Understanding Common Mode Rejection Ratio

This video explains the common mode rejection ratio, or CMRR, and in particular why CMRR is an important figure of merit for differential voltage probes.
Learn more about R&S Oscilloscopes: rsna.us/60569SNWm
Discover more about R&S Oscilloscope Probes: rsna.us/60579SNWW
Timeline:
00:00 Introduction
00:19 Suggested viewing
00:34 About differential amplifiers
01:29 About common mode signals
02:10 About common mode rejection ratio (CMRR)
03:10 About CMRR values
04:03 About differential probes
05:24 Summary

[@Kenobiii]

I'm getting into RF engineering and your videos help me soooooo much to understand many of the concepts a lot better!!!! It's all explained so well and clear, thank you so much!

[@pauldenisowski]

Thank you! I sometimes tell people that I'm making the videos I wish that I had when I started in engineering :)

[@Floyd..B]

​@@pauldenisowski And you are doing a perfect job at that.

[@IcRDlayout]

真強你

[@stud_mechatronic_polito_22]

thank you, now it's clearer; I was getting crazy with that indian accent -_- but apart the indian accent "all about electonics" is a great yt channel.

[@nareshkumar4207]

Thanks for this good lecture

[@pauldenisowski]

Thanks for the feedback!

[@user-jc9kn4uy2u]

What I don't understand, is that if noise is present in both inputs of the OA, when you subtract them, you should see 0V. So i do not understand why it's amplified.

[@KingdomAddict]

Thank you for the lectures; they are very helpful, thank you. Question: Should Vout be Adm(V2-V1) instead of Adm(V1-V2) shown in the video?

[@pauldenisowski]

Yes - thank you for catching that. Vout is Adm * (Vplus - Vminus). In retrospect, I should have used Vplus an Vminus instead of V1 and V2. Thanks again for the correction!