06 LEGEND OF ZELDA MENTIONED
I find it funny ( in a good way ) that the most " understood " and " intuitive " proof of 0.999... = 1 is the Calculus method ( Summation ) 😆
The calculus way is the only formal/rigorous way of doing it. Even the 10x argument, say, has to be proven using calculus, because it has a subtle flaw.
You lost me after the first one
The way i explained it to a kid who asked (whom i babysit) was that 1-0.9999... equals 0.000000...1, which is basically 0. Prob not the best proof, but he's only 7 so doesn't rlly understand fractions yet
There is no such decimal as 0.000...1. You can't have a 1 at the non-existent end of an endless string of 0s. 1 - 0.999... = 0.000... = 0. If it was OK, then 1 - 0.000...1 would be 0.999...9, not 0.999.... OTOH, surely 0.999... + 0.000...1 = 0.999...1. What do you think 0.000...1 * 10 and 0.000...1 / 10 are?
Using plancks, the entire Universe is not large enough to write out the digits. Thats crazy.
accept the idea or keep writing the number 9 till the end of time
for the 5th method, i question that interval. why not choosing an x strictly inferior to 1, and superior or equal to 0.9[n]. considering beforehand 1 as within the range is a mere confirmation bias
as i said, if 0.999999... = 1, then 0 = 1 = +∞ also, if 0.99999999... = 1, then 1/0 has a solution within R
The unit symbol is not lower case (it is on IUPAP documents) this would cause confusion with the multiplier kilo. It is only lowercase if you use the NAME of the unit because it is not a proper name.
I'm a simple polish man: I see ,,-ski" surname - I click
This just proves infinities are paradoxes and can’t theoretically exist
Repeating 9 is repeating 1 off from 1
Every time you put a "9" in the number, you make the difference 10 times smaller. If there are infinite nines, the difference tends to be infinitly small, so it simply doesn't exist.
1/inf - 1=0.r9. And if there are no numbers between 0.r9 and 1 well then that “breaks math”
Also you are slick when you made me not able to reply on that comment thread
Man this guy's stupid is he sayong that 0.3333... is 4??!! Joke
11:13 is senseless. How can something have infinite surface area but finite volume. And don't reply to this comment stating that the trumpet is defined that way.....just don't
for the first proof i never rlly understood it since what if 1/3 was based off 3/9? and rather than 1/3 = 0.333..., 0.333... = 1/3?? what im trying to say is that the result of 1/3 mightve been based off the assumed result for 3/9 and imo might not prove anything 😭i could be very wrong but thats just my thoughts
1:34. This paradox only works when both the Cheetah and Snail are considered as point masses. In real life, this paradox fails because both Cheetah anf snail are not points but have some length. The cheetah just has to reach a point where the diastance between it and snail is leass than or equal to the snail's body length.
I think 1 - 0.(9)= 1/10_in_power_of_infinity
Actually even in hyperreal, 0.999…=1 can be true. Let 0.999…;…9990 = *0.999… and 0.999…;…999… = 0.999… 1 - *0.999… = epsilon 1 - 0.099… = 0 I read book about hyperreal analysis but it was so hard to understand.
Since hyperreal contains real, the properties that hold for the reals continue to hold for the hyperreal due to the transfer principle.
Ok but is 1.999.... equal to 2
Yes if you accept 1=0.999...
if we can "prove" that .999 = 1, we need a new word for these "proofs" lmao. nothing is being proven if we can use the method to come to incorrect conclusions
.999... truthers are given far too much attention 😭
5:00 that's kind of the approach I used in middle school, just that I didn't know how to formulate it properly. In plain language: 1 - 0.9 = 0.1 1 - 0.99 = 0.01 Each further 9 in the sum on the left adds one more decimal 0 on the right. Therefore, the difference between 1 and an infinitely repeating .999... also has an infinite number of decimal 0 positions until we finally get to the 1: 0.00000... (repeat infinitely) ...1 If we were to read this number for any processing purposes, we would never reach the "1" at the end. It's just an infinite string of 0s. The 1 no longer has any meaning.
You cannot go from the finite case to the infinite case in the way hat you suggested. You, formally, need to take the limit. Also note that: 0.999... - 0.9 = 0.0999... 0.999... - 0.99 = 0.00999... and that doesn't get to 0.000..., even though that is the limit of the "process". There is no such decimal as 0.000...0999..., that being the dual of 0.000...1
how much of this video is AI-generated? the voice, surely? what about the script? don't take this the wrong way, but it's ringing some alarms in my head..
if the voice is real, take this as a compliment. if the script is real as well, i'd suggest repeating information less often (and maybe using slightly more TeX/math for illustrations instead of just cliparts)
actually, i'm 99.99999…% certain the voice is AI
the voice is clearly just a guy reading a script
i was expecting a simpler version of the LAST explanation to be the FIRST one LOL i.e. "what number would you add to 0.999... to equal 1?"
If you add any number to 0.999... you get a result that is greater than 1. The last "proof" redefined the meaning of the symbol 0.999... in an abysmal way. It completely breaks decimal arithmetic. For instance there would be is no decimal for 1 - 0.999... or 10 * 0.999 - 9. It is amazing to me that a mathematician can claim to have proved that 0.999... = 1 and in the next breath contradict himself by saying that 1 > 0.999... without so much as blinking an eye.
5:26 scp
What do you think about S1 = 0.9 = 1 - 0.1 = 1 - 10^-1?
HUH
1:33 neat but with all prime numbers being odd adding 2 together regardless would be factors for even numbers
0.99999...989983982≠1 ^^up there is 3t nines
Interesting. I only knew of three of those before. I am trying to comprehend having higher numbers indicating colder temperature. That would be tricky to get used to.