Thanks so much for saying. Your TA Indy is usually more of a "big picture" kinda kitty, but in this case of the Reynolds Transport Theorem, he's all about the details.
Yes, this is correct. It would have been better if I had explicitly written "uniform flow" in my assumptions section, since I was making that assumption here, which makes the integral trivial.
Your TA Indiana is just a regular kitty - no formal training at all - entirely self taught. For me - I was a nuclear power officer on submarines in the us navy. That was my first job after college. Nowadays, I have a phd in mechanical engineering, and I teach at Schreiner University in Kerrville, TX. Thanks so much for watching.
@@BrianBernardEngineering i would love some examples of an isentropic nozzle and its relation with static air temps at different points in the nozzle. How do the temps differ? especially, being isentropic (trick question?) Also, tie in the mach number at a specific point IN the nozzle. Want to see an example??
is right positive because you already determined a coordinate system with y axis positive upwards and x-axis positive to the right? Because when calculating over a tee pipe, you would determine the coordinatesys. another way?
Yes, I defined my xy coordinates positive Right and Up, default style. You could rotate these for a different problem where it makes sense, my choice was convenient, but ultimately arbitrary.
It's usually the difference in pressure that actually matters. Pressure inside something pushes outward, atmospheric pressure pushes inward. The difference is important since you are summing forces in the two different directions to get a net force due to gauge pressure. This is why you don't actually measure atmospheric pressure usually. Atmospheric pressures changes a bit everyday due to weather. Since we only care about the gauge pressure, it doesn't matter exactly what the reference points absolute pressure is.
@@BrianBernardEngineering If the pressure at the outlet was Patm, would we consider it then? Since the cross sectional area at the outlet is different?
this was the BEST explanation I've ever seen. couldn't wrap my head around this topic, 13 min later and I'm 100 percent confident in it
awesome! have a great rest of your semester
A.M.A.Z.I.N.G video, love the enthusiasm and attention to each detail!
Thanks so much for saying. Your TA Indy is usually more of a "big picture" kinda kitty, but in this case of the Reynolds Transport Theorem, he's all about the details.
Thanks, I watched this during the exam
I hope your exam was open book / open internet. Otherwise you may want to keep that to yourself :P
@@BrianBernardEngineering yes of course haha
@@BrianBernardEngineering from CFD
one of the best explanation i have ever heard,thank you very much am humble 🙏
You are very welcome
This is such a well produced video, really should have more views!
That's very kind to say, thank you so much for watching.
@4:17 What if you have a nonuniform flow? You need to include the integration over the control surface.
Yes, this is correct. It would have been better if I had explicitly written "uniform flow" in my assumptions section, since I was making that assumption here, which makes the integral trivial.
Ive been an engineer for about 3 years now, absolutely love it. Best explanation I've come across... what is your background?
Your TA Indiana is just a regular kitty - no formal training at all - entirely self taught. For me - I was a nuclear power officer on submarines in the us navy. That was my first job after college. Nowadays, I have a phd in mechanical engineering, and I teach at Schreiner University in Kerrville, TX. Thanks so much for watching.
@@BrianBernardEngineering i would love some examples of an isentropic nozzle and its relation with static air temps at different points in the nozzle. How do the temps differ? especially, being isentropic (trick question?) Also, tie in the mach number at a specific point IN the nozzle. Want to see an example??
is right positive because you already determined a coordinate system with y axis positive upwards and x-axis positive to the right? Because when calculating over a tee pipe, you would determine the coordinatesys. another way?
Yes, I defined my xy coordinates positive Right and Up, default style. You could rotate these for a different problem where it makes sense, my choice was convenient, but ultimately arbitrary.
If the pressure at the outlet was Patm, would we consider it then? Since the cross sectional area at the outlet is different?
I would almost always recommend working in terms of gage pressure, which makes Patm = 0, and can be ignored.
Why do we use gauge pressure? And not the abs
It's usually the difference in pressure that actually matters. Pressure inside something pushes outward, atmospheric pressure pushes inward. The difference is important since you are summing forces in the two different directions to get a net force due to gauge pressure. This is why you don't actually measure atmospheric pressure usually. Atmospheric pressures changes a bit everyday due to weather. Since we only care about the gauge pressure, it doesn't matter exactly what the reference points absolute pressure is.
@@BrianBernardEngineering If the pressure at the outlet was Patm, would we consider it then? Since the cross sectional area at the outlet is different?