@@radiationphysicsradiationb5460 my question is simple , when positive and negative voltage from rectifier fed to anode & cathode wt will be happen ? Do the cathode is connected to ground ? I know there will be points like s , l, c other than these there wont be any points . Wt I understood is the negative voltage is connected to ground at anode side and positive voltage is fed to anode will help to attract electrons from filament , correct me if i am wrong
Well if u want the basics. Anode is positive mean, anode is lacking electrons. Cathode is negative means cathode is having surplus electron. If Free ellectrons are placed between two electrodes and one of the electrode is positive other negative or ground level then electrons will move towards positive electrode. If anode is at ground and cathode at negative(surplus electrons) then also electrons will flow towards anode. Electrons will naturally flow towards less negatively charged plate . Or in otherwards towards more positive plate.
Ma'am you only say step up transformer high voltage circuit But you don't say step down transformer low voltage Please ma'am make a video of step down transformer And provide a diagram of step up and down transformer in one figure. By the way thank you ma'am ❤
Is simple bro step up has more coil turn in secondary winding, and it increases voltage(that's why called high voltage transformer) and decrease current and exact opposite is for step down transformer.
They did not error. Only partly, due to skipping an important feature. This Transformer has a center tap. Therefore, each secondary winding only has half of the voltage. Combined makes 72kv. But half is 36kv each side. There will be losses due to the core, so 32kv is a close estimate.
Excellent video please start making video again on further topics.
Excellent Subject you are provided
Thank you.
Good
Nice knowledge
ua-cam.com/video/-2iiPhCYHIg/v-deo.html
Where is flament transformer ?
9:58 👍
12:38
When anode is + charged mater and cathode is -ve charged matter why only electrons from filament is accelerated not from - ve side ??
Electrons are free inside xray tube, after thermionic emission. Filament is in _ve side only
@@radiationphysicsradiationb5460 my question is simple , when positive and negative voltage from rectifier fed to anode & cathode wt will be happen ? Do the cathode is connected to ground ? I know there will be points like s , l, c other than these there wont be any points . Wt I understood is the negative voltage is connected to ground at anode side and positive voltage is fed to anode will help to attract electrons from filament , correct me if i am wrong
Well if u want the basics. Anode is positive mean, anode is lacking electrons. Cathode is negative means cathode is having surplus electron. If Free ellectrons are placed between two electrodes and one of the electrode is positive other negative or ground level then electrons will move towards positive electrode. If anode is at ground and cathode at negative(surplus electrons) then also electrons will flow towards anode. Electrons will naturally flow towards less negatively charged plate . Or in otherwards towards more positive plate.
Ma'am you only say step up transformer high voltage circuit
But you don't say step down transformer low voltage
Please ma'am make a video of step down transformer
And provide a diagram of step up and down transformer in one figure.
By the way thank you ma'am ❤
Is simple bro step up has more coil turn in secondary winding, and it increases voltage(that's why called high voltage transformer) and decrease current and exact opposite is for step down transformer.
To the robot narrator: 180*400 = 32 kv. That does not compute!
Thanks for pointing out the calculation error. Hope the rest of content is useful to u.
They did not error.
Only partly, due to skipping an important feature.
This Transformer has a center tap.
Therefore, each secondary winding only has half of the voltage. Combined makes 72kv. But half is 36kv each side. There will be losses due to the core, so 32kv is a close estimate.