Q8.ans 45 +30=75 300/75=4 so, 30×4=120 first station and 45×4 =180 second station so, that the first station will the two trains meet =120km etu right ne sir 😊
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20m/sec সুষম গতিবেগত চলি থকা 100m দৈৰ্ঘ্যৰ এখন ৰেলগাড়ী 1km দৈৰ্ঘ্যৰ এখন দলং পাৰ হওতে ৰেলগাড়ী খনৰ প্ৰয়োজন কিমান সময় , sir short trick t answer tu kenekua hbo
A train leaves jorhat at 5AM and reaches Ghy at 11AM another train leaves Ghy at 5.30 AM and reaches jorhat at 11.30 AM what time the two trains cross each other Sir please question 2 kori dbo
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Q8.ans 45 +30=75
300/75=4
so, 30×4=120 first station
and 45×4 =180 second station
so, that the first station will the two trains meet =120km
etu right ne sir 😊
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20m/sec সুষম গতিবেগত চলি থকা 100m দৈৰ্ঘ্যৰ এখন ৰেলগাড়ী 1km দৈৰ্ঘ্যৰ এখন দলং পাৰ হওতে ৰেলগাড়ী খনৰ প্ৰয়োজন কিমান সময় , sir short trick t answer tu kenekua hbo
100m+1km=1100m×1sec/20m=55sec
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A train leaves jorhat at 5AM and reaches Ghy at 11AM another train leaves Ghy at 5.30 AM and reaches jorhat at 11.30 AM what time the two trains cross each other
Sir please question 2 kori dbo
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