@@tuatarian6591 How about a formula for it? Is that a thing? I know that the LINEAR regression equation is already complicated, so I'm not looking forward to the quadratic one, but would you know where to find it? (Also I'm seeing this comment 10 years ago and 10 months for the reply, what the heck?!)
@pratiksrc is standard knowledge for projectiles, projectiles always follow a parabola - x^2 so quadratic dats why. its just summut you have to know for this example. ovawise its trial and error by looking at the graphs for the original data
I found this document. It might help? www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=12&cad=rja&uact=8&ved=2ahUKEwjj07DHqIrgAhVUGDQIHQMuD_0QFjALegQIChAC&url=https%3A%2F%2Fwww.farmingdale.edu%2Ffaculty%2Fsheldon-gordon%2FRecentArticles%2Fquadratic-regression-equation.doc&usg=AOvVaw1SRqApHbBqiWcHmAWbKBym edit: replaced typeo with "It" instead of "I"
Also there is an analytical, theoretical solution for this, which we learned in our high schol physics class (back in the day), with aerodynamics (mainly drag) neglected and gravity being the sole influence changing the speed vector of the object (golf ball) once it is travelling. That analytical solution is quadratic. If you know beforehand that the relation should be quadratic (or, very predominantly quadratic in real life), you should use quadratic regression as well.
Ok, found out the theoretical height as a function of time in a vacuum: -(1/2)g t^2 + Vy0 t g= gravitational acceleration Vy0= starting velocity in the y direction And Vy0=40*sin(70)=37,6 h(t)=-4,9t^2+37,6t Voila! We can solve for h=0 and get how long it takes before landing: t=7,67 Finding velocity in x direction (stays constant because the only force, gravity, works at an 90 angle): Vx=37,6 37,6m/s*7,67s=288m That ball'll travel 300 meters in a vacuum! I love MATHS!
math makes me wish i was never born
For some reason, I can't find this on the Khan Academy website
... so what's r^2 equal to and how do you use a calculator to find it? Trying to find how to calculate the regression itself
🙏 Thank you so much, you saved my entire math class. 😂
Is there a video that shows how to determine a quadratic regression by hand?
It's not simple at all, but the search term an internetter would be looking for is least squares quadratic regression
@@tuatarian6591 How about a formula for it? Is that a thing? I know that the LINEAR regression equation is already complicated, so I'm not looking forward to the quadratic one, but would you know where to find it?
(Also I'm seeing this comment 10 years ago and 10 months for the reply, what the heck?!)
@@thecodedmastergeodash8807 you can use linear algebra to solve any degree regression using least squares
Ok, but i wanna know how to do it *by hand* and without a calculator.
@pratiksrc is standard knowledge for projectiles, projectiles always follow a parabola - x^2 so quadratic dats why. its just summut you have to know for this example. ovawise its trial and error by looking at the graphs for the original data
Can't wait to see the computer algorithm for quadratic regression video. Do you think Excel would be better to illustrate this concept?
@purefatdude2 Grade of math as in level of math? I'm doing this stuff in Brief Calculus if that helps
@bryanfunk You can probably find a TI-85 emulator by using a Google search; I download an HP-15C emulator fairly easily.
If i want to do it but with an equation with terms c1-c2*x^2=y(x), how can i get it?
calculator
@@unzelanoor8312 lmao
How do I do it without a calculator?
That is fairly complicated as it uses multivariable calculus. If you would like to see the formulas, you can DM me.
+dirk diggler Yeah. You can drop me an email at kamakwazee@gmail.com and I'll gather the formulas.
I found this document. It might help? www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=12&cad=rja&uact=8&ved=2ahUKEwjj07DHqIrgAhVUGDQIHQMuD_0QFjALegQIChAC&url=https%3A%2F%2Fwww.farmingdale.edu%2Ffaculty%2Fsheldon-gordon%2FRecentArticles%2Fquadratic-regression-equation.doc&usg=AOvVaw1SRqApHbBqiWcHmAWbKBym
edit: replaced typeo with "It" instead of "I"
great, I have a statistics tes ton this tomorrow, thanks.
how'd you do?
@TranceAddict2 nvm
u learn it in algbera 1
where can i get that calculator for my pc?
I know it's ten years and most likey you graduate but . . . . . Use Desmos it might help
XD skjsgfrfdgfd
how did u know that u were going to use quadratic regression.. why not linear or power3 regression.. anyone help please
Pratik Dhakal he knew that bc the height value went down and did not vonstantly go up (linear)
Also there is an analytical, theoretical solution for this, which we learned in our high schol physics class (back in the day), with aerodynamics (mainly drag) neglected and gravity being the sole influence changing the speed vector of the object (golf ball) once it is travelling. That analytical solution is quadratic.
If you know beforehand that the relation should be quadratic (or, very predominantly quadratic in real life), you should use quadratic regression as well.
@@optionsuniversum3528 To keep the time gap of these comments going boiiiiii
Ok, found out the theoretical height as a function of time in a vacuum:
-(1/2)g t^2 + Vy0 t
g= gravitational acceleration
Vy0= starting velocity in the y direction
And Vy0=40*sin(70)=37,6
h(t)=-4,9t^2+37,6t Voila!
We can solve for h=0 and get how long it takes before landing: t=7,67
Finding velocity in x direction (stays constant because the only force, gravity, works at an 90 angle): Vx=37,6
37,6m/s*7,67s=288m
That ball'll travel 300 meters in a vacuum!
I love MATHS!
yipeee
what grade math is Quad regression
5th
Math 2 9th
@@gwen-pc2mo bruh, that was 11 years ago. Definitely is not grade 9. I already taken grade 9 math even when I posted that comment.
what is the point of this?
Yeah I thought that we gonna learn how to calculate those coefficient, here it's just basic addition and multiplication
He forgot to enter 1.5 and 42.9
wow
he missed one input lololol
Venuhmz yeah I was like...wait what?
@purefatdude2
Year 11