Solving for Stress on an Inclined Plane!

Поділитися
Вставка
  • Опубліковано 12 гру 2022
  • Question: The steel bar shown will be used to carry an axial tensile load of 400kN. If the bar is 45mm thick, determine the normal and shearing stresses on plane a-a.
    If you have any recommendations for future problems, or have suggestion for tutorials in the future, feel free to leave a comment!

КОМЕНТАРІ • 10

  • @181zahoorzaier9
    @181zahoorzaier9 2 місяці тому

    thank you sir

    • @simple_civil
      @simple_civil  2 місяці тому

      No problem! Glad I could help my friend

  • @p4umce
    @p4umce 4 дні тому

    Can you give a real life example where you would need to consider where an angular plane needs to be considered and stress at that plane with respect to axial load needs to be calculated?

    • @simple_civil
      @simple_civil  4 дні тому

      An example that comes to the top of my head would be having an an axially loaded member, fastened together in the middle by a bolted connection, but the connection between the two members is at an angle instead of perfectly perpendicular to the load. I'm sure there are more examples in textbooks, but I also assume that the most likely used for these formulas would be for material testing purposes.
      Hope this helps!

  • @simple_civil
    @simple_civil  Рік тому

    If you wish to only see the problem, please skip to 3:52. As always, thanks for watching and I appreciate the support!

  • @angelolimage
    @angelolimage 4 місяці тому

    Why is Aplane=A/cos(theta)?

    • @simple_civil
      @simple_civil  4 місяці тому +1

      Hey! It should be just basic SOH CAH TOA. CAH is cos(theta) = A / A(plane). Rearranging this, we are left with A(plane) = A / cos(theta). Hope that's okay!

    • @angelolimage
      @angelolimage 3 місяці тому

      I see now. Thank you!@@simple_civil

    • @sabugeorge5001
      @sabugeorge5001 2 місяці тому

      P=N cos(theeta). Am i correct sir

    • @simple_civil
      @simple_civil  2 місяці тому

      @@sabugeorge5001 P=N / cos(theta)! Thanks for asking