Did anyone notice he said that he stole his daughter's toy for that demo 😂😂 Wish my teacher also will teach like you, absolutely amazing👏👏👏👏, now I understand everything about physics from your videos sir, thank you so much and God bless you😄😄
Literally sir, if there would be the teachers like you then those days are not so far that our country will be a superpower country, I am not exaggerating sir, I am telling truth sir ji.
As you know, Work = force × displacement Here, boy has to lift a mass of 5 kg upwards with a force which is equal to its weight (mg ) F = mg = 5 Kg × 10 m/s^2 = 50 N But, he displaces it to height of 150 cm = 1.5 m Hence , W = 50 N × 1.5 m = 75 Joule work done: work is said to be done when a force F acts on an object and object moves through a distance or there is displacement in the direction of the force. i.e work done =F×S work done can be zero when any of these things happen:- 1.) when the force applied is zero. 2.) when displacement is zero. 3.) if cos is 90° then work done is zero . w=FScos work is a scalar quantity, it has only magnitude not direction.
1) W = Fs = 50 × 1.5 ( w= mg = 5× 10) ( 150 cm = 1.5 m ) = hence , work done = 75 J 2) The force and the displacement are in the perpendicular direction, we can say that the work done is 0 J (or)w = fscos theta = fs × cos 90 = 0 = 0 J 3) work is scalar quantity
(Answer of Q1) The minimum force applied by the boy is the weight of the box. Weight=mass X gravity =(5 X 9.8)N=49N As the force and displacement are in the same direction,we can use the formula Work=force X displacement =49N X 150cm =49N X 1.5m=73.5J (Answer of Q2) Under the following conditions, work done is zero ---- 1) When the force applied is zero, the work done is also zero. 2) When the displacement is zero, the work done is zero. 3) When the angle between the force and displacement is 90 degrees, work done is zero. (Answer of Q3) Work is a scalar quantity.
Wow, from Nigeria, I started watching your video yesterday and I really like the way you teach, the best I have come across. May God continue to strengthen you.
Hello dear from nigeria can u do friendship with me . iam a very weak in english And for learning english plz friendship with me .and which language is spoken in your country .
Thankyou sir The answer of the questions 1.75 J (5*10(accelaration due to gravity= 50 mass we have to convert 150 cm to meter which is 1.5 meter work=force*displacement 50*1.5=75J)) 2.When the force and displacement are perpendicular to each other 3.Work is a scaler quantity
Q1 Answer will be 75J. I think you forgot to multiple by 'g' = 10 m/s2. F = mg. Q2 Right! Also when force is zero or displacement is zero. Q3 Even though force and displacement are vectors, work is a scalar product. It's a scalar quantity since work has no direction.
sir your infinity star teacher if all teachers like u we students wont get problems in studies sir the answer for first question is 75 j and question 2 when force and displacement are not in same direction and question3 work is a vector quantity as displacement is present in it if correct pls reply sir
1) Force= 5N Displacement=150 cm = 1.5 m Work= Force x Displacement =7.5 J/ Nm 2) Work done is 0 when the angle between the for and the displacement is 90 degrees. 3) Work is a scalar quantity because it doesn't have distance but only magnitude. Thanks for the tutorial really helped! :)
If I'm not mistaken, you can't change KG to N. Since the given is 5 kg, you will convert it to N, where N=((kg)(m)/(s^2). And F=mg. Where you will use the gravity in this situation. W=Fd F=mg F=(5kg)(-9.81m/s^2) F=49.05N Substitute, W=(-49.05N)(1.5m) W=-73.575Nm or -73.575J
@@brenzkimseysabado1675 I do not believe the work done by the boy is a negative value since the boy lifted the book in the direction of the displacement. The work done by gravity would be negative since it is opposite of displacement. Have to be careful to know who, or what is doing the work. Yes, gravity is doing work in this problem yet that is not what was asked.
Thank u so much for this video it really helped me and made the topic easier to me Really sir if all schools had teachers like you then it would be great
Sir your explain is very easy to me and I improve in the physics class so thank you so much sir and I share the video to my friend also sir and my friend also improve ed sir so thank you so much sir 🙏
What if I apply a force of 10N into an object in space. Theoretically its displacement will tend to infinity as time tends to infinity. So it's work will tend to infinity?
Work done by an object is the gain of energy or expenditure by the object. When a body moves, it has kinetic energy whose mathematical formula is 1/2 mv^2. Here we do not need to know the displacement.
thank you sir......you are the BEST TEACHER IN THE WORLD........and my request is to make all videos regarding MATHS,PHYSICS,CHEMISTRY....almost all you have covered sir.......but remaining topics also make videos sir.....PLEASE SIR.....
@@ManochaAcademyI really love your method of teaching I was avery dull student in science but I am now at the average Thanks Mulch love From Nigeria🥰👍💥🏆
Ans.1 W = 75J Ans. 2 When the angle between force and displacement is 90 degree or the force is perpendicular to displacement. Ans. 3 Work done is a vector quantity.
Sir your video on work is more convincing. Even you use simple indian pronunciation. That's why I am impressed. Thank you sir. You are doing hard work. Without the intension of fruit. Thank you again. Keep it up!
Sir I want to ask another question on this topic.If I walk in a Circle many times then my body tired but due to zero displacement my work done is zero so where my body energy goes?
That's a great question! Yes the work done is zero due to zero displacement. But the body is doing work against the force of friction of ground. Which gets dissipated as heat energy. Plus work is being done at a muscular level. Here again some of the energy is dissipated as heat. So if we take into account these work dones and energy changes, that's where our body's energy is going. So we feel tired. Hope that helps :)
@@sivakumar-oh2if Coz that's how it is, work is the dot product of force and displacement. No offence, but your question is like asking why is sin/cos=tan.
Answer 1:- (-75 j) Answer 2:- when the angle between force and displacement is 90 digree... Than work done is zero.. Answer:- work is scalar quantity...
@@ManochaAcademy i have a bacaloriate exam this year ,and i hope that i'm going to got the full mark ! A greeting from heart to such a great techers like you From Algeria ( north of Africa)
@@ManochaAcademy i am soo late..I now know about such this class. My friend recommended it to me. It felt good to hear that. Very well understood. When your examples come together, the class gets excited. i like it. love from kerala💞... Where is ur place?
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos at www.manochaacademy.com . I have arranged the videos by subjects: Physics, Chemistry and Maths. I'll be uploading more videos!
Sir how do you do these videos with patience you are such an amazing teacher I never I never hear this explanation one day unfortunately I open your video and the teaching is excellent and I went for comment section and all the comments are amazing excellent mind blowing super explanation all the comments are positively thank you sir you are such a great teacher and I am a big fan of you sir in studies thank you sir
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If all the teachers teach like you then the students will not face problems in studies
Great to hear that you liked the video!! Thanks a lot :)
S sir please upload detailed information with examples at that time student can easily understood.....
rad
Correct
@@chanduchayvlogs9548 that is rude he makes it very clear he is a good teacher
This is the best teaching i've ever seen thanks a lot sir.
You are most welcome
Sab dhoka baji ha
ua-cam.com/channels/CtouuwYwq8Ostl5B4ZzomA.html
@@ayushmeerut43 e tu jjaa re
tere ko nahi padna to mat padh na
k
Did anyone notice he said that he stole his daughter's toy for that demo 😂😂
Wish my teacher also will teach like you, absolutely amazing👏👏👏👏, now I understand everything about physics from your videos sir, thank you so much and God bless you😄😄
agreeed gurl
Yes 🤣
Word
YA DUDE...
Stole toy for thousands of students to understand work
Literally sir, if there would be the teachers like you then those days are not so far that our country will be a superpower country, I am not exaggerating sir, I am telling truth sir ji.
1) 75 J (Taking g=-10m/s^2)
2) Work done is zero , when force and displacement are perpendicular to each other
3) Scalar Quantity
the first one taking g as 9.8m/s^2 is 73.5 J
❤
Mass (m)= 50 kg
Displacement(s)=150cm=>1.5 m
Work Done(w)=F.s.
W= 50*1.5
= 75J
Im learn future grade syllabus,thank you so much sir, I love the way you teach.
"Pause the video and get a book right now"
Me: Holds my phone
What a coincidence bro I also hold a phone..
As you know,
Work = force × displacement
Here, boy has to lift a mass of 5 kg upwards with a force which is equal to its weight (mg )
F = mg = 5 Kg × 10 m/s^2 = 50 N
But, he displaces it to height of 150 cm = 1.5 m
Hence , W = 50 N × 1.5 m
= 75 Joule
work done:
work is said to be done when a force F acts on an object and object moves through a distance or there is displacement in the direction of the force.
i.e work done =F×S
work done can be zero when any of these things happen:-
1.) when the force applied is zero.
2.) when displacement is zero.
3.) if cos is 90° then work done is zero .
w=FScos
work is a scalar quantity, it has only magnitude not direction.
1) W = Fs
= 50 × 1.5 ( w= mg = 5× 10) ( 150 cm = 1.5 m )
= hence , work done = 75 J
2)
The force and the displacement are in the perpendicular direction, we can say that the work done is 0 J (or)w = fscos theta
= fs × cos 90 = 0
= 0 J
3) work is scalar quantity
Thank you so much
@@sanjuktamalakar2241
Y😂
(Answer of Q1) The minimum force applied by the boy is the weight of the box.
Weight=mass X gravity
=(5 X 9.8)N=49N
As the force and displacement are in the same direction,we can use the formula
Work=force X displacement
=49N X 150cm
=49N X 1.5m=73.5J
(Answer of Q2) Under the following conditions, work done is zero ----
1) When the force applied is zero, the work done is also zero.
2) When the displacement is zero, the work done is zero.
3) When the angle between the force and displacement is 90 degrees, work done is zero.
(Answer of Q3) Work is a scalar quantity.
How do you get 49
@@onimolebolanle5740 f=ma
Mass=5kg
Gravitation (acceleration due to earth)=9.8m/s²
m*a=5×9.8
F=49N
the formula for Q1 isn't F.S.COS 180 DEGREES [-1]? cause that's the gravitational force which is in the opposite direction right? so cos 180 degrees
@@03alyanurul92no
1) 7.5J
2) work done is zero when force and displacement are in the same direction .
3) scalar quantity
Thank you sir. I understand better
Wow, from Nigeria, I started watching your video yesterday and I really like the way you teach, the best I have come across. May God continue to strengthen you.
Thanks a lot :) Do check out more Videos, Quiz and Top 3 Questions on my website: www.manochaacademy.com
Where are the answers?
ua-cam.com/channels/CtouuwYwq8Ostl5B4ZzomA.html science channel
Hello dear from nigeria can u do friendship with me . iam a very weak in english And for learning english plz friendship with me .and which language is spoken in your country .
@@danishmushtaqdraboo5729 English
Sir you teach using many different examples which makes our study easier
Glad to hear that
Very good explanation sir 👍. Thank you 😊😊😊
Most welcome
Sir ! Why SI unit of work and energy is same?
Thankyou sir
The answer of the questions
1.75 J
(5*10(accelaration due to gravity= 50 mass
we have to convert 150 cm to meter which is 1.5 meter
work=force*displacement
50*1.5=75J))
2.When the force and displacement are perpendicular to each other
3.Work is a scaler quantity
Me who wasted so much time in calculation by reading the 75 J as 1.75 J 😭
@@fathimamuzammil8818😂😂😂😂😂😂
Today your work was to make us (not work) but understand perfectly!😀
I don't know what is the magic behind your teaching.👍 But you are really great
Wow, thank you
Q1: 7.5J
Q2: Under 90 degrees angle of displacement and force.
Q3: vector quantity since direction is involve
Q1 Answer will be 75J. I think you forgot to multiple by 'g' = 10 m/s2. F = mg.
Q2 Right! Also when force is zero or displacement is zero.
Q3 Even though force and displacement are vectors, work is a scalar product. It's a scalar quantity since work has no direction.
Sir your teaching is so great it even helped me to understand work and force I really adore your teachings sir like really!👍
Glad to hear that
👍👍keep it up
This video help me to understand work topic easily
Sir you deserve million subcribers not k subcribers.
Ans-1 =2.25J
Ans-2 = yes, when friction is present so work is 0
If all sciences teacher are like you...we will have many scientist
Great to hear that you like the videos!! Thanks :)
You are the best teacher
THANKS
Thanks sir, this video really helped me for my exam! From the Philippines🇵🇭
1 question answer is7 .5 beacuse w = f x s so we convert into the si units first and then multiply 3 answer work done is netier scalar nor vector sir
Iam a teacher.i learned a lot from your teaching in this holidays.thank you sir
sir your infinity star teacher if all teachers like u we students wont get problems in studies sir the answer for first question is 75 j and question 2 when force and displacement are not in same direction and question3 work is a vector quantity as displacement is present in it if correct pls reply sir
1) Force= 5N
Displacement=150 cm = 1.5 m
Work= Force x Displacement
=7.5 J/ Nm
2) Work done is 0 when the angle between the for and the displacement is 90 degrees.
3) Work is a scalar quantity because it doesn't have distance but only magnitude.
Thanks for the tutorial really helped! :)
If I'm not mistaken,
you can't change KG to N. Since the given is 5 kg, you will convert it to N, where N=((kg)(m)/(s^2). And F=mg. Where you will use the gravity in this situation.
W=Fd
F=mg
F=(5kg)(-9.81m/s^2)
F=49.05N
Substitute,
W=(-49.05N)(1.5m)
W=-73.575Nm or -73.575J
@@brenzkimseysabado1675 I do not believe the work done by the boy is a negative value since the boy lifted the book in the direction of the displacement. The work done by gravity would be negative since it is opposite of displacement. Have to be careful to know who, or what is doing the work. Yes, gravity is doing work in this problem yet that is not what was asked.
thank you sir i was confused with the concept of work but now i am cleared your way of teaching is best
If you'll teach me physics I'm gonna to become a best student. You are mind-blowing teacher
Yes yes ✅👍
Lol you are wrong
🦍🦍🦍🦍🦍🦍🦍
Yes yes👍👍
Yes sir
Thank u so much for this video it really helped me and made the topic easier to me
Really sir if all schools had teachers like you then it would be great
Sir your explain is very easy to me and I improve in the physics class so thank you so much sir and I share the video to my friend also sir and my friend also improve ed sir so thank you so much sir 🙏
Keep it up
Excellent explanation
Thanks a lot sir..🙏🙏🙏
Welcome
Yes, - 7.5 joule q2 at right angled q3 scaler quantity
It is scalar physical quantity because it is dot between force and displacement
When u are there there is no problem with online classes
Great !!!
ua-cam.com/channels/CtouuwYwq8Ostl5B4ZzomA.html science channel
Ans-3 = vector because it has both magnitude and direction
What if I apply a force of 10N into an object in space. Theoretically its displacement will tend to infinity as time tends to infinity.
So it's work will tend to infinity?
Work done by an object is the gain of energy or expenditure by the object. When a body moves, it has kinetic energy whose mathematical formula is 1/2 mv^2. Here we do not need to know the displacement.
Bad
Your explanation is so awesome!! Thank you sir..
Most welcome
1 - 5*10*1.5 =75joule
2- when force and displacement make 90
3 vector
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Are u pubg pro??
@@deviprasadpalli5236 he is fake
3 is scalor
Sir please explain the second formula!!! Thank you and god bless you sir!!!!
i had many doubts in this subject sir but it got clarified now thanks to you sir
Amazing teacher & learning process is wonderful .
Omg ! IF MY TEACHERS EXPLAIN LIKE THIS THEN 105/100 IS CONFORMED
REALLY ☺
O realy
@@sonymishra3594 Yess
@@anitapandey5261 really aumsum video
No way chansee la hela doppu 😆😆😆😆😆🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣
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Thanks
Welcome
thank you sir......you are the BEST TEACHER IN THE WORLD........and my request is to make all videos regarding MATHS,PHYSICS,CHEMISTRY....almost all you have covered sir.......but remaining topics also make videos sir.....PLEASE SIR.....
😊
It's a great video for work
You are a great teacher, sir, the best one I have known. If only I had a nice teacher like you.
Wow, thanks
Sir, what happened when displacement=0
No work
i subed cuz he resembles my friend
and he teaching is spelended
1.7.5 j
2.if force and displacement was 0 . the work done also 0
3.scalar
I wish every teacher of every subject could be as clear and perfect as u 👍👌🏼❤️
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos on my UA-cam channel page or on my website: www.manochaacademy.com
If what you said was real, you would have watched this vid.
@@ManochaAcademyI really love your method of teaching
I was avery dull student in science but I am now at the average
Thanks
Mulch love
From Nigeria🥰👍💥🏆
Ans.1 W = 75J Ans. 2 When the angle between force and displacement is 90 degree or the force is perpendicular to displacement. Ans. 3 Work done is a vector quantity.
Excellent learning of physical science happily
Excellent explanation sir 👍👏
This type of energy and Intresting teachers should be there in our school .
what
it should be in ALL schools
Under what condition is work done is zero
answer is cos 90.(Watching from Nigeria)
Work Done Will be 0 If
F = 0
S=0
& Angle Between Force and Displacement is 90* (cos 90* = 0)
7 star teacher that I have ever seen
Thanks a lot :) Do share our videos with your friends!!
1)7.5J
2)when the direction force and displacement are perpendicular to each other
3)vetor quantity
teachers should be like you sir,Superb Explanation I like it
Thanks a ton
👍
Sir your video on work is more convincing. Even you use simple indian pronunciation. That's why I am impressed. Thank you sir. You are doing hard work. Without the intension of fruit. Thank you again. Keep it up!
Sir really we are very lucky to listening ur videos.
It's my pleasure
Best video on UA-cam! Thanks for the clear and funny video from America!
3:14 daughter be like : dad where is my toy
Do you have an app cause I am a big fan of you
I enjoyed watching your videos! Amazing.
Thanks! Glad you liked the videos :) I'll be posting more videos regularly!
Hi how are yuo sir yuor all teaching is very nice
You are amazing master teacher
Thanks
Sir I want to ask another question on this topic.If I walk in a Circle many times then my body tired but due to zero displacement my work done is zero so where my body energy goes?
That's a great question! Yes the work done is zero due to zero displacement. But the body is doing work against the force of friction of ground. Which gets dissipated as heat energy. Plus work is being done at a muscular level. Here again some of the energy is dissipated as heat. So if we take into account these work dones and energy changes, that's where our body's energy is going. So we feel tired. Hope that helps :)
@@ManochaAcademy why cont we use distance instead of displacement sir please help thanks
@@sivakumar-oh2if Coz that's how it is, work is the dot product of force and displacement. No offence, but your question is like asking why is sin/cos=tan.
Manish kumar Sharma
@@ManochaAcademy sir can u say which guide is best for 11 cbse because my sister is going to study 11 please
Answer 1:- (-75 j)
Answer 2:- when the angle between force and displacement is 90 digree... Than work done is zero..
Answer:- work is scalar quantity...
Q1) -75 J
Q2) When the Q is 90°. When force is equal to zero and displacement is equal to zero
Q3) It is a scalar quantity
Did you use g= -10?
You are correct only but that is .75J
750 j work aara ha mera koi btao sahi ha ya glat
I got Q1) 750
Q1 = 75 J
Q.1} 7.5 j
Q.2 } cos90°=0, where F=0, S=0, if taken work of gravity then W=-1
Q.3} Scalar because it can be measured accurately.
hi how about you
wow what a style of teaching||New subscriber here💖||@Amazing
Welcome aboard!
Can u come to our school and can u be our physics and chemistry teacher in Banglore, Akash International school. Please come to our school.
I'm feeling so bad 😶 I knew that you make videos like this but still I was tensed of this chapter 😑 uffff 💁🏻♀️
Great teacher i mever see
Thank you sir..❤️
3:14 my favourite part in this video...😂
Please give a Heart❤️ Sir.
This is very very useful and it is such amazing for childrens
Thanks a lot
Sir, how unlucky I am feeling to myself that how late I came to know about your videos.
So nice of you
Me also 😂😂😂
doubt why there is no work done when we hold bag in hand ? and why work done is there when we put it on head
Thank you for your support Sir. U explained it so easily. U don't even know that how much I was worried about this chapter and topic as well.
Happy to help
Thnx sir.
@@ManochaAcademy i have a bacaloriate exam this year ,and i hope that i'm going to got the full mark !
A greeting from heart to such a great techers like you
From Algeria ( north of Africa)
Sir i have a doubt
Force and displacement are both vector quantity , then why work is scalar quantity
Sir please sir please answer the question 🙏
Thank you so much sir
for Your explnation clearly and praticlly
And also thank to you done good job for us
Great to hear that you liked the video :) Thanks!
In Ethiopia very good thank you teacher.👍👍👍
Most welcome
Your teaching methods are awesome sir . Love from ranchi
Thanks a ton
Amazing one....
Thank you! Cheers!
@@ManochaAcademy i am soo late..I now know about such this class. My friend recommended it to me. It felt good to hear that. Very well understood. When your examples come together, the class gets excited. i like it. love from kerala💞... Where is ur place?
Sir you're superb...I like your teaching always , as I like spending time with my frnds ...It's really a fantastic experience for me ...😀🙂
🙏 🙏thanks 🙏🙏
U R Amazing!!👌👌👌 Plz Upload Class 10th Science all chapters!!!!
Thanks a lot :) Happy to hear that you liked the video!! Do check out more videos at www.manochaacademy.com . I have arranged the videos by subjects: Physics, Chemistry and Maths. I'll be uploading more videos!
@@ManochaAcademysir I have shared ur video s to my friends
Q1- 75J
Q2- when friction is acting on the object
Thank you sir you are the best
Great to hear that you liked the video! Thanks :)
3:14 So funny!!! You teach the concepts very well!!
Thank you ,you're great teacher go forward
Happy to hear that you liked the video!! Thanks :)
thanks dear teacher
Sir how do you do these videos with patience you are such an amazing teacher I never I never hear this explanation one day unfortunately I open your video and the teaching is excellent and I went for comment section and all the comments are amazing excellent mind blowing super explanation all the comments are positively thank you sir you are such a great teacher and I am a big fan of you sir in studies thank you sir
Wow, thanks
@@ManochaAcademy you're the best teacher we've ever seen on UA-cam
From the start message I was already concentrating like never before.
Thanks sir, this video is very helpful for me
Glad to hear that
sir pls make a video on theory of relativity