hey, when you say that you want to generalise the equation, aren't you doing the opposite by applying sign conventions that are specifically meant for the particular lens that is, for this case, a convex lens? intuitively, i think it makes more sense to call the eqn you derived first as the general eqn instead of the one you got after the application of sign conventions.
Although at last when we take sign convention. We take v as +ve, u as -ve and F as positive but f is in both the sides of lens so why not take it as -ve ?
I think the more general equation is 1/f = 1/u + 1/v, right?. Since it isn't limited by signs and therefore allows one to use a sign convention (e.g right side of lens = +; left side = -) for all the variables (f, u, and v) according to the specific mirror/lens. Is that correct?
i have the same question! when you say that you want to generalise the equation, you're doing the opposite by applying sign conventions that are specifically meant for the particular lens that is, for this case, a convex lens. intuitively, i think it makes more sense to call the eqn derived first as the general eqn instead of the one after the application of sign conventions.
Let's have an example Let's say, f = 2 units u = 3 units u > f By using the formula, 1/f = 1/v - 1/u 1/2 + 1/3 = 1/v 1/v = 5/6 v = 6/5 Which is f > v but from the diagram to derive the formula, it is v > f.
Sir, this is the wrong formula. Lens formula= 1/V *-* 1/U = 1/f You took the u(object distance) positive, whereas it should always be -ve. The first eq. should have been hi/ho=v/-U
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Term2 ki preparation kaise chal rahi h? 😹
Thanks sir love your lectures... My revisions are easier due to you... And your English is amazing thank you very much sir
Your English is fantastic...
How clear you pronounce all the words!
Anyone can easily understand it.
yeah... everything but the hetch
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Mahesh sir, you are a saviour!
U are just 💕amazing optics now my favorite topic🔅
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This is so helpful. Thanks a lot!!
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hey, when you say that you want to generalise the equation, aren't you doing the opposite by applying sign conventions that are specifically meant for the particular lens that is, for this case, a convex lens? intuitively, i think it makes more sense to call the eqn you derived first as the general eqn instead of the one you got after the application of sign conventions.
Bst one,keep it up
Thanks a lot sir in this much simple language!
Although at last when we take sign convention. We take v as +ve, u as -ve and F as positive but f is in both the sides of lens so why not take it as -ve ?
Because light converges on the side opposite to the one from where the rays are coming in case of a convex lens.
really nice ❤❤
Amazing demonstration
I think the more general equation is 1/f = 1/u + 1/v, right?. Since it isn't limited by signs and therefore allows one to use a sign convention (e.g right side of lens = +; left side = -) for all the variables (f, u, and v) according to the specific mirror/lens. Is that correct?
i have the same question! when you say that you want to generalise the equation, you're doing the opposite by applying sign conventions that are specifically meant for the particular lens that is, for this case, a convex lens. intuitively, i think it makes more sense to call the eqn derived first as the general eqn instead of the one after the application of sign conventions.
Amazing 😍😍
What a teacher😌
Thankyou Sir Mahesh!
Superb
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thank you..
Its not hetch
Thank you
Bro, it is not u, but minus u
Object left side
7:51
ty :)
Let's have an example
Let's say,
f = 2 units
u = 3 units
u > f
By using the formula,
1/f = 1/v - 1/u
1/2 + 1/3 = 1/v
1/v = 5/6
v = 6/5
Which is f > v but from the diagram to derive the formula, it is v > f.
U have to take U= -3 units
Sir, this is the wrong formula.
Lens formula= 1/V *-* 1/U = 1/f
You took the u(object distance) positive, whereas it should always be -ve.
The first eq. should have been hi/ho=v/-U
See the entire video bro... 😁
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@@_N_o._.one_ 😂😂😂That's great bro
Ya brother you are right
Super sir
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Abe lens formula to 1/v-1/u hota h. Ye to mirror h
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