The lighthouse of height 10root 3 stands vertically on a sea shore. A tower and a ship are standing 30m and 10m away from the foot of lighthouse respectively. The angle of elevation of the top of the tower from the top of the lighthouse is 30°. Find the height of the tower and distance between the top of the lighthouse to the top of the tower. Also find the angle of depression formed from the top of the lighthouse to the ship.
Distance= (80√3-80)m = 80(√3-1)m = 80(0.73)m = 58.4m Time = 2seconds ( given) Therefore speed of bird = distance/speed= 584/20=146/5=29.2m/s Hence the speed of bird is 29.2m/s Thank you Ma'am
In triangle ABC Tan45° = 80/BC. Cross multiply bc = 80 Now, In triangle EBD Tan30° = 80/cd+30 = 1/√3 80√3-30 = 1 80(√3-1) = cd Put the value of √3 80(1.732 -1) =cd. ( 40(√3 - 1) 4x 7.32 - 1 = 29.28 is the bird flyed 😊
Excuse me mam in modal paper and in state level preaparatory there are giving 3marks of sum in triangles lesson plzz note that and please explain about it mam Please reply
The lighthouse of height 10root 3 stands vertically on a sea shore. A tower and a ship are standing 30m and 10m away from the foot of lighthouse respectively. The angle of elevation of the top of the tower from the top of the lighthouse is 30°. Find the height of the tower and distance between the top of the lighthouse to the top of the tower. Also find the angle of depression formed from the top of the lighthouse to the ship.
Mam explaination with answer plz mam
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35:22 29.2m/s
Distance= (80√3-80)m
= 80(√3-1)m
= 80(0.73)m
= 58.4m
Time = 2seconds ( given)
Therefore speed of bird = distance/speed= 584/20=146/5=29.2m/s
Hence the speed of bird is 29.2m/s
Thank you Ma'am
Plz help me br9
Bro in last why did you divide by 5 ?
Homework Ans:-Speed of flying of bird is 29.2 m/s
In triangle ABC
Tan45° = 80/BC. Cross multiply bc = 80
Now,
In triangle EBD
Tan30° = 80/cd+30 = 1/√3
80√3-30 = 1
80(√3-1) = cd
Put the value of √3
80(1.732 -1) =cd. ( 40(√3 - 1)
4x 7.32 - 1
= 29.28 is the bird flyed 😊
Mam answer is 29.20
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Mam Answer for Homework Question is
29 metre/second
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Present mam⚡ Last question ans CB= 58.4 barutane
Yes bro correct
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15:15 mam we should rational everytime we get √ in denominator
Speed of the Bird Ao 138.4 and DA 58.4 And DO 80m
Speed = 29.2 m/s
29.2 is the answer
12:05 it's same mam
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Mam Hw ans:2.92m
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Yes mam banthu 40 / root 3
The speed of flying bird is 29.2
Speed is 25.1m/s
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Ad =80
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no problem
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Mam speed is 29.2m/s
Is it correct?
40/√3
29.2m/s
Speed of flying of the bird is 29.20 m/s
Mam please make a video on application questions of triangle chapter
AD =40/root3
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Hw problem of cos is correct as 40/√3 as sin and last hw is 29.20 m/s
Mam ans 29.20m/s😊
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speed of bird= 29.2 m/s
Excuse me mam in modal paper and in state level preaparatory there are giving 3marks of sum in triangles lesson plzz note that and please explain about it mam
Please reply
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Speed of bird is 29.28 m/s
Can anyone provide social imp material
29.2 mls
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Madam 58.4
Mam 58.4m/s
Mam zen paper 4 nivu solve madilva
29.2m2
Mam i got around 26.011 m/s
AD=80(√3-1)
Mam speed is equal to or twenty nine point two meters second
Hw answer 29.2
Zen paper means what mam??
AD=40√3
29.2mls
58.4m/s is correct or wrong say mam
Speed is 29.2 m/s
29.20m/s
Answer for H.W question:- 29.2m/s.
29.20 m/s
Mam congratulations for reaching 55k m. Thank you very much mam for helping for exams . I wish to grow more you in youtube.
thank you
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2/58.4
First view
Hiii
Ad =80
AD=40/root 3
29.2 mls
29.28m/s