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+Mr Sai Mun yes its moving behind..but if I want to calculate.. above the x axis the values are (+).. but what about the below?? should we calculate with the (-) sign or no need?
Ok, so does it mean, ( im gonna say until very complicated bc idk how to explain my understanding ajshsjjs ) ok so, is it like, the V-T GRAPH is the one who DECIDES THE MOTION OF ALL THE OTHER GRAPHS? Ok and does it mean that, if V-T GRAPH IS INCREASING, CONSTANT, DECREASING VELOCITY, ( POSITIVE, ABOVE THE GRAPH ), the S-T GRAPH'S gradient IS POSITIVE AND THUS, THE LINE DRAWN AND GOING UP AND UP UNTIL THE V-T GRAPH REACHES ZERO VELOCITY, WHICH MAKES THE S-T GRAPH HAS NO CHANGE. DO I GET IT RIGHT?? And so, if the V-T GRAPH is UNDER THE GRAPH, the S-T GRAPH's GRADIENT WILL BE DECREASING thus THE LINE DRAWN IS GOING DOWN AND DOWN?? is it?? Andddddddd V-T GRAPH CONTROLS A-T GRAPH TOO. So when there is increase of velocity, the S-T graph line will be on the graph, while when the V-T GRAPH IS CONSTANT AND ZERO, THE A-T STAYS AT ZERO THERE. and when the V-T GRAPH decreases / is under the graph ( negative ) THE A-T GRAPH LINE IS ONLY DRAWN UNDRR THE GRAPH???
Thanks for watching this video. Pls give it a big Thumbs Up and also click on the big Red Button. Comments are much appreciated also. Take care & Stay safe.
hello sir! I was wondering about the calculation of motion graph.. when should we use negative during the area under graph?
+Mr Sai Mun yes its moving behind..but if I want to calculate.. above the x axis the values are (+).. but what about the below?? should we calculate with the (-) sign or no need?
Thank you sir! Are you running a tuition? Because i think most of your vids are from spm's syllabus
yes, we have spm and igcse videos. for this video you can use for both. Thanks for your comment.
thanks
Very good
thanksss
Ok, so does it mean, ( im gonna say until very complicated bc idk how to explain my understanding ajshsjjs ) ok so, is it like, the V-T GRAPH is the one who DECIDES THE MOTION OF ALL THE OTHER GRAPHS? Ok and does it mean that, if V-T GRAPH IS INCREASING, CONSTANT, DECREASING VELOCITY, ( POSITIVE, ABOVE THE GRAPH ), the S-T GRAPH'S gradient IS POSITIVE AND THUS, THE LINE DRAWN AND GOING UP AND UP UNTIL THE V-T GRAPH REACHES ZERO VELOCITY, WHICH MAKES THE S-T GRAPH HAS NO CHANGE. DO I GET IT RIGHT?? And so, if the V-T GRAPH is UNDER THE GRAPH, the S-T GRAPH's GRADIENT WILL BE DECREASING thus THE LINE DRAWN IS GOING DOWN AND DOWN?? is it?? Andddddddd V-T GRAPH CONTROLS A-T GRAPH TOO. So when there is increase of velocity, the S-T graph line will be on the graph, while when the V-T GRAPH IS CONSTANT AND ZERO, THE A-T STAYS AT ZERO THERE. and when the V-T GRAPH decreases / is under the graph ( negative ) THE A-T GRAPH LINE IS ONLY DRAWN UNDRR THE GRAPH???
Omg i asked so long im sorry
@@yunyi2895 @-@
Tq so much your video soogood
Welcome 😊
You teach so good omgomgomg do you open a tuition I wanna go
yes i do. you can find more info at vbest.edu.my
could you please add a lesson about gait motion, please
Thanks. Really helpful.😊
thanks. Pls subscribe and share with your friends.
great thanks,
I don't understand the part C of v-t graph, can you give me more explanation
very useful tyty
Welcome 😊
halo! may i ask why displacement is a curve?
displacement - graph is curve when there is acceleration. (velocity is not constant)
That was a fantastic explanation - Thank you.
Thank you so much. Pls subscribe and share with friends
wow
wowie
I just realised this video was 5 years ago....
knowledge never grow old
mr sai mun hahahah so professional
Hahaha sorry if it cringes you but you have a nice voiceee
awww.. thanks.