30:23 Most of the people does not notice this 3rd example of transitive relation (R-3) relation. Ye example tranisitive nahi hai kyuki R3 relation mai (3,1) hai, (1,2) bhi hai, lekin (3,2) (R3) relation mai kahi bhi nahi hai Hence it should not be transitive Like if you agree 💯
@@sasukegaming8289 The relation is a+d=b+c and here if u take (2,5) as a and b then we do need c,d such that d added to a and c added to be make them equal. Now 0 is not in the relation so cant be take and 1 added to 5 and corresponding 4 added to 2 make them 6 and 6 so 4 would be d since d is added to a. just like this (2,5), (3,6), (4,7), (5,8) and 6,9. You cant add 7 because then you would need then which is not in the relation
@@sasukegaming8289 if you add (2,5) in another subset and the sum you are getting is equal then only we can say that it is an equivalence class of that particular subset
@@savitrisharma977 May be it is depend on the example we have taken like if we take in fraction like 1/2 or 1/4 etc. than it shouws that z^2 is always less than y
Bro for JEE you have to study many such topics which are deleted from NCERT like Periodic Functions, Odd- even functions, Transformations (Graphs), etc....
JAB TUTANE LAGE HOSALE TOH BUS YE YAAD RAKHANA BINA MEHNAT KE HASHIL TAKHTOH TAAJ NAHI HOTE DUND LENA ANDERO ME MANJIL APNI JUGUNU KABHI ROSHNI KE MEHTAJ NAHI HOTE😊😊😊❤❤
1:53:01 answer is 2 according to me, btw sir lecture bahut badiaya tha, maza aaya , bas aise hi lectures aur lana aur pls practice vaale sessions bhi laana, humble request🙏🙏
@@arabindamohapatra2550 According to me this is one of the biggest drawback of recorded lectures, teacher is also a human and he can also make mistakes. In live classes we can highlight the teacher's mistake but this is not possible in recorded lectures which creates confusion for us.
1:52:11 but sir when we put (2,1) in the relation then according to transitive definition that is if (a,b)€R , (b,c)€ R then (a,c)€R here (1,2)€R ,(2,1)€R and as well (1,1)€ R. Which mean it is transitive n?
29:58 here in the 3rd relation there is (3,1) and (1,2) but there is no (2,3) then how can it be considered transitive ???? (can someone explain? incase I am wrong over here)
sir You only say that i will bring question video no this chapter in all video you have said that i will bring question video i am part of this channel since 2022 and at that time they bring what they say but now it is very sad to say but this is very frustrating😢
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😢@@PoojaRaghuvanshi-wc5pc
00:00:00 - INTRO
00:01:27 - 11TH REVISION
00:13:40 - TYPES OF RELATION
00:13:59 - NULL RELATION
00:16:05 - REFLEXIVE RELATION
00:19:23 - SYMMETRIC RELATION
00:23:27 - TRANSITIVE RELATION
00:30:46 - EQUIVALENT RELATION
00:31:18 - QUESTIONS
01:14:01 - FUNCTIONS
01:18:05 - TYPES OF FUNCTIONS
01:22:05 - QUESTIONS
01:56:19 - OUTRO
💌
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30:23
Most of the people does not notice this 3rd example of transitive relation (R-3) relation. Ye example tranisitive nahi hai kyuki
R3 relation mai (3,1) hai, (1,2) bhi hai, lekin (3,2) (R3) relation mai kahi bhi nahi hai
Hence it should not be transitive
Like if you agree 💯
yes
yes
Verg good
1,3 bhi nhi hai bro
@@Divesh0007 (1,3) is literally next to (3,1)
Vote for Inverse Trigonometric Function 👇👇👍
Aa chuka hai
1:13:20 Equivalence class of (2,5) = {(1,4), (2,5), (3,6), (4,7), (5,8), (6,9)}
how can u explain
@@sasukegaming8289 The relation is a+d=b+c and here if u take (2,5) as a and b then we do need c,d such that d added to a and c added to be make them equal. Now 0 is not in the relation so cant be take and 1 added to 5 and corresponding 4 added to 2 make them 6 and 6 so 4 would be d since d is added to a. just like this (2,5), (3,6), (4,7), (5,8) and 6,9. You cant add 7 because then you would need then which is not in the relation
@@sasukegaming8289 if you add (2,5) in another subset and the sum you are getting is equal then only we can say that it is an equivalence class of that particular subset
Sir.. PLEASE CONTINUITY AND DIFFRENTIABILITY ka ek one shot daal dijiye.. 😢kux smjjh nhi aa rhaa school mein..
Sir inverse trigonometry ka ek video banado
Yess
Haa bro hmraye school exam me aarha h ITF
56:33 in this question the relation is transitive! Bcoz if we take (x,y) : x
For example; if we take (10,4) and (4,2) then (10,2) it doesn’t satisfy relation R. That’s why it is not transitive
@@savitrisharma977 May be it is depend on the example we have taken like if we take in fraction like 1/2 or 1/4 etc. than it shouws that z^2 is always less than y
I'm IIT jee aspirant and this chapter is going through 25 days in our coaching😂
Bro for JEE you have to study many such topics which are deleted from NCERT like Periodic Functions, Odd- even functions, Transformations (Graphs), etc....
Bro hmara me toh 30 lecture hai😅
3 Din me hamare sir ne pura chapter khatam Kara diya aur mai unhi din absent tha ab one shot dekhna pad raha hai 😢
@@aryavardhan1201 if u r prep for jee Nishant vora oneshots will help you
@@yasxhh thanks 🙏
JAB TUTANE LAGE HOSALE TOH BUS YE YAAD RAKHANA
BINA MEHNAT KE HASHIL TAKHTOH TAAJ NAHI HOTE
DUND LENA ANDERO ME MANJIL APNI
JUGUNU KABHI ROSHNI KE MEHTAJ NAHI HOTE😊😊😊❤❤
Totivation bnd kro😂
@@Yadav444 kya
@@Priya-gn1xr ye faltu ki shayiri bnd karo
@@Yadav444 faltu hoga tu tere baski h toh likh Varna faltu na bol👿👿👿
😂@@Priya-gn1xr
1:53:01 answer is 2 according to me, btw sir lecture bahut badiaya tha, maza aaya , bas aise hi lectures aur lana aur pls practice vaale sessions bhi laana, humble request🙏🙏
1 hoga na bss 2 kaisai huai btana plz
Bhai tum dono galat ho 3 hoga
nhi, option 3 h answer
Yess
Yes👍@@alokgayakwar7859
1:07:41 ab(b+a) hoga na ki ab (b+c)
Ha bilkul sahi kahi ho isi ki wajah se mai confused tha lekin tumhara comment pad kar confusion dur ho gaya. Thank you 😊
@@saurabhji460 welcome 🤗
@@Censton wow
1:13:32 equivalance class of (2,5) is
(4,1), (5,2), (6,3),(7,4),(8,5),(9,6)
Wrong answer hai. Elements ki position change hogi
Bhai 3 [c] hai correct
Amazing video Jo doubt aaya wo agle question mein sir ne apne aap hi solve kar diya
1:13:50 sir equalence class of (2,5) is (1,4),(2,5),(3,6),(4,7),(5,8),(6,9)
Brother how?
(2,5)R(c,d)
=>2+d = 5+c
=>d-c=5-2=3
Therefore, we have to find those ordered pair whose difference is 3 from set (A×A)
@@StuDent-v7j thanks buddy
@@animefusion-db8xv 😌✌🏻
0:09 0:11 0:12 application of derivatives
1:53:15 homework answer - 2
How?
1:53:08 homework answer is option ( b ) 2
Hii
Agreed
I got this:-
R1= { (1,1)(2,2)(3,3)(4,4)(1,2)(2,1)}
R2={(1,1)(2,2)(3,3)(4,4)(1,2)(2,1)(2,3)(3,2)}
R3={(1,1)(2,2)(3,3)(4,4)(1,2)(2,1)(2,3)(3,2)(1,3)(3,1)}
I was literally waiting for lecture
and please month end tak inverse trigonometry ka bhi one shot upload kar dijiye ❤❤❤❤
Already uploaded plz check
bhai kab ke wa chuke
Sir transitive relation me last wala example transitive nahi hogaa... Kyunki usne (3,1) or (1,2) haai pr (3,2) nahi h.!
30:30 We have (3,1) and (1,2) but we don't have (3,2) so how can this be Transitive??
no but if u dont even have (1,2) in relation then it is transitive
@@NoobPro24boi I did not get your point
According to me it shouldn't be transitive
Yes @OpGamer-io3th I agree strongly with your point
Mai bhi wahi soch raha tha ki ye transitive kaise hua and sir ka ye mistake ko koi tackle kaise nahi kiya !
@@arabindamohapatra2550 According to me this is one of the biggest drawback of recorded lectures, teacher is also a human and he can also make mistakes. In live classes we can highlight the teacher's mistake but this is not possible in recorded lectures which creates confusion for us.
1:52:11 but sir when we put (2,1) in the relation
then according to transitive definition that is if (a,b)€R , (b,c)€ R then (a,c)€R
here (1,2)€R ,(2,1)€R and as well (1,1)€ R. Which mean it is transitive n?
I also have same doubt. tell the reason once you get to know pls!!!
Full relation is calculated. If a relation is (2,1)(1,2) then it will be transitive but here we have other subsets like (2,1) (1,3) but not( 2,3)
@@nidhanshiraheja2581 Ok so youtube section is a chatting group right ? IDIOTS
SEARCH ON GOOGLE
@@AnuragChaudhary-sd9go are wahh mst idea hai ☺️
The answer to the question at 1:53:19 is b
And thank you for the lecture sir
20:26 Softly by Karan Aujla
37:29 (ii) is neither Reflexive nor Symmetric but it is Transitive
Continuity and differentiability
plz watch at 2x 41:46
Sir actually mai itne dino se preshan thi ki relation function ko lekr mujhe aata hi nhi tha but aaj laga so easy ❤ thank you sir by heart ❤
53:16 how successfully he managed to answer it
Love uuuu sir....... ❤❤❤🥺thankuuuuuuu sooo soooo much 🎉🎉🎉🎉🎉🥺🥺🥺❤❤❤
1:53:10 -> (B) 2
29:58 here in the 3rd relation there is (3,1) and (1,2) but there is no (2,3) then how can it be considered transitive ???? (can someone explain? incase I am wrong over here)
Same doubt 🧐
Trust is very important for a relation ...........
Jai hind sir ❤
1:53:22 answer is b 2
13:01 Arrow diagram
39:07 yes sir transitive hai..
How
Short and crisp lecture.Good for revising basics
Not good for studying for the first time?
Best teacher on youtube joh aapko simple way mein samjha deta hai and basic clear karva deta hai...
❤❤
Sir how can we join your offline batch.?
Thank you sir, this video has helped me a lot
Answer of Homework question - Equivalence class of (2,5) is (1,4) (2,5) (3,6) (4,7) (5,8) (6,9)
Thank you sir bahat maja aagya.
44.2 No
37.37 No
54:07 normal circumstances
39.14 question R (x,y):y is equal to x plus 5 ,x
Yes (a,b) belongs to r but there is not (b,a) is not in r
Extremely helful sir , i was struggling with equivalence class and equivalence relation topic but your video made it crystal clear ❤
Thanku
Sir any one of these is the main question
Thank u sir ❤
Thank you so much sir 🙏🙏 for this series...
Sir 30:33 me thoda wrong hogya aapse . I think ye transitive nhi hoga kyuki (3,1)∈ R3 and (1,2) ∈ R3 but (3,2) ∉ R3
You are right
@@AdityaKumar-jv5nn hmm
right
Sir next lecture please INVERSE TRIGONOMETRIC FUNCTIONS 🙏🙏🙏🙏
inverse trigonometric function
Class Notes kaha milega???? Telegram pe to nahi mil rha
Best math teacher ❤❤❤❤❤❤❤
Yes bro
I want to study with him tell me he is ryte for 12 board
Mera btao bhai m bhur confuse hu
Ashish sir and ye sir best hai on UA-cam
1:53:07 correct ans (C)
30:36 sir example 3rd mai (3,1)hai(1,2) hai but,(3,2) nhi hai, uske it is not transitive
Boyfriend boyfriend 💀
Teri category 🙂
😂😂😂@@defencelover192
Can I watch this lecture for the first time? Is it detailed or revision?
Sir applications of derivation kra do ek baar
1:53:17 answer is 2
Sir this was a extremely helpful one shot, all my concepts were clear. Thank you
Thankyou sir ❤🎉
1:17:55
1:53:14 sir answer is 2
sir 29:43 pr jo h last wala releation according to me transitive ni hona chahiye because usme (3,1) or (1,2) h but ( 3,2) nhi h
The only 2 hours lecture I attended without taking a break..gonna stick with science and fun!
1:12:11 imp pyq
Brahmastra for last time revision
Thankyou sir maja aya
Sir 17 question me reflexive me to ab(b+a)=ba(a+b) hona chahiye tha
Timestamp:- 5:04
Ek ladki
13:48 actually started from
Maaja aa gya sir ji😊😊
bare shi ho sir aap ❤❤❤ aapki padai me majaaa aa jata hai aur kisi teacher se samajh ni aata aapse sab samajh aa jata hai eak baar me
Sir inverse trigonometry
Finally
sir You only say that i will bring question video no this chapter in all video you have said that i will bring question video i am part of this channel since 2022 and at that time they bring what they say but now it is very sad to say but this is very frustrating😢
Sir inverse trigonometry kab aaya gai??
We need inverse trigonometric
Yes😊
If I don't know anything about relation and functions is this enough for CBSE board
❤
y=x+5 Wale transitive kaise hoga jab b,x h hi nahi
Skip basics at 13:41
06:10 boy friend boy friend hai🤣🤣
1:07:24 sir vaha ab( b+a) hoga apne c glti se likha hai ya mai glt hu ....
You are one of them who found a mistake 🎉
13:00 Arrow Diagram
13 .1 aro diagram
Inverse trigonometric sir
Maths❤ kis kis ka sabse best subject hai 😊
Thank you sir it helped me a lot
Sir please 11 class ki math pdha doh paper shuru hona wla hai september se..
59:31 sir A is give so (a,a) = 0 dose not belong to A there for a is not reflexive
what is the correct answer bro
0 does not have to belong to A. It just needs to be even. That's the relation. Only a needs to belong to A. So the relation is indeed reflexive.
41:50 was op🤣
Yes bro
1:53:15 Homework ans = (B)2
How?
no it's 1 bro
@@mr.camera.indian8707 its' one dont worry
N@@sunnyshah2160is it's one one but ye log kese 2 nikal le rahe hai kahi me hi to galt nahi hu
@@OptimusPrime-wc1ff answer is 2
R1 = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)}
R2 = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1),(2, 3), (3, 2), (1, 3)(3,1)}
6:10 talwarbazi💀
13:47