It will not necessarily be the exact value as it is a line of best fit. However, I would expect an answer fairly close to the real one. Have you checked your values and is your observed value x within the lower and upper values that were in the original data table.
Hello, sir. If I am not mistaken, a graphic calculator is allowed in the Math Studies exam on both papers... Why not use the calculator to calculate the line of regression instead of using and applying all those formulas?
@xImMorTalxT That was not the point behind the video. I was trying to explain from first principles. Anyway, what if you don't have a calculator that can do regression?
Thanks a lot sir...This video was extremely helpful..S1 seems to trouble me a lot,,but after watching ur videos..I found it very easy..All the credit goes to u
An x on y graph would be used when x depends on y. For instance if x were the temperature of a cup of coffee and y the time. Then the temperature of the coffee would depend on the time it is sitting around. For y on x, y depends on x.
i came back here to thank you ,i passed the math exam because of you ..this is one of the only two type of exercise which ive done perfectly at the exam alll the others were half finished because i did not understand them very well,so it helped the overral grade a lot!lol..i wish you could do videos about random variables,probabilities,conditional probability,lagrange multiplier ,integrals or second derivative test
It depends on the question. The best way is to look at the exam questions on my website and watch the videos for S1 June 2010 6e and S1 Jan 2008 4c. However, this would make for a good video which I may do.
You Tube prevents me from placing a link here but if you go on my website check out the product moment coefficient in the statistics index or your exam module S1.
@ExamSolutions yeah i get where you're coming from. 1 question if there's a 4 mark question that asked to find equation of regression line if i simply put the values down because i worked it out from the calc would i get all the marks? or would i have to show some sort of working out??
Thank You Sir... I am looking for application of this method on 2 Dimensional matrices. Please tell me how can I use Least Square Method on 2D Matrices?
Evaluate the statement “In the model: y=a+bx+cz+e,if z=√x, where a, b and c are parameters to be estimated and e disturbance term satisfying classical assumptions then muliticolinearity couldn’t be a serious problem
@ExamSolutions Why wouldn't you just use a calculator?? It's soo much easier and faster. Would i ever need to use this method in a test if i know how to do it on a calc??
I have answered a question using this method. But have to interpret my answer. the answer is y= -0.49 +0.44x . But when i try to put the data I have for x, the answer does not match what the true y is! I.E with a voltage applied (y) of 15v the current (x) is 6ma. Using my answer to to check this, the y value does not come to this.
I don't understand how the sum of the squares of the residuals/errors has to do with the final answer, being the line of y on x. I don't see how they link if the sum of the squares of the errors doesn't get included in the calculations to find the line equation. And also, what if you don't find the lowest error thing, as there may be so many options you can have to put the best fit in, does that mean you get it all wrong?
You take the sum of square residuals (which for an individual is y-a-bx, so sum up that for all observations) and then differentiate to obtain two first order conditions with two unknowns and then solve the equations (for the most simple case, ofc you can generalise to as many regressors as you want) for your estimators. And then you'll see if you do that, for the case of a single regressor, you get b=Sxy/Sxx and a=y(bar)-bx(bar). So you mathematically solve for the values of a and b that minimise the squared residuals. This is above anything expected at A level and the maths of it can be quite intimidating at first but stick with it, I think its very very hard to intuitively understand least squares regression unless you know the derivation and understand how the estimates are obtained
Betuel Oliva Nonlinear You can still use the exact same method. Ordinary Least squares requires that the model is linear in the parameters, not the variables
Play his videos on 1.5x or 2x speed if you feel he's going too slow. The explanations are well worth listening to.
honestly, this is the best and only good explanation I've seen about the least squares
Daaave s1 next week Wednesday?
Devil's Den same, goodluck 😭
Devil's Den 😭😭👎👎. I found some questions doable but some 😭. How did you find it?
fantastic, really. you explained my whole chapter just in 14 mins. i now don't need to study that heavy book which indeed sucks. you are wonderful.
Never mind, I found it. Great videos, you are a life saver!
Best video on Linear Regression! Extremely helpful!
Thank you!
Thanks
That's good - well done.
All your videos has been great and explained in a simple manner. Thank you so much.
@Exam Solutions
this was extremely helpful! Thank you for creating this video!
It will not necessarily be the exact value as it is a line of best fit. However, I would expect an answer fairly close to the real one. Have you checked your values and is your observed value x within the lower and upper values that were in the original data table.
Thanks from the UK
Hello, sir. If I am not mistaken, a graphic calculator is allowed in the Math Studies exam on both papers... Why not use the calculator to calculate the line of regression instead of using and applying all those formulas?
@xImMorTalxT That was not the point behind the video. I was trying to explain from first principles. Anyway, what if you don't have a calculator that can do regression?
Thanks a lot sir...This video was extremely helpful..S1 seems to trouble me a lot,,but after watching ur videos..I found it very easy..All the credit goes to u
Best wishes to you.
Confused me in college, this helped a lot. Thanks!!
I really need more of this, this is very helpful
Thanks to u I went through 2 chapters in about 30 mins
An x on y graph would be used when x depends on y. For instance if x were the temperature of a cup of coffee and y the time. Then the temperature of the coffee would depend on the time it is sitting around. For y on x, y depends on x.
i came back here to thank you ,i passed the math exam because of you ..this is one of the only two type of exercise which ive done perfectly at the exam alll the others were half finished because i did not understand them very well,so it helped the overral grade a lot!lol..i wish you could do videos about random variables,probabilities,conditional probability,lagrange multiplier ,integrals or second derivative test
+natalie shinobi Well done for passing your maths exam.
It depends on the question. The best way is to look at the exam questions on my website and watch the videos for S1 June 2010 6e and S1 Jan 2008 4c. However, this would make for a good video which I may do.
Thank you very much!!! after reading book and watching this video, everything is clear!!! Even all those complicated equations ))
Sir, you're a saint.
@marymalu09 Pleased to hear that you found it useful
Cool - All the best
You Tube prevents me from placing a link here but if you go on my website check out the product moment coefficient in the statistics index or your exam module S1.
is introductory,let appreciate you
love your videos you explain it so simply
Simplified and to the point.
Thanks for the feedback.
@Madsblach Yes but in place of your 'a' it will be my 'b' and in place of your 'b' it will be my 'a'.
Thank for creating this video, make several video, this was exatily helpful
that was a really really good video! very clear and at a very good passe!
thanks :) really helped me out :)
So nice video and its fully helped me to understand this method. thanks again
Excellent coaching.Thanks for clearing my doubts.
M.V.Apparao, Hyderabad
Absolutely amazing tutorial! Thank you very much, a great help. :)
Great Video, well explained! :)
Greetings from Watford, UK
@AtoZyzzyva Yes, have you looked on my site.
very nice tutorial.. thank you.. was really helpful
You are a legend!
Great video for last minute revision, or should I say on the day learning?
Fabulous Teaching 👌
Thanks
@ExamSolutions thankkyouuu!!
What previous video do you refer to at 5:53, where you explain how to find b in y=a+bx?
thanks a lot sir!
IT REALLY HELPS
Super useful
Thank you
thank you!!! was very useful :)
great work, God bless you,
@ExamSolutions yeah i get where you're coming from. 1 question if there's a 4 mark question that asked to find equation of regression line if i simply put the values down because i worked it out from the calc would i get all the marks? or would i have to show some sort of working out??
@Madsblach yes
Hello. Great lesson
What software are you using to crate this lesson?
thank a lot...great clarity!
thanks sir love the way you explain. ndo livhuwa means thank you in venda.
Thanks.
Lol I love South Africans
Life saverrrr ❤️❤️❤️❤️❤️❤️
What does Sxy interprets?? You have said that you have explained it in previous class.. can you please post the link??
Cool - another life saved.
It was really helpful for me
Thanks for the good work. It is really helpful.
Thanks
Going International. Thanks
Excellent Explanation (y)
Excellent video
found it very useful
thats nice presentation
@SelasSolaris That's ok.
very good video!
Thank You Sir... I am looking for application of this method on 2 Dimensional matrices.
Please tell me how can I use Least Square Method on 2D Matrices?
@ExamSolutions Okay so it's basically the letter before the "x" that should be solved as you solve your "b"?
when would an x on y graph be used, and when would a y on x graph be used?
Hi Stuart,
I gave the final answers for the line in fractions.. is that still going to give me the marks?
Impressive!!
How did u get those formulas ? Derivations?
Evaluate the statement “In the model: y=a+bx+cz+e,if z=√x, where a, b and c are parameters to be estimated and e disturbance term satisfying classical assumptions then muliticolinearity couldn’t be a serious problem
@AtoZyzzyva Good - Hope it helps
You rock man
Yes
Good
How do you find the line of best fit without the trial and error?
Does this solution also work on y=ax+b?
Thank you so much Sir.
+Konark Raj Mishra You're welcome
Hi. How can I interpret the equation of regression?
@blockenfocken168 not at all.
thank you sir.
Thank you!
+Leona Asgarpour You're welcome.
@ExamSolutions Why wouldn't you just use a calculator?? It's soo much easier and faster. Would i ever need to use this method in a test if i know how to do it on a calc??
tks for tutorial!!!
+Dan Cacovean Thanks for looking at it.
You can use the calculator to do the line of regression but that was not the point of the tutorial.
hats off to u
MODE
STAT (2)
A+BX (2)
ENTER VALUES
AC
SHIFT
1 (Stat)
REG
A & B
-> AQA Question = 4 marks.
is the regression line affected by coding?
I have answered a question using this method. But have to interpret my answer. the answer is y= -0.49 +0.44x . But when i try to put the data I have for x, the answer does not match what the true y is! I.E with a voltage applied (y) of 15v the current (x) is 6ma. Using my answer to to check this, the y value does not come to this.
I don't understand how the sum of the squares of the residuals/errors has to do with the final answer, being the line of y on x. I don't see how they link if the sum of the squares of the errors doesn't get included in the calculations to find the line equation. And also, what if you don't find the lowest error thing, as there may be so many options you can have to put the best fit in, does that mean you get it all wrong?
You take the sum of square residuals (which for an individual is y-a-bx, so sum up that for all observations) and then differentiate to obtain two first order conditions with two unknowns and then solve the equations (for the most simple case, ofc you can generalise to as many regressors as you want) for your estimators. And then you'll see if you do that, for the case of a single regressor, you get b=Sxy/Sxx and a=y(bar)-bx(bar). So you mathematically solve for the values of a and b that minimise the squared residuals. This is above anything expected at A level and the maths of it can be quite intimidating at first but stick with it, I think its very very hard to intuitively understand least squares regression unless you know the derivation and understand how the estimates are obtained
Cool
Pleasure
How would you do a problem where the line isn't straight? The line they are asking me is y = a(√x) + b
Betuel Oliva Nonlinear You can still use the exact same method. Ordinary Least squares requires that the model is linear in the parameters, not the variables
my two thumbs up
Chouutauuu Nanuuuu....
I have now made a video on this for you. Check out your exam board module. I hope you find it useful.
MODE
COMP (1)
-> To reset your calculator back to normal.
@hamidbcu Pleasure
mba is costly in colleges . im doing distance education due to money constraint . i cant get this quality teachhing even if i do in regular college.