Great method - easier than the suspension method i was taught! So useful to do this to determine the exact amount of gold i have in a rock containing only gold and quartz, as the rock's specific density will be a ratio of the gold and quartz's specific density.
the water weight is often too heavy for many jewel scales, because your goal is just to get the weight difference of the rock in air and in water, you do not need to put water container on the scale. You need to smartly use the jewel scale in a "spring scale" way. that is, you need to hang the rock to the scale. To do this, move water container to underneath the scale, use a metal hook to hook on the center of the scale, the hook's lower end will be right underneath the scale so that you can hang the rock on it to merge into water container (if you form the wire a heart shape, you put the scale in the heart, that's it). How to make water container go under the scale? of course, you can use your hand palm to hold the scale above the water (I use a 2"x3" x 2' long wood beam to hang out of table)
to me this looks like black magic. how does the scale register the weight if the object is suspended bo something outside the scale? does the string itself interfere with the reading?
@DrDirtSoilVideos So doesn't the string itself effect the results? I've seen people use these types of wire cages and they make sure and tar it with the wire cage first to be more percise. Am I correct in assuming the string itself is so small that the difference in results would be almost negligible?
You can use it on any nonporous item. In the case of items that float, you would have to make sure the item remained completely submerged, e.g., hold it under rather than hold it off the bottom. Use an object of negligible volume relative to the potato to hold it under, e.g., something that displaces almost no water.
The suspending method is a water displacement method. In this method, the mass of the water is used to identify the volume of water displaced - more precise measurement than a graduated cylinder. However, if the object (rock or otherwise) touches the bottom of the container, the mass then is the mass of the rock plus the mass of the water, rather than the mass of the water plus the volume of water displaced by the rock.
@@LANDSHARKK because to lift the stone there is 2 components, him pulling the string and the water aplying pressure to the bottom of the rock. And we know that force cant just go in one direction so the neutral force from the water gets applied to the scale in turn showing the weight. Just a guess.
The rock displaces a volume of water = to its volume. Notice the volume of water in the container appears to increase, the volume of the water plus the rock. The mass of the water increases an amount equal to the volume of the rock. See this video about Archimedes, the first to express the principle of displacement. ua-cam.com/video/KMNwXUCXLdk/v-deo.html
The rock displaces a volume of water = to its volume. Notice the volume of water in the container appears to increase, the volume of the water plus the rock. The mass of the water increases an amount equal to the volume of the rock. See this video about Archimedes, the first to express the principle of displacement. ua-cam.com/video/KMNwXUCXLdk/v-deo.html
However, particle density is not. Specific gravity is essentially the particle density divided by the density of water, resulting in a dimensionless number.
Watched it twice to thoroughly understand this concept and now it's ingrained in my head. Thank you good sir.
Great method - easier than the suspension method i was taught!
So useful to do this to determine the exact amount of gold i have in a rock containing only gold and quartz, as the rock's specific density will be a ratio of the gold and quartz's specific density.
OMG I was struggling with measurement of stones that do not fit into graduated cylinder for so long. This is awesome, thank you!
That was clear, concise, and wonderful to follow. Thank You!
Thank you so much! I was able to identify a cool rock that is not valuable, but very sentimental. Thanks for clear explanation!
the water weight is often too heavy for many jewel scales, because your goal is just to get the weight difference of the rock in air and in water, you do not need to put water container on the scale. You need to smartly use the jewel scale in a "spring scale" way. that is, you need to hang the rock to the scale. To do this, move water container to underneath the scale, use a metal hook to hook on the center of the scale, the hook's lower end will be right underneath the scale so that you can hang the rock on it to merge into water container (if you form the wire a heart shape, you put the scale in the heart, that's it). How to make water container go under the scale? of course, you can use your hand palm to hold the scale above the water (I use a 2"x3" x 2' long wood beam to hang out of table)
Who what now?
Amazing video, very clear information. Can’t remember we did much calculation with this method on high school sadly.
But what is the prove that the weight of the mass in water equal to the the volume?
I think He used pure water, With an SG of 1
Thanks that's a cool tip!
I guess the strings influence on displacement is negligible?
Thanks alot, solved it for me by hanging thread👍🏻
simple and nice
Very clear thanks.sir.
What is this norm ..ASTM ....¿?
Standard methods will be more detailed, possibly requiring a controlled temperature (20 C), and using more sophisticated equipment.
whats the units of measurement for its spesific weight ?
how to calculate porosity of fiber reinforced polymer composite
Nice one
Great! Thanks.
Simple and effective video.
Can I use this method to find the density of wood that floats?
Good method
to me this looks like black magic. how does the scale register the weight if the object is suspended bo something outside the scale? does the string itself interfere with the reading?
finally clear sir thanks
Hello.thank you for sharing this clip .i have a question , dose this method work for a small rough or gem? .i mean around one or 2 carats ?thanks
It should work well.
whats the name of this watch
@DrDirtSoilVideos So doesn't the string itself effect the results? I've seen people use these types of wire cages and they make sure and tar it with the wire cage first to be more percise. Am I correct in assuming the string itself is so small that the difference in results would be almost negligible?
The string itself is essentially negligible. A standard method would use more sophisticated equipment.
can I use this method to determine the specific gravity of potatoes
You can use it on any nonporous item. In the case of items that float, you would have to make sure the item remained completely submerged, e.g., hold it under rather than hold it off the bottom. Use an object of negligible volume relative to the potato to hold it under, e.g., something that displaces almost no water.
Vol. Of water?
i think water displacement method gives us better result then suspending method. Almost all the mineral gives a sg value around 2.5 to 2.9
trigger ongole .
Almost all are not between 2.5 to 2.9.
The suspending method is a water displacement method. In this method, the mass of the water is used to identify the volume of water displaced - more precise measurement than a graduated cylinder.
However, if the object (rock or otherwise) touches the bottom of the container, the mass then is the mass of the rock plus the mass of the water, rather than the mass of the water plus the volume of water displaced by the rock.
The specific gravity of minerals likely found in soil varies greatly, from about 1.5 (feldspars) to more than 5 (hematite) g/cm^3.
it is not understood how your scale directly gave the weight=volume of displaced water=volume of suspended object. Is the scale has anything special?
Nirmalya Biswas I can wrap my head around that either. How does displacing the water add weight?
@@LANDSHARKK because to lift the stone there is 2 components, him pulling the string and the water aplying pressure to the bottom of the rock. And we know that force cant just go in one direction so the neutral force from the water gets applied to the scale in turn showing the weight. Just a guess.
30slak 🤷🏼♂️
The rock displaces a volume of water = to its volume. Notice the volume of water in the container appears to increase, the volume of the water plus the rock. The mass of the water increases an amount equal to the volume of the rock. See this video about Archimedes, the first to express the principle of displacement.
ua-cam.com/video/KMNwXUCXLdk/v-deo.html
The rock displaces a volume of water = to its volume. Notice the volume of water in the container appears to increase, the volume of the water plus the rock. The mass of the water increases an amount equal to the volume of the rock. See this video about Archimedes, the first to express the principle of displacement.
ua-cam.com/video/KMNwXUCXLdk/v-deo.html
So Desnsity is exactly specific gravity, they are all the same am I right?
Density = mass ÷ volume.
No. Specific gravity has no unit. He multiply the density of water which is 1 g/cc with the specific gravity of the solid
why bother using cubic centimeters??? just get the dry weight of the object then divide by the water displacement weight.
Thanks
this totaly wrong.. Your stone 36.2 and u are put in water it is coming 14 that is impossible.. you are hold stone weight
Specific gravity is unitless.
However, particle density is not. Specific gravity is essentially the particle density divided by the density of water, resulting in a dimensionless number.
brother saya memiliki sebuah batu dan saya melakukan ukuran ke padatan sama seperti ini
36.5/(36.5-14.2)
Horrible, shaky, needs to be redone.