Inter-planar spacing

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  • Опубліковано 3 гру 2024

КОМЕНТАРІ • 55

  • @Elfisicocuenta
    @Elfisicocuenta 6 років тому +15

    This is a espectacular explication, thanks so much professor. (From Colombia)

  • @Laura-Yu
    @Laura-Yu 2 роки тому +2

    Thank you for the clear drawing and the neat notes!! I was getting rusty with some of the earlier concepts and was having a hard time envisioning the plane!

  • @MrFaiqueShakil
    @MrFaiqueShakil 4 роки тому +5

    This was absolutely helpful, studied crystallography so much times from different professors, reference books but never got good understanding like this. Now, I understood why in XRD the miller indices planes are taken. Its all make sense now.

  • @priyankachahal2936
    @priyankachahal2936 Рік тому +1

    I was analyzing my TEM data and now matching it with my XRD data, however can you please tell that which peak I should consider from XRD data majorly so that I can correlate interplanar spacing by both XRD and TEM.

  • @russellazure9316
    @russellazure9316 3 роки тому

    Nice and concise. Thank you!

  • @Prisom-j3p
    @Prisom-j3p 6 років тому +2

    this is awesome sir

  • @rememberthename1238
    @rememberthename1238 3 роки тому +1

    Sir , what will happen if the miller indices of planes are not same or in other words, planes are not parallel? How will we calculate the interplanar spacing????

  • @thobelanisibiya8163
    @thobelanisibiya8163 4 роки тому

    Thank You Sir. You are the best

  • @sandipanpaul4440
    @sandipanpaul4440 6 років тому +1

    Superb

  • @陳沐雨-f5h
    @陳沐雨-f5h 4 роки тому +2

    thanks sir. bravo

  • @nikhilnegi9446
    @nikhilnegi9446 2 роки тому

    Sir I think at 6:45, OA will be equal to a/h if ,and only if, we had not scaled the Miller indexes by some factor to make it an integer. I mean, to find h if we just do reciprocal of the number of a's required to span x- intercept, only then will OA be equal to a/h. Please correct me if i am wrong.

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  2 роки тому +1

      You are right. When we define Miller indices we reduce to smallest integers, making (200) as (100). This is fine if we are not worrying about dhkl. But when we think of dhkl we do not use such reductions and consider (200) and (100) as distinct. For example, d200=a/2 and d100=a in cubic crystal.

    • @nikhilnegi9446
      @nikhilnegi9446 2 роки тому +1

      @@introductiontomaterialsscience i got it sir. Thanks for the help.

  • @divyanshrehal9819
    @divyanshrehal9819 4 роки тому

    Best explanation of topic 💯

  • @deeptikumarroy8630
    @deeptikumarroy8630 3 роки тому

    Thank you so much professor!

  • @VRAGHAVENDRASEC
    @VRAGHAVENDRASEC 4 роки тому +2

    Abdul Kalam voice sir

  • @aakashghole3007
    @aakashghole3007 5 років тому

    Thank u so much for detailed explanation 🙏🙏🙏🙏🙏

  • @shl9958
    @shl9958 6 років тому +2

    if OA=a/h, OB=b/k OC=c/l, miller indice (h/a k/b l/c). these are not equal to (hkl)???

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  6 років тому +6

      For Miller indices, you need to take reciprocals of 'intercepts in terms of respective lattice parameters". Thus the intercepts a/h. b/k and c/l have to be divided by a, b and c respectively to give relative intercepts 1/h. 1/k and 1/l. taking the reciprocals of the relative intercepts we get the Miller indices (hkl).

    • @shl9958
      @shl9958 6 років тому +2

      Thank you!!

    • @Krishna-in3ni
      @Krishna-in3ni 2 роки тому

      @@introductiontomaterialsscience 7:31 Sir once can you explain how you got OA= a/h if edge length of cube is a?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  2 роки тому

      @@Krishna-in3ni By definition, if the first Miller index is h then the first intercept is a/h.

    • @nikhilnegi9446
      @nikhilnegi9446 2 роки тому

      @@introductiontomaterialsscience sir according to you, we need to divide the edge length "a" by the corresponding length of intercept in order to get Miller index "h". But in books( for example SSP BY CHARLES KITTEN) ,they do the same but they also scale it to the nearest integer. If we also scale it then OA ≠ a/h. So according to the definition of h, do we have to scale it or not?

  • @sachinsingh-fx3bj
    @sachinsingh-fx3bj 6 років тому +1

    Good lecture.

  • @deeptikumarroy8630
    @deeptikumarroy8630 3 роки тому

    This can be found out using simple pythagoras theorem by projecting in all three planes XY, YZ, ZX

  • @caruntudamian8475
    @caruntudamian8475 4 роки тому +1

    My hero

  • @karthikpm9669
    @karthikpm9669 3 роки тому

    why cant sir use the black board

  • @banajadandasena4142
    @banajadandasena4142 6 років тому

    What is the interplanar spacing for BCC and fcc lattice?

  • @rajeshjaat4291
    @rajeshjaat4291 6 років тому +1

    awesome

  • @sharadchauhan1433
    @sharadchauhan1433 6 років тому +1

    Marvellous

  • @amrali3161
    @amrali3161 3 роки тому

    Thanks for that. How can we prove the interplanar spacing relation in the case of a hexagonal lattice?

    • @rajeshprasadlectures
      @rajeshprasadlectures 3 роки тому +1

      You can derive it using the concept of reciprocal lattice. I will do a video on it soon.

    • @nikhilnegi9446
      @nikhilnegi9446 2 роки тому

      @@rajeshprasadlectures Sir I think at 6:45, OA will be equal to a/h if ,and only if, we had not scaled the Miller indexes by some factor to make it an integer. I mean, to find h if we just do reciprocal of x- intercept, only then will OA be equal to a/h. Please correct me if i am wrong.

  • @shishtdharpandey6012
    @shishtdharpandey6012 2 роки тому

    Thank you so much sir

  • @sharadchauhan1433
    @sharadchauhan1433 6 років тому +1

    Great

  • @lokeshverma5902
    @lokeshverma5902 4 роки тому

    what does it mean for plane to pass though corners ? no where in derivation you took plane to be passing through corners

    • @rajkhandait8847
      @rajkhandait8847 4 роки тому

      Plane is passing through the corners of the unit cell.. The unit cell is not drawn.. We are assuming it

  • @dineshthagunna1807
    @dineshthagunna1807 2 роки тому

    What for hexagonal shape?

  • @livingliffee
    @livingliffee 3 роки тому

    Sir How do you calculate the miller indices given the inter planar spacing ? Thank you :)

    • @rajeshprasadlectures
      @rajeshprasadlectures 3 роки тому +3

      If only the interplanar spacing is given, nothing can be done. If lattice parameters are also given then you have a relationship giving interplanar spacing in terms of miller indices and lattice parameters. Still, since there are three Miller indices and only one equation, a solution is not guaranteed. But in the case of a cubic crystal, it is possible to get a solution because you can determine h^2+k^2+l^2. Given this value, one can determine the family {hkl}. for example if h^2+k^2+l^2=3 then you can say that {hkl}={111}. But within this family, a specific plane (hkl) cannot be determined. For example, it can be (111) or (-1 1 1) among other possibilities.

  • @piyushjadhav1685
    @piyushjadhav1685 4 роки тому

    Thank you very much sir

  • @rajkhandait8847
    @rajkhandait8847 4 роки тому

    Sir, how can we say that the distance between origin and plane is the same as the distance between two successive planes passing through corners.? Can you please explain this?

    • @introductiontomaterialsscience
      @introductiontomaterialsscience  4 роки тому +7

      This really part of the definition of interplanar spacing. Consider any given Miller Indices (hkl). This gives a plane with intercepts a/h, b/k, c/l. By definition, any plane parallel to this will also have the same Miller indices. Thus with this definition alone we cannot define dhkl uniquely. So after having the first plane with intercepts a/h, b/k, c/l we take as the next plane one passing through the origin and parallel to this plane and define the distance between them as dhkl. And then we repeat these planes at dhkl to have a set of parallel (hkl) planes with spacing dhkl. I hope I have made it clear.

    • @rajkhandait8847
      @rajkhandait8847 4 роки тому

      @@introductiontomaterialsscience yes sir, i got it. Thank you so much.

  • @BethCh
    @BethCh 5 років тому +2

    Thankyou Sir

  • @harshitpant07
    @harshitpant07 4 роки тому

    Sir did you not teach numerical?

  • @DAGAME464
    @DAGAME464 4 роки тому

    Thank you sir

  • @Upgradezz
    @Upgradezz 4 роки тому

    How do you define 'adjacent' planes?

    • @rajkhandait8847
      @rajkhandait8847 4 роки тому

      The parallel plane in the adjacent unit cell passing through its corners

  • @melkamubaza6707
    @melkamubaza6707 6 років тому

    God bless you

  • @BC-yr6eg
    @BC-yr6eg 4 роки тому

    👍👍👍👍

  • @kc-dotdot
    @kc-dotdot 4 роки тому

    Amrita ece(E,F,G) guys say 👋

  • @HIMANSHU-hu2re
    @HIMANSHU-hu2re 6 років тому

    How it can be proved that (hkl) perpendicular to [hkl]?
    Please answer me sir with my UA-cam account