Heat Equation: Solution using Fourier transforms

Поділитися
Вставка
  • Опубліковано 5 гру 2014

КОМЕНТАРІ • 17

  • @teldtel4641
    @teldtel4641 9 місяців тому +1

    Your video is very clearly explained ! I've understood the main principe of FT for PDE'S thank you so much !

  • @jazminalejandramartinezgue6939
    @jazminalejandramartinezgue6939 3 роки тому +2

    thanks! :) absolutely clear as always

  • @miguelaphan58
    @miguelaphan58 5 років тому +2

    excelent work, short and complete

  • @AJ-et3vf
    @AJ-et3vf 2 роки тому

    Awesome video! Thank you!

  • @Abhishekvipulshah
    @Abhishekvipulshah 9 років тому +1

    Tomorrow is my test and you man have saved me!! Thank You.

  • @ingenieroacevedo
    @ingenieroacevedo 9 років тому +1

    Props to you! Great step through step explanation. Thanks, man

  • @ankitsinghnegi3587
    @ankitsinghnegi3587 5 років тому +1

    Thank you!

  • @user-xl4fx4je2g
    @user-xl4fx4je2g 3 роки тому

    Thank you :)

  • @AbuSayed-er9vs
    @AbuSayed-er9vs 4 роки тому +1

    Well done!But how to visualize it?

  • @zawette
    @zawette 7 років тому

    is it possible to use the first shifting theorem on this example ?

  • @njaurora3171
    @njaurora3171 7 місяців тому

    thanks a lot🎉

  • @HeneStuchi
    @HeneStuchi 5 років тому

    excellent

  • @sirr3d488
    @sirr3d488 8 років тому +5

    Very well explained but you kinda got it wrong with the Fourier Transforms. The forward fourier tansform is with an - in the exponential and the backwards one is with the +.

    • @aberpdes
      @aberpdes  8 років тому +23

      No, that's just one convention :) Other conventions are available. So long as a consistent transform/inverse pair are used along with theorems (e.g. derivative theorems) that are consistent with the definition, all is well :)

  • @ginnykaur9886
    @ginnykaur9886 6 років тому +3

    Sir, could you explain me why are you not using -ve i (iota) in the definition of Fourier Transform and +ve i in the inversion formula......?

  • @paulestrada961
    @paulestrada961 5 років тому

    Otherwise you are just creating a new way to define a fourier transform

  • @paulestrada961
    @paulestrada961 5 років тому

    Need to redo this video with the proper definition of a fourier transform. All this is doing is making me more confused with how to solve the heat equation and also more confused to understand where the fundamental solutions of this PDE come from. Yes, because of the boundary conditions for the heat equation; this way to define the fourier transform will still agree with the fourier derivative theorem. But still, I came here for help and all I got was a new form or way in which the fourier transform was to be defined as.