SOP and POS Form : Non Canonical to Canonical Form Conversion of Boolean Expression

[@ALLABOUTELECTRONICS]

Timestamps:
0:00 Introduction
0:37 Sum of Product Form: Non-Canonical to Canonical Form Conversion
3:00 Example 1
5:45 Example 2
7:43 Shortcut method for Non-Canonical SOP to Canonical form Conversion
9:52 Product of Sum Form: Non-Canonical to Canonical Form Conversion
12:35 Shortcut method for Non-Canonical POS to Canonical form Conversion
14:17 Example 3

[@ajiteshkumar5841]

You discuss all the topics in detail ,please upload remaining videos on digital electronics . I think the channel " All about electronics " and " neso academy " are the best channel in youtube for digital electronics. THANKS 👍👍👍

[@zarapkarajinkya4034]

Here from IITG , this channel is literally a gem❤

[@abubakarusman5298]

Thanks alot sir, you have really saved me, to be honest you are better than our professor. you deserve a big thumb

[@OKPB]

Thanks so much! I really appreciate the excellent work and effort you put in. I was struggling with these concepts but all your videos are saving me. Many blessings your way❤🙏

[@girikeshav1802]

One should always be proud of their work. I bow to you with great reverence

[@ajiteshkumar5841]

9:51 , Answer is
Canonical SOP form = Sigma ( 1,5,8,9,10,11,13 )
Canonical POS form = pi ( 0,2,3,4,6,7,12 ).

[@thesbeccompany7752]

wrong answer
corroct is
Canonical SOP = Sigma(3,7,11,12,13,14,15) ===(7 terms)
Canonical POS = Pie(0,1,2,4,5,6,7,8,9,10) ===(9 terms) ===(7+9==16 term it should be total 16 terms bcz of 1111)

[@bilaltariq2332]

correct ans but in POS form add 14 and 15 also

[@chiranjeevipathipati885]

at last pi (2 , 5 , 6 , 10 , 12 ,13 , 14 , 15)

[@foradfreeutube9528]

Best explanation !!! I have ever seen

[@creativeprojectsmaker6113]

I am getting answer for last question as:-
pie 2,5,6,10,12,13,14,15
sigma 0,1,3,4,7,8,9,11
All are getting different @ABOUT ELECTRONICS please provide correct answer

[@CodesNGames]

Same

[@ALLABOUTELECTRONICS]

Yes, That's correct answer.

[@-Tren_ding]

Correct answer👍👍

[@mayurshah9131]

Excellent as usual

[@poojashah6183]

Love ur videos 👌🏻👌🏻

[@vinayaksharma-ys3ip]

Best teacher

[@Imkids001]

Thankyou, sir 😊😊 it is really helpful video aase he video banete raheye.

[@sheikharooj5762]

Loved the explanation

[@UE_devlover]

Your understanding and explanation is to good sir 🫡

[@sivagopika9913]

Easy way to understand

[@adefisanadedotun797]

Much Appreciated Sir

[@gowrispaniker369]

well explained sir❤️❤️

[@rezwanaroza2981]

hi can you please show how to convert non canonical sop to minimum sop form?

[@이병석-k1z]

great lecture thanks!!

[@shubhisingh8474]

Thank you so much sir!!!❤️
It' become so easy to solve now and it's only because of you✨..

[@Okundanielaugustine]

Brilliant.
Thank you!

[@jk-sm6qr]

Brilliant sir

[@TarekMahmud-vc4cn]

love from bangladesh

[@tcv_sacred734]

Is there a mistake at 11:48? Isn't it A'CB' = m5, not m6?

[@tcv_sacred734]

nevermind, i mixed up the order of C and B'. m6 is correct

[@KrishnaJain-k2u]

@@tcv_sacred734 same

[@coreyhooker4064]

What was the solution for F3-- The do it yourself example.

[@onnumillasummathan2611]

Nice sir

[@siddhantsingh8721]

how can we just remove terms like that

[@ALLABOUTELECTRONICS]

Hi, would you please mention the timestamp where you are refering to in the video?

[@Abhishekkumar-wu3bz]

F= sigma 1,5,8,9,10,11,13

[@malik6939]

at around 5:20, how does he get the minterm numbers of m7, m5, m4, m6, m3?

[@ALLABOUTELECTRONICS]

m7 = ABC, meaning that both A, B and C are 1. (ABC = 111, in decimal that is 7)
Likewise, AB'C = 101, meaning that, the output is 1 when A = 1, B = 0 and C = 1 (101 in decimal is 5). So, it is minterm m5.
For more information, check the earlier video on SOP and POS form.
Here is the link: ua-cam.com/video/YmKmS9bpMqM/v-deo.htmlsi=gmAomYZdCaSvIHZL

[@b_34_asmitakatti84]

MISTAKE = 11:55 , it should be M5

[@ALLABOUTELECTRONICS]

For Maxterms, the assignment is different than minterms. For example, (A + B + C) corresponds to M0, while (A' + B' + C') corresponds to M7. Therefore, here this (A + B + C') corresponds to M0. And likewise you can find the remaining corresponding Maxterms.

[@vinayaksharma-ys3ip]

🙌🙌👍👍

[@user-ub2hb9rm7k]

12:00 the pos form answer is 0,1,4,5 but u have written 0,1,4,6

[@ALLABOUTELECTRONICS]

For Maxterms, the assignment is different than minterms. For example, (A + B + C) corresponds to M0, while (A' + B' + C') corresponds to M7. Therefore, here this (A + B + C') corresponds to M0. While, A' + C + B' = A' + B' +C corresponds to M6. I hope, it will clear your doubt.

[@Clutchgod-l9z]

you can find the m1 and m... by a easy method

[@omkar5587]

100th like 🥳

[@shaylasamara6605]

Are non-canonical form and standard form same thing?

[@ALLABOUTELECTRONICS]

Yes

[@dseekertv7191]

👍

[@Zzzzzzz._.]

11:45 why is it written in the form (A’+C+B) and not (A’+B+C). Is (A’+C+B) considered canonical even though C is written before B?

[@ALLABOUTELECTRONICS]

Both are same. You can write either way.

[@debmalyamukherjee233]

9:51 --- The answer is F = SIGMA(3,7,11,12,13,14,15) and F = Pi(0,1,2,4,5,6,8,9,10)???

[@Josuke217]

The shortcut method is not easy to grasp imo. The standard method is better

[@angelmoisesvalleanalco4503]

3:48

[@gaaraofddarkness]

First you should also explain what is canonical and non canonical clearly

[@millenjanclarkconsuegra4907]

please look at the previous video, the video before this.

[@duels6968]

I can barely understand what you're saying, sorry