Thank you sir...it's a very usefull clip.. Can you please explain activity and fugacity... As well as derive gibbs - helmholtz equation.... I have finished my syllabus expect these two..
Hello sir... I do not understand how you equated Pext = P... As I understand it, the external pressure cannot be equal to the internal pressure, unless the process is reversible... Is there something more to it? Would you be so kind as to point that out, or correct me if I am wrong? Thank you.
Hey Romaisa, this really depends on the conventions of the book your using that should be established for the first law of thermodynamics. In my convention (and common in physical chemistry) work done by the system is negative and work done on the system is positive. So we write the first law as dU = dQ+dW, other books flip this convention for the work and thus write the first law of thermo as dU = dQ+dW. So your book must be using the opposite convention. I know it can be confusing when comparing different sources but both equations are valid with respect to the proper conventions for the work.
Sir, you saved my thermodynamics grade, I'm so glad to see your channel. THANK YOU SO MUCH
Brilliant 10/10
wish I had you teaching me thermodynamics back in my college years
Thank you !! Now I understand the relation between Cp and Enthalpy. This is helping me solve an evaporation system in ChemEng
Glad you found the video useful Gary! Good luck in your studies.
Nicely explained! Thanks for your videos. Glad I found them
Thank you sir...it's a very usefull clip..
Can you please explain activity and fugacity... As well as derive gibbs - helmholtz equation.... I have finished my syllabus expect these two..
Hello sir... I do not understand how you equated Pext = P...
As I understand it, the external pressure cannot be equal to the internal pressure, unless the process is reversible...
Is there something more to it?
Would you be so kind as to point that out, or correct me if I am wrong?
Thank you.
💓💓💓
But sir in our book it's dQ=dU+dW
And you told that it's dQ=dU-dW..
Hey Romaisa, this really depends on the conventions of the book your using that should be established for the first law of thermodynamics. In my convention (and common in physical chemistry) work done by the system is negative and work done on the system is positive. So we write the first law as dU = dQ+dW, other books flip this convention for the work and thus write the first law of thermo as dU = dQ+dW. So your book must be using the opposite convention. I know it can be confusing when comparing different sources but both equations are valid with respect to the proper conventions for the work.