Poisson Distribution | Mean and Variance | Statistics and Probability | By GP Sir

[@rakshitkhandelwal8497]

Sir your Statistics and Probability series is awesome

[@durgeshanand6774]

12:42 sir q2 mei prove krna h exp[ lambda ( 1 - e^-k ) ] and aapka aaya h exp[ lambda ( e^-k -1 ) ] .....sahi konsa h?

[@suryansh1308]

Option D 0.0872 is correct
Btw my answer is 0.0860 approximately

[@RaoNaeem-g4h]

Sir kindly Start functional analysis

[@Jagrit_Khurana]

sir d is the correct ans.

[@Nainagour-l1h]

Option b is correct sir

[@Monukumar-yi9nb]

0.0872 is a correct answer
0.086 (approx) = 0.0872

[@prashantgautam9975]

🔥🔥

[@arunkoli1059]

Option (B)

[@arunkoli1059]

P=7/1000,n=400,np=2.8

[@skcareater1277]

Required 480p for clear understanding. 🙏 Thanks

[@OK-ku8ez]

x aur lambda me fark karo sir

[@_s_9694]

Q2 main hua Kiya bhai😂

[@indoserver9109]

OPTION D IS CORRECT

[@manik.imtiaz]

D

[@OK-ku8ez]

writing sudhar lo sir.