SUMMATION PROBLEM JEE ADVANCED 2024 RELATED

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[@UltraFocused-zf8ow]

Thank you so much

[@VERSATILEMATHS]

You're most welcome

[@dhruvchaudhary5379]

£ tan inv ( 1/ ( n^2 + n +1) ) = taninv ( n+1) - taninv(n) telescopic series so solve to get = taninv(n+1) -pi/4

[@VERSATILEMATHS]

First how will you think the nth term. After this you will apply the concept of telescopic series. So please watch the full video. ❤❤❤

[@shivamrathore5502]

Correct ans is 12