solving a trig equation with the double angle identity (hard one)
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- Опубліковано 3 жов 2024
- Here's a hard trigonometric equation for students who are taking trig or precalculus. We will solve cos(2theta)+6sin^2(theta)=4 (i.e. solve cos(2x)+6sin^2(x)=4) on the interval 0 to 2pi. How do we get all the solutions of a trig equation? This math tutorial will help you be good at solving trig equations!
#precalculus #trigonometry #blackpenredpen
I had pretty good teachers of analysis and trigonometry which were my best subjects in maths, yet I can't help wishing I'd had you instead :) I'm 70 years old and use very little maths nowadays but I love watching your videos. I'd love to see something about complex analsysis (although maybe I just haven't encountered those videos yet).
Hi David.
Thank you very much for your comment. I am extremely happy nowadays because people are watching my videos and find them helpful/entertaining.
bprp
I would have done (sin θ)^2=(1 - cos 2θ)/2 instead of dealing with squares
This is apparently the easiest question I ever seen here
This is a question that can come in class 10th board/pre-board lol
cos(2theta)+3(1-cos(2theta))=4
cos(2theta)+3-3cos(2theta)=4
-2cos(2theta)=1
cos(2theta) = -1/2
2theta = 2/3pi+2kpi
2theta = 4/3pi+2kpi
theta = pi/3 + kpi k in Z
theta = 2pi/3 + kpi k in Z
At last, I managed to solve something correctly LOL
your awesome , wish you were my teacher right now hahaha
Corey Shimashuka thanks
thanks for your help!
Why don't you just use the formulae for that?
If sinx=sin(theta)
Then x= n(pi)+-(1)^n(theta) where n belongs to Z
And formulae for others are there too ?¿??
He was just trying to show different things...I guess
Thank you for the background music.
thankyou so much
i appreciate you.
How can I solve:
sin(2 theta) =0.998
What is theta?
Does it matter which one you use for cos2theta?
I know its been a year but yes it matters, you want to completely remove cos(x) terms and keep sin(x) to turn the equation into a simple quadratic, so you use cos(2x)=1-2sin^2(x)
But you could then have solutions like 7π/3 etc. It would be neater to express the solutions as an infinite set defined parametrically.
He defined the solution to be between 0 and 2pi from the start in order not to worry ab this.
Чё так долго это решал, уравнение же легкое
+2kphi k integre
you are amazing
thanks
Cool video