Actually dekha jaye to isothermal woh process hai jis main temperature constant HOTA hai means change in internal energy remains zero . So input, Matlab heat energy saari ki saari work main consume Hoti hai but isothermal process practically impossible hai So the answer of ur question will be , that isothermal process main work sab se ziada HOTA hai
@@waheedkhan2880Sir Confused hoon agr ye ata h ke agr expansion ho to maximum work kahan zyada ho ga tou kiya phrr hm isobaric process ko select krein gein kiya
@@corpusxlive Jee bilkul. Agr expansion aata hai then maximum work is done in isobaric and if contraction then the answer will be adiabatic. But if nothing like that is mentioned then we will have to choose isothermal process.
ua-cam.com/video/9LLiUr9wJjQ/v-deo.html Dear! i have addressed all the questions as u mentioned in ur comment. Link of that new lecture is given above. Share it with ur frnds and juniors for maximum help.
@@sixeditz8649 Dear Its not about research but about understanding the point. keeping in view the statement of question, it is clear that slope of velocity time graph is gradually decreasing. This situation can be possible in both positive acceleration and in negative acceleration. Because in case of positive slope, the slope can either increase or decrease and the same can be achieved in case of negative acceleration. And these both variable slopes (increasing or decreasing) conclude that acceleration is variable but not specifying that its negative or positive. For reference, i am mentioning a link here from Physics in Seconds ua-cam.com/video/hKAj5E26YKs/v-deo.html You may also find other refences which are taking the statement as you took but the y dont have a proper explanation for it.I will further suggest if u r a student and preparing for mdcat then make ur mind clear on it. I can make a special lecture in that case for ur further clarification(if u need it) as i dont want anyone to get a wrong concept and appear in tests like mdcat , nums etc Stay Blessed
good explanation sir....Appreciated❣
I Feel blessed when the students get what I want to explain.
It encourages me to do more in that respect.
Share it with ur frnds
JazakALLAH ❤
Share it with ur frnds
@waheedkhan2880 🆗👍🏻👍🏻
Good
Thank u dear
Share with ur frnds
❤❤❤
Maximum workdone isobaric mn hoty hn sir
Actually dekha jaye to isothermal woh process hai jis main temperature constant HOTA hai means change in internal energy remains zero .
So input, Matlab heat energy saari ki saari work main consume Hoti hai but isothermal process practically impossible hai
So the answer of ur question will be , that isothermal process main work sab se ziada HOTA hai
But sir main nay 2 jaga parha Tha waha isobaric main maximum work Aya tha or test main b isobaric lagiya Tha @@waheedkhan2880
@@waheedkhan2880Sir Confused hoon agr ye ata h ke agr expansion ho to maximum work kahan zyada ho ga tou kiya phrr hm isobaric process ko select krein gein kiya
@@corpusxlive Jee bilkul. Agr expansion aata hai then maximum work is done in isobaric and if contraction then the answer will be adiabatic. But if nothing like that is mentioned then we will have to choose isothermal process.
149... 150.. 151 missing kindly sir explain them with statements and options.. JazakALLAH
44:52 p
ua-cam.com/video/9LLiUr9wJjQ/v-deo.html
Dear! i have addressed all the questions as u mentioned in ur comment. Link of that new lecture is given above.
Share it with ur frnds and juniors for maximum help.
"I really appreciate your dedication to helping students succeed. Your guidance has been invaluable."
🙂🙃
Most welcome dear. Keep studying.
@@waheedkhan2880 Bs Dear sir Dua kari 8 December ko reconduct MDCAT ha
Bus mehnat Karen
More and more practice with proper understanding of statements or questions.
@@waheedkhan2880 g g Dear sir
But Dua bi kari hum sub Mdcat aspirants ka liya 🙂🙃
157 k bhi A h sir Key mn apn solve kr k B nikala h or us question mn range k to koi zikr hi nahi h
ua-cam.com/video/gzM-zToH60M/v-deo.html
Dear! open the above link, i have solved Q No 157 and cleared the scenario.
Stay Blessed
36:40 Answer key ma A✓ ?😢
It is A. 😂
yes they opted the wrong option in key available on website
But dear the correct option as i explained is D
@@waheedkhan2880
The option is A.
It's not D. Kindly research again respected Sir.
@@sixeditz8649 Dear Its not about research but about understanding the point.
keeping in view the statement of question, it is clear that slope of velocity time graph is gradually decreasing.
This situation can be possible in both positive acceleration and in negative acceleration. Because in case of positive slope, the slope can either increase or decrease and the same can be achieved in case of negative acceleration. And these both variable slopes (increasing or decreasing) conclude that acceleration is variable but not specifying that its negative or positive. For reference, i am mentioning a link here from Physics in Seconds ua-cam.com/video/hKAj5E26YKs/v-deo.html
You may also find other refences which are taking the statement as you took but the y dont have a proper explanation for it.I will further suggest if u r a student and preparing for mdcat then make ur mind clear on it.
I can make a special lecture in that case for ur further clarification(if u need it) as i dont want anyone to get a wrong concept and appear in tests like mdcat , nums etc
Stay Blessed