Statement: If the probability of occurrence of an event (probability of success) in a single trial of Bernoulli's experiment is p, then the probability that the event occurs exactly r times out of n independent trials is equal to nCr qn - r pr, where q = 1 - p, the probability of failure of the event.
Suppose that a game is played with a single die assumed fair. In this game a player wins 20$ if a 2 turns up, 40$ if a 4 turn up, losses a 60$ if a 6 turns up. While he neither wins nor losses of any other face turns up. Find the probability density function?
Probability to show 6 is 1/6 and amount is -60 Probability to show 2 is 1/6 and amount is 20 Probability to show 4 is 1/6 and amount is 40 Remaining possibilities 3/6 and amount is 0
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clearly explained than any English tutor. Thanks man
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شكرا لك
Very nice explanations
Statement: If the probability of occurrence of an event (probability of success) in a single trial of Bernoulli's experiment is p, then the probability that the event occurs exactly r times out of n independent trials is equal to nCr qn - r pr, where q = 1 - p, the probability of failure of the event.
Great 👍
Have a great learning in CSE
U re good man❤
Have a great learning in CSE
beautifully put!
Thank you 😊
formula- P(r)=nCr P^r.q^n-r WHERE r=1,2,3,.......n
Suppose that a game is played with a single die assumed fair. In this game a player wins 20$ if a 2 turns up, 40$ if a 4 turn up, losses a 60$ if a 6 turns up. While he neither wins nor losses of any other face turns up. Find the probability density function?
Please interpret this question. Thank you
Probability to show 6 is 1/6 and amount is -60
Probability to show 2 is 1/6 and amount is 20
Probability to show 4 is 1/6 and amount is 40
Remaining possibilities 3/6 and amount is 0
❤
nice
Sab kuchh thik tha pr suru ka rington Kan dukh gya
Nice explanation but iam unable to understand
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Mathlab?
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