Checkbox Values edit and update from mysql database in PHP Tutorial-106(Hindi/Urdu)

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  • Опубліковано 9 лис 2024

КОМЕНТАРІ • 45

  • @CreateWebsiteWithJigs
    @CreateWebsiteWithJigs  6 років тому +1

    Checkbox Values edit and update from mysql database code
    drive.google.com/open?id=14QLUw0PJ7RPsPSmeIPe-PU-KfKu5ZG_i

    • @jaydeepsapariya8532
      @jaydeepsapariya8532 4 роки тому +1

      sir one more question regarding in php that is it is posible to make depandent dynamic drop-down without Ajax,jquery and js.... posible?......

    • @CreateWebsiteWithJigs
      @CreateWebsiteWithJigs  4 роки тому +2

      Without jquery and ajax it is possible but you have to use jquery and ajax because without that page will refresh every time

    • @adityamakarubiya3075
      @adityamakarubiya3075 11 місяців тому

      full code is send please

  • @atinsehgal
    @atinsehgal 4 роки тому +2

    Thanks a ton...I am glad I could find this tutorial which is easy to understand and you also have a helpful attitude to help if any query is there from visitor

  • @jayeshparmar3132
    @jayeshparmar3132 2 роки тому +1

    Thank sir

  • @pawanbhatta8973
    @pawanbhatta8973 4 роки тому +1

    Thanks a lot man, you saved me

  • @nourarochdi
    @nourarochdi 4 роки тому +1

    oh thank uuuuuuuuuuuuuuuuuuuuuuu, thank u very much.

  • @ColdFuzionz9111
    @ColdFuzionz9111 5 років тому +1

    Thank you. Your knowledge is appreciated.. =)

  • @jobkochu6533
    @jobkochu6533 4 роки тому +1

    please make a video on how to make reports with output from all the controls like text box,drop down,check box etc ...

  • @sohamvirda7914
    @sohamvirda7914 4 роки тому +1

    Thank you sir

  • @HemantKumar-zi4xr
    @HemantKumar-zi4xr 4 роки тому +3

    sir ji laravel bhi shikhayie plz , and php with oops

  • @shanudey3671
    @shanudey3671 7 років тому +1

    Really helpful . Its save my life :)

  • @ni3makwana
    @ni3makwana 6 років тому +1

    great sir...

  • @titik_kom
    @titik_kom 6 років тому +1

    terimakasih banyak, ini berhasil

  • @temmyalex5364
    @temmyalex5364 6 років тому

    nice tutorial thanks

  • @iPushprajMishra
    @iPushprajMishra 7 років тому +1

    thnx jigs ....got it very well

  • @JatinderSingh-nj1cy
    @JatinderSingh-nj1cy 6 років тому

    Nice in_array

  • @mariacristinaulloagarrido1224
    @mariacristinaulloagarrido1224 7 років тому +1

    very nice!

  • @benhamdinemohamed3854
    @benhamdinemohamed3854 3 роки тому +1

    How about if the select options are in another table ?

  • @marathiminati7530
    @marathiminati7530 6 років тому +1

    thanks sirg

  • @manvithakur5172
    @manvithakur5172 6 років тому +1

    thanks

  • @atmakarimang
    @atmakarimang 7 років тому

    Thanks..

  • @thebookwormsden890
    @thebookwormsden890 5 років тому +1

    Hi, I tried this code.Updation works fine but when we are about to submit a new form the checkbox field is showing error as "Warning: in_array() expects parameter 2 to be array, string given" .Any solution for this????

  • @yosratawfieg9661
    @yosratawfieg9661 4 роки тому +1

    echo checked does not work ????

  • @darshandave9145
    @darshandave9145 6 років тому

    i got an error "Warning: in_array() [function.in-array]: Wrong datatype for second argument in" ill used xamp server nd using mysqli function

  • @stellatio4854
    @stellatio4854 4 роки тому +1

    Where $a and $b from?

  • @renudhotre9552
    @renudhotre9552 6 років тому +1

    can u provide source code