Sir greetings ..you have been the one most significant tutor for me...I don’t simply understand what teachers teach me ...if you were nor here I would have failed in my classes always ...now i have getting good marks and all of credit , all of credit totally i wanna give to you,,,,you made me so easy to understand ,,
OK I have a question why on the first two problems after taking the derivatin of MUx you added also the y and vice versa and on the last two you didn't add the second factor near the derivative of the first? Thanks a lot very useful but this question came into mind.
@@Camcrazy530 because in the first few examples he is multiplying the x and y and in the other cases (where he doesn’t use the Y) he’s adding the two. Derivative of x*y by x = y. Derivative of x+y by x is 1.
The only thing I dont understand is how you got the y/2x , the exponent part I dont get I understand how you got 2 but not how the exponents are just gone.
U = X^2Y^3 The partial derivative of U with respect to Y = 3X^2Y^(3-1) = 3X^2 Y^2. Notice that the exponent on the Y term was brought down in front and then we subtracted 1 from the exponent on Y, leaving Y raised to the 2nd power. Another way of doing this, which might be easier to understand, is to rewrite the utility function as U = bY^3, where b = X^2. The derivative of bY^3 = 3bY^2. Next, substitute X^2 for b to get your final answer: 3X^2 Y^2.
Im so confused on how we get the final answers for the examples , can someone please help me understand how exactly we came from 2xy^3/3X^2y^2 = 2y/3x and 1/3X^-2/3Y^2/3÷ 2/3X^1/3Y-1/3= Y/2x 😭😭💀
This many years later, you sir are still helping students with their homework.
Sir greetings ..you have been the one most significant tutor for me...I don’t simply understand what teachers teach me ...if you were nor here I would have failed in my classes always ...now i have getting good marks and all of credit , all of credit totally i wanna give to you,,,,you made me so easy to understand ,,
Exactly what I looked for 3 hours. Thanks
I would like to raise an argument, isn't the Marginal Rate of Substition supposed to have a negative sign for instantance MRS = -MU`/MU``
Who's watching in 2020?
2021
2023
2023✋️
2024
2020 you say. 2023
whose economics professor is using cruise control and just sending you here?
OK I have a question why on the first two problems after taking the derivatin of MUx you added also the y and vice versa and on the last two you didn't add the second factor near the derivative of the first?
Thanks a lot very useful but this question came into mind.
exactly idk why
Agreed..... wtf
@@Camcrazy530 because in the first few examples he is multiplying the x and y and in the other cases (where he doesn’t use the Y) he’s adding the two. Derivative of x*y by x = y. Derivative of x+y by x is 1.
@@Jimmyczech1thanks for clearing that up. I was confused for a second there
Thanks for the easy to understand examples
thank you teacher this is amezing video it helps me
The only thing I dont understand is how you got the y/2x , the exponent part I dont get I understand how you got 2 but not how the exponents are just gone.
he missed the negative. it should be y/2x^-1
@@Lucas-jc2rq nope, he was right
This video was very useful. Thanks a lot!
Kaç video izledim, 8 yıl önce 8 dakikada anlatılmış video etmiyor
thank you .this video is very useful
But Why didn’t MRS Equation Being negative?
why did you derive in the beginning? how did that get the MU?
thank you so much this is very helpful youre the best
Thank you very much 🎉
Im sure this is wrong. Isnt marginal utility supposed to be diminishing? Wouldn't the marginal utlity be increasing in the first example?
Thank you very much, sir.
but I have some questions in the last few examples. why you didn't add constant factor to the derivative factor
it's a partial derivative, the constant is ignored
But he did at the first example
How do u derive the demand function of X and Y?
Hope this helps: ua-cam.com/video/jDbVWay6c20/v-deo.htmlsi=tJxxucTZrc5oXop7
Sir how do we derive the equation of equi marginal utility
This may help: ua-cam.com/video/6H4ZHLDBrjY/v-deo.html
thank you so much
You are welcome!
since the 3 is brought down already, from where does the square come on the Y
You need to subtract 1 from the exponent on Y, which gives Y^(3-1) = Y^2. I did the same thing for the exponent on X.
Why is the marginal utility for y when derived 3x^2 y^2. sorry my calculus is very bad but i could not figure it out.
U = X^2Y^3
The partial derivative of U with respect to Y = 3X^2Y^(3-1) = 3X^2 Y^2.
Notice that the exponent on the Y term was brought down in front and then we subtracted 1 from the exponent on Y, leaving Y raised to the 2nd power.
Another way of doing this, which might be easier to understand, is to rewrite the utility function as U = bY^3, where b = X^2.
The derivative of bY^3 = 3bY^2. Next, substitute X^2 for b to get your final answer: 3X^2 Y^2.
1sportingclays Thank you, I've watched a couple of times now, starting to pick it up now :)
Im so confused on how we get the final answers for the examples , can someone please help me understand how exactly we came from 2xy^3/3X^2y^2 = 2y/3x and 1/3X^-2/3Y^2/3÷ 2/3X^1/3Y-1/3= Y/2x 😭😭💀
shouldn't there be a minus sign before ur result?
You would only put a minus sign in front of the MRS results if you wanted the slope function of the indifference curve.
How to solve u(x,y)=x÷logy
How come 2/3 - 1 = -1/3?
2/3 - 1 = 2/3 - 3/3 = -1/3.
(I changed - 1 to - 3/3 to get the same denominator in the other term, 2/3).
@@EconomicsinManyLessonsthank you for that
I didn't really understand the entire explanation
derive marshallian demand function
Who can please answer to this:
U=x²+4xy+4y²-20
i study economy and in i hate it i want to be a forex trader
No i did not go to university... i went to youtube academy)))
wow
(B,Z)=AB^1/a Z^1/B
What's the marginal utility
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