Ratio Test Proof

Поділитися
Вставка
  • Опубліковано 4 лют 2025

КОМЕНТАРІ • 15

  • @jonasdaverio9369
    @jonasdaverio9369 3 роки тому +3

    Haha, nice to see the uncut bug at 4:03. I'm happy to see that proof, I've wondered for quite some time how it could be proved.

  • @johnholme783
    @johnholme783 11 місяців тому

    Crystal clear! Thank you!

  • @Test-zd4mp
    @Test-zd4mp 3 роки тому +2

    Cool, I hadn‘t seen this particular proof before. Do you have a video on the inequalities with ratios and roots used in the proof?

    • @drpeyam
      @drpeyam  3 роки тому +1

      Yeah the video is called the pre ratio test

  • @camonophy
    @camonophy 3 роки тому +2

    I am not really good at math, but it is really impressive and cool to watch anyway

  • @Julie-ih9du
    @Julie-ih9du 3 роки тому

    It's amazing
    Thanks for uploading this video.....really useful for my exam💯 thanks a lot

  • @clementeromano5691
    @clementeromano5691 3 роки тому +1

    This proof is very similar to that of Rudin's Principles of mathematical analysis, and it is the same for some others of your videos. Are you taking these proofs from that book?

    • @clementeromano5691
      @clementeromano5691 3 роки тому +1

      Also there's a condition that you haven't said in the video : the sequence a_n has to be, from a certain number N on, non-zero, otherwise it's not realy clear what is meant by the limit of the ratio, because some ratios doesn't exist (cause you are dividing by zero)

    • @drpeyam
      @drpeyam  3 роки тому +1

      Took it from Ross

    • @yichen8884
      @yichen8884 2 роки тому

      @@clementeromano5691 I wonder if, in the case of a_n becoming zeros after some N, the series converges automatically, as the sum is adding 0.

    • @clementeromano5691
      @clementeromano5691 2 роки тому

      @@yichen8884 Yes, but think about what happens in the case a_n = 0 if 3 divides n, a_n = n if n divided by 0 has remainder 1 and a_n = n^2 if n divided by 0 has remainder 2 ( the sequence goes like 0,1,2^2,0,4,5^2,0,7,8^2, ... ). This sequence has infinitely many zeros and it doesn't even converge. What happens to |a_{n+1}| / | a_n | when n tends to infinity?

  • @dgrandlapinblanc
    @dgrandlapinblanc 2 роки тому

    Ok. Thanks.

  • @marshal4408
    @marshal4408 3 роки тому +1

    Hello sir