[CFD] The Energy Equation for Solids and Fluids in CFD

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  • Опубліковано 22 січ 2025

КОМЕНТАРІ • 53

  • @akshayghorpade8624
    @akshayghorpade8624 9 місяців тому +2

    Thank you Dr. Aidan wimshurst
    Your lectures help a lot in developing solvers of openFoam. The kind of explanation you give is remarkable.
    Thank you for making our lives easy by covering these topics in so much detail.🎉

  • @sreekar443
    @sreekar443 5 років тому +14

    So far well-explained mate. My friend suggested me this vid.
    Guess I 'll forward it to the whole class.

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +5

      Thats fantastic! Yes definitely forward it to the class if you think they will find it useful

  • @zaidrehman21
    @zaidrehman21 4 роки тому +1

    Best playlist I found till now... Concise 👌🏼👍🏼👏🏼

  • @pavelmaksimov3850
    @pavelmaksimov3850 4 роки тому +2

    This is absolutely brilliant!

  • @Pakhavar
    @Pakhavar 4 роки тому +1

    Thank you man. Stay safe and blessed.

  • @gagank9199
    @gagank9199 Рік тому

    @19:58 in the video -why are we neglecting kinetic and potential terms for the incompressible flows? (I don't think they are negligible terms)

  • @Thonix94
    @Thonix94 3 роки тому +3

    is there a divergent missing in eqn 13?

  • @MrDuonghuong1991
    @MrDuonghuong1991 4 роки тому +8

    Thanks for the videos, can you make some videos about chemical reactions and combustion??

  • @yongtuition
    @yongtuition 3 роки тому +2

    Have you made any video on how to incorporate radiation into CFD? Such as a radiative-convection model. Thanks.

    • @fluidmechanics101
      @fluidmechanics101  3 роки тому

      Yes! Check out the Surface to Surface radiation model video or the discrete ordinates model video ☺️

  • @rafaortwein6646
    @rafaortwein6646 5 місяців тому +1

    Super useful.

  • @ahmedx89
    @ahmedx89 2 роки тому +1

    thank you for this amazing lecture

  • @scientium8770
    @scientium8770 6 місяців тому +2

    Hey Aidan, Thank You very much for this amazing lecture!!
    I had a doubt... Isn't internal energy equal to "c_v * T" rather than "c_p * T", which is instead for enthalpy??
    Then why are we using "c_p * T" for internal energy here??
    If anyone can help, please do...

  • @idreeskhan1629
    @idreeskhan1629 5 років тому +1

    i'm confused sir in OpenFoam user Guide when the are writing dive discritization schemes how they (page123-124 version 7) take.first please explaine what is the difference b/w advection, convection , diffusion Laplacian.and which one term represent which one ( advection, convection , diffusion Laplacian,) in naviar stocks equation.

    • @fluidmechanics101
      @fluidmechanics101  5 років тому

      If you have a watch of my video ‘the finite volume method in CFD’ that should help you understand a lot better 😊 alternatively, you can check out my fundamentals course on my website, which will explain everything to you from first principles! Check it out: www.fluidmechanics101.com/shop

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +1

      Sorry got the url wrong! www.fluidmechanics101.com/pages/shop.html

  • @bi_block_inbleau4105
    @bi_block_inbleau4105 2 роки тому

    for the 20/23 page, where is the terme -grad(Up) at the left of the =?

  • @alejandropiquero5193
    @alejandropiquero5193 5 років тому +3

    Hi Aidan! First of all, I would like to say thank you for all the incredible effort you are putting into this channel and all the useful material provided. Hands down one of the best resources out there for anyone starting out with CFD like myself.
    One question arises from my side after watching the video: say you are modelling a liquid flow in which you are accounting for the temperature dependence of its properties (density, viscosity, thermal conductivity and specific heat). What would be the energy equation to be used here according to you?
    Despite being a liquid per definition an "incompressible fluid", if we follow a fluid parcel along its pathline in this context its density wouldn't be constant due to the temperature dependence (i.e. D(rho)/Dt =/0) ... so strictly speaking we would have a compressible flow (correct me if I'm wrong). Could we however neglect the variations in density with temperature (since these are much lower in comparison with those of a compressible fluid at high Mach numbers) and still assume an incompressible flow? (D(rho)/Dt = 0 --> divergence of U = 0).
    All the best,
    Alejandro

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +3

      Hi Alejandro, yes you are correct! you would want to use the full form of the energy equation (rho E) being inside the differential operators. This is the same formulation as the compressible formulation, even though the flow is not compressible. Really the full form can be thought of as ‘the form when density variations are significant’. If you are using ANSYS Fluent, you wont need to worry, as Fluent uses the full form by default. If you are using OpenFOAM I would choose your solver carefully. If you are using CFX, i would choose the ‘total energy’ form of the equation.
      To be honest, using the full form wont slow down the solution that much and you wont have to worry about incorrect modelling or missing a term! Better to be safe than sorry i think 😊

    • @alejandropiquero5193
      @alejandropiquero5193 5 років тому

      @@fluidmechanics101 Got it! Thank you for the quick response Aidan! Keep up the good work and definitely looking forward to seeing more from your content.

    • @javierconesa1952
      @javierconesa1952 3 роки тому

      Hi Aidan! Thanks a lot for all the videos you make, they are such an incredible help for us!
      In this case, in which Fluent solves the full energy equation, how is the conduction term treated? Since the specific heat depends on the temperature, the relation between T and e is not proportional.
      So, is the heat flux treated as a source term when Fluent solves the energy equation, computed from a suposed value of T? So then, once the value of e is obtained, the value of T is updated and Fluent recalculates the equation with this new value. Or would it be possible to solve the energy equation in terms of T?
      Thanks!

  • @mostafaelshafie6889
    @mostafaelshafie6889 3 роки тому +1

    Thanks, sir. How can I define buoyancy force in COMSOL?

  • @idreeskhan1629
    @idreeskhan1629 5 років тому +1

    sir i,m confused what is the difference b/w trnsport equation and naviar stockes equation.plz explane in detail

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +6

      Navier-Stokes equations are transport equations for momentum. Transport equations are a general type of equation that describe the transport of a physical quantity (temperature, momentum, turbulence) through a physical space. I hope this makes a bit more sense now!

  • @ahmedbalushi5161
    @ahmedbalushi5161 3 роки тому

    Hi, if I have a solid bar surrounded with gas and the gas only flowing due to the natural convection around the bar and i want to find the temperature gradient across bar cross-section. What i need to do in CFD models? Is same concept explained here to be followed? In ansys fluent possible?

    • @fluidmechanics101
      @fluidmechanics101  3 роки тому

      Yes it is possible. You will need to set this up as a Conjugate Heat Transfer calculation in ANSYS Fluent (mesh the solid and the fluid). Maybe send ANSYS support an email to help you get started?

  • @ramkumars2329
    @ramkumars2329 4 роки тому +1

    hi. it is a well explained talk.. thank you!.. by the way, i wrote few codes for solving incompressible flows and would like to go for compressible one.. could u plz make a talk that shows on how to solve for compressible flow field, algorithm used etc..?..

  • @abhayminachi6020
    @abhayminachi6020 Рік тому +1

    Bro Your videos are too good🙌🙌🙌🙌.
    Please make a video on pressure based and density-based solver.

  • @engineeringarts4509
    @engineeringarts4509 4 роки тому

    Thanks Dr. Aidan for your sharing.
    According to the 1st thermodynamics law, dQ = dU + dW, where U is the internal energy of the system. In yr eq 1, the heat flux is balanced out the internal energy of the system but the works done by the system to resist the fluid motion is NOT included. May I know if I misunderstood it?
    Thanks.

    • @fluidmechanics101
      @fluidmechanics101  4 роки тому

      Yes, this was a slight error in the talk which i have not had time to correct yet. Well spotted 👍

    • @engineeringarts4509
      @engineeringarts4509 4 роки тому +1

      @@fluidmechanics101 Thanks for your reply, Dr. Aidan. I like yr channel!

  • @knnfatima9
    @knnfatima9 5 років тому +1

    Brilliant

  • @nikan4now
    @nikan4now 4 роки тому

    Good work but two important things: 1. The first equation needs to incorporation the contribution of work 2. e=CvT (not Cp) and ONLY for callorifically perfect gasses

  • @goodday276
    @goodday276 4 роки тому +1

    Tnx for good tutorials
    Aidan what software do you use for drawing the pictures and writing the formulas?

    • @fluidmechanics101
      @fluidmechanics101  4 роки тому +2

      I make all the pictures in inkscape and make the equations in latexit. Once you have made the equations as vector images (pdf) you can insert them into your pictures in inkscape so that the fonts match 👍 all the software is open source so you can use it yourself

    • @goodday276
      @goodday276 4 роки тому +1

      @@fluidmechanics101 thank U so much my friend

  • @shuchang769
    @shuchang769 6 років тому +2

    Hi, is there any problem with eq. 2? I think it should be e=CvT and h=CpT. Thanks for the videos. It helps a lot.

    • @fluidmechanics101
      @fluidmechanics101  6 років тому +3

      Ah yes! Well spotted. This is a typo. It should be e = cvT. The reason for the confusion is that cp and cv are practically identical for liquids. Hence, we only really use the energy equation in terms of temperature when we have an incompressible liquid flow, say water. However, for gases, we use the energy equation in the form of e or h (if incompressible) or total energy (if compressible), so this typo shouldnt make a difference and the later equations still stand. I will correct the first few slides and upload a part 2 video! Thanks for spotting the error!

    • @shuchang769
      @shuchang769 6 років тому +1

      @@fluidmechanics101 Thanks, this makes it more clear, and it did not affect the derivation after. Will you cover some about species transport equations? It also have several assumptions and different versions. Your videos always make things clear. Really like them.

    • @fluidmechanics101
      @fluidmechanics101  6 років тому +3

      Yes definitely. Species transport can be confusing, especially with some codes using volume fraction, others using mass fraction. Im going to take some time and pull together the best video i can for everyone, as it is definitely a confusing topic :)

  • @mohammedouallal2
    @mohammedouallal2 3 роки тому +2

    Enthalpy = Cp.T
    Enthalpy (Tolal energy) = kinetic + internal + potential

  • @idreeskhan1629
    @idreeskhan1629 5 років тому

    Fluid Mechanics 101 Thanks sir, other what is the difference b/w advection term and diffusion term in momentum equation?

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +2

      The advection term in the momentum equations is non linear, as it contains UU (velocity squared). The diffusion term is linear and contains the stabilising effect of viscosity 👍 there are many differences but these are the main ones

    • @idreeskhan1629
      @idreeskhan1629 5 років тому

      @@fluidmechanics101 but sir what is the difference between advection and convection

  • @srijithms1
    @srijithms1 4 роки тому

    But combustion model non pre-mixed, pressure based solver in supersonic flow is used..It's compressible flow !!

  • @jungtaemin1639
    @jungtaemin1639 7 місяців тому

    Shouldn't the inernal energy be e = Cv * T? Cp * T is the enthalpy

    • @fluidmechanics101
      @fluidmechanics101  7 місяців тому

      Yes you are right. This is a very old video and hopefully I will redo it one day!

  • @ninesstea3215
    @ninesstea3215 5 років тому

    Hello Aidan, thank you so much for the explanation! I just have one question: how to get from equation 13 to 14? I try to do the dot product (along with a funny integration-like business *facepalm*) but I do not reach the expression in 14.

    • @fluidmechanics101
      @fluidmechanics101  5 років тому +1

      Yes, this is quite tricky! Start by taking the dot product of the entire equation with U. Then use equation 12 to simplify and try and get K inside the brackets. Only the terms on the left hand side simplify. The right hand side terms just stay as the dot product 😊

    • @ninesstea3215
      @ninesstea3215 5 років тому

      Ooh, I see. Thanks!