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Not -jw it's -jw^3 because in the question it is given that (jw)^3 means j^2×j×w³ and we know that j²=-1. That's why sir has written -jw^3. Hope you understood 😊🙏
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Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
@@EngineeringFunda sure sir u are doing hard work. Please keep on providing quality and clear content. I have subscribed your cahnnel and will suggest my friends too to learn from here.
Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
4:38 pe sir calculation me mistake hai omega^3/omega hoga coz omega^2 jab sq root chodega to sirf omega bachega. Par ans fir bhi infinite hi aayega shyd so np.
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if i will score good in cs i will definitely share this in my group you doing good job dholakiyaaaaaaaaaaaaaaaa ji :P
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Thank you Sir. Very good explain polar plot.❤️❤️❤️❤️❤️❤️.
Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.
@@EngineeringFunda -jw^3 kyu liya sir in step 4
at 13:19 there is a calculation mistake, tan^-1(root(2)) = 54.7 not 60 it is root 2 not root 3
Exactly
yaa, you are correct the value of tan inverse of root 2 is wrong but the overall phase is 180.01 degree. The phase is correct.
You are correct
This video is really helpful for me.
Thank you sir for this video❤️
Love and happiness of students is my ultimate goal, God bless you 🙏, keep learning and keep progressing.
Best explaination !! Crystal clear✅
Your Appreciations, care and share matters a lot to me. #EnginneringLove.
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THank you so much fo rexplaing the steps as well as the reasoning behind it!!
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why's there -jw in the 4th step?
Not -jw it's -jw^3 because in the question it is given that (jw)^3 means j^2×j×w³ and we know that j²=-1. That's why sir has written -jw^3. Hope you understood 😊🙏
Thanks sir i have a few doubts regarding it but now you have answered it well. Thanks a lot 🙂👍👍👍
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Sir your contribution for us very helpful
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Sir is the negative sign necessary in step 4
Hard work sir🔥🔥🔥
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you are excellent teacher !!!!
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
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Bahut badiya sir♥️♥️♥️
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
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@@EngineeringFunda sure sir u are doing hard work. Please keep on providing quality and clear content. I have subscribed your cahnnel and will suggest my friends too to learn from here.
Your welcome 🙏
nice explanation!! Thanks Sir
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Sir can u pls explain where is - j in step two, how to write magnitude =w
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This is a gem
nice explanation sir
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
TQsm sir😍 for sharing
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12:33 why there is -3 is not considered for calculating magnitude and why there is 3 power of root 2
Wasn't there a mistake in step three? It was omega /2 so 90/2 so it has to be 270-90-45 right?
Omega isn't equal to 90⁰, omega is substituted to infinity.
So it's infinity ÷ 2 = infinity.
Tan-¹ infinity = 90⁰
Great sir
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Sir jcube = -1 . Question mai (jw)^3 diya hua hai. Then sir in step 4 , why have you taken -w^3 , it will be either -w3 or j^3 w^3
First thing jcube is not -1
it is -j
Because j=✓-1
J. J. J=J^2=-1 and J×-1=-J
@@sourabhkoshti978 chal na lawde ladki dekhi nhi ki gyaan chodna shuru..
@@Area-fd8ht so what are you doing basically
@@sourabhkoshti978 ha me bhi whi kar rha tha..
Gyaan hi bacha hi wese bhi chodne ke liye..😂
Thanks Sir 🙏
Most welcome
Thank u very much sir
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Sir the phase angle which you have taken of w^3 as 270 degree while finding polar form .how sir?
sir you did a mistake in step 4 you take -jw^3 where this negative sign come ?
Sir why have you written -jw cube in step 4 the sign should be positive?
I thought of It too
@@DamnSonImGood because there is a negative sign in a denominator which is taken to numerator 👍
As it is type 0 doesnt the graph start from the other side
4:38 pe sir calculation me mistake hai omega^3/omega hoga coz omega^2 jab sq root chodega to sirf omega bachega. Par ans fir bhi infinite hi aayega shyd so np.
It is correct dear
@@EngineeringFunda ohh yes sir I just noticed dono sq roots se ek ek omega niklega, sorry.
awesome...❤❤❤
Your welcome
Sir how you calculate w=√2 it's 3√2
where is the '-j' in the second step
Sir I have a doubt you wrote jw^3=jw^3=270 But sir Jw^3=-jw^3=-270
why you have taken w^2=2 as w=+root2 only? what about -root2
Sir how should we say direction of polar plot??
In step4 sir you have written -jw^3 but in question there is no (-) why did you kept that. Clear my doubt sir
In question it is (jw)^3 = j^3×w^3
Here j^2 = -1,
So (jw)^3 = -jw^3
Thanks sir😇
@@EngineeringFunda sir, some where I read j^2= -1.
Is it wrong sir?
@@vijayprakashee23gec-bhoj75 I have already said that J^2 = -1
@@EngineeringFunda sir at 1:47 how it is √1 + w² where j² = -1 please explain
hi sir,
when i calculated i got -0.66 and not 0.66
Sir , at intersection point if the magnitude is 0.66 , then why have u taken 0.66 point in left hand side of graph
You see the angle (phase) here, it is 180.
@@EngineeringFunda Ok Sir, Thank you very much for videos
@@EngineeringFunda sir but, w^2=2, so omega should be +- √2 right ??, Why did you take only √2?, Even w=-√2 could be taken
@@pranayjain._ frequency can not be negative
@@EngineeringFunda Thank you sir for your time ❤️
Sir solve the question
K/[s(1+jwT1)(1+jwT2)]
Plz sir solve the question 🤗
In my playlist of control engineering, I have explained polar plot for type 1 system, just go through it. This is that example only.
why only +ve root ??? why not w=-root2?
Sir , kindly explain the concept of polar plot and how it decides the stability
See it in playlist, I have already explained it.
how do we calculate that term using matlab
why 0.66 on negative real axis???
√2 kidhar se aaya
Why - sing sir in step 4. ???
In step 4 :-jw how it will come
Sorry to say but I couldn't understand a thing from step 4 and onward for past three videos that are type 0, type 1 and this.
There's "-" in 4rth step because he didn't write j^3 and wrote"- j"only he put j^2 = -1 and wrote only j
Step 2 is not clear as well as step 4..
Number of people are asking in the comments. No response from you...?!
I think you need to prepare well before explaining this topic....I think you are not clear about this topic..so dont repeat this again
No need of your advice
Jalwa😅😅😅@@Anonymous____________A721
Thank you Sir 🙏.
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