JEE Main Physics Mechanics #47 Velocity vs Distance Graph
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- Опубліковано 29 чер 2024
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The velocity-displacement graph describing the motion of a bicycle is shown in the figure. The acceleration-displacement graph of the bicycle’s motion is best described by…
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I always enjoy Dr. van Biezen's clear explanations. His teaching is excellent and his knowledge approaches infinity.
graph must be an horizontal line ( derivative of gradient (slope) is a constant) and falls down to zero at 200 ?
Nice little problem
Glad you liked it.
Hello, I'm having a hard time accepting that both velocity and acceleration can both be linear at the same time when plotted as a function of distance x, and at the same time be both continuous in the case of velocity and discontinuous in the case of acceleration at the point x = 200.
Myself (and many others probably) and mostly versed in the time domain when talking about distance, velocity and acceleration problems, and I think it would make for a very satisfying connection if you were able to convert this specific example to the time domain and explain such a conversion in more detail (I guess I'm specifically asking about comparing v(t) with v(x) and a(t) with a(x) if possible).
Damn
Challenging indeed.
❤❤❤❤❤. Thanks a lot.
You're welcome 😊
wow
An interesting problem indeed.
@@MichelvanBiezen it blew my mind