Solving An Exponential Equation for All Solutions

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  • Опубліковано 20 гру 2024

КОМЕНТАРІ • 38

  • @MisterPenguin42
    @MisterPenguin42 Рік тому +7

    My brain immediately changed the 1 to 3^0 and I had the real solutions. I wouldn't have been able to do that a month ago.
    As always, thank you for leveling up my math skills.

  • @gila168
    @gila168 Рік тому +13

    You made life too complex😅

  • @SimonClarkstone
    @SimonClarkstone Рік тому +1

    Are there no other branches of "ln 3" that we need to consider? How about other branches of the square root operation at the end?
    (I don't know how to tell if such things matter.)

  • @merizigramdane6238
    @merizigramdane6238 Рік тому +4

    0 and 2

  • @GrandAbeysinghe
    @GrandAbeysinghe Рік тому +2

    Since the exponent is equal to 1, there are three cases: power is 0, base is -1 and power is even, and base is 1. Since we know the base is 3, the only possible way to find the real solutions is to set the power to 0. We have x^2-2x=0, solve by factoring. x(x-2)=0 so the real solutions for x is x = 0, 2.

    • @selimcalskan9442
      @selimcalskan9442 Рік тому

      You're correct, but those are only the real solutions. The main purpose of this video is to find the complex solutions, since x²-2x=0 is the obvious solution and doesnt really make content for a whole video.

    • @flam3guin114
      @flam3guin114 Рік тому

      @@selimcalskan9442 but it’s a quadratic so isn’t there only 2 possible solutions ?

    • @selimcalskan9442
      @selimcalskan9442 Рік тому

      @@flam3guin114 its not a quadratic, its a nonstandard equation. You cant know x²-2x=0 because 0 is not the only value that makes 3^x equal to 1

  • @AKBARCLASSES
    @AKBARCLASSES Рік тому

    Maza aa gayaa 😂
    Translation: Had fun 😂

  • @scottleung9587
    @scottleung9587 Рік тому +1

    Nice - I got the same family of complex solutions. However, you forgot the real solutions: x=0 and x=2!

    • @l.w.paradis2108
      @l.w.paradis2108 Рік тому +1

      Those come up when you set n = 0 in the 2n(pi)i expression, which eliminates the imaginary part.

  • @vladimirrodriguez6382
    @vladimirrodriguez6382 Рік тому

    The complex solution to this exponential equation is obtained with complete precision, it is even indicated that when n=0 the only two trivial real solutions for the equation are obtained.

  • @l.w.paradis2108
    @l.w.paradis2108 Рік тому

    The real answers are immediate -- so the proof of your having found all real and complex solutions is really interesting.

  • @yttyw8531
    @yttyw8531 Рік тому +1

    Finding real solutions a lot easier

  • @Paul-222
    @Paul-222 Рік тому

    I accepted the challenge and set x = a + bi. The values for a and b are too long to try to type them here, but they are achievable within half a page of calculations.

    • @SyberMath
      @SyberMath  Рік тому

      Wow! maybe share a picture you post on twitter or postlmg.cc/

    • @Paul-222
      @Paul-222 Рік тому

      @@SyberMath I tweeted it and @ed you.

  • @matthewfunk734
    @matthewfunk734 Рік тому

    Just imagine all the possibilities...

  • @ziplock007
    @ziplock007 Рік тому

    Problem: x +1 = 2, solve for x
    Answer x = e^(2 n pi i), n is integer
    I guess, if it doesn't say real numbers only... darn Euler

  • @zakariaaouf5564
    @zakariaaouf5564 Рік тому

    One simple solution, X^2-2X=0
    then X=2.

  • @rakenzarnsworld2
    @rakenzarnsworld2 Рік тому

    x = 0 or 2

  • @giuseppemalaguti435
    @giuseppemalaguti435 Рік тому +3

    X^2-2x=0....x=0,x=2

    • @robertveith6383
      @robertveith6383 Рік тому

      x^2 - 2x = 0, etc. The upper case ex and the lower case ex are two different variables.

  • @barakathaider6333
    @barakathaider6333 Рік тому

    👍

  • @BurningShipFractal
    @BurningShipFractal Рік тому +2

    Hello

  • @alextang4688
    @alextang4688 Рік тому

    Is it necessary to find the complex solution? In reality, students are not supposed to work out of them and no extra marks will be given. 🤔🤔🤔🤔🤔🤔

  • @shoshosalah3447
    @shoshosalah3447 Рік тому

    0,2

  • @justabunga1
    @justabunga1 Рік тому

    You don't need to waste time trying to do complex numbers and all, but why not set this as 3^(x(x-2))=3^0. Therefore, x=0 and x=2.

    • @jpolowin0
      @jpolowin0 Рік тому

      Because he stated at the outset that he wanted to determine all possible solutions, including the complex ones.

    • @justabunga1
      @justabunga1 Рік тому

      @@jpolowin0 it's true and that's correct, but it's just to make things a lot simpler and save time.

    • @RB_Universe_TV
      @RB_Universe_TV Рік тому

      Because he was trying to find out all the solutions
      He was experimenting

    • @SyberMath
      @SyberMath  Рік тому

      exactly! Thanks