Chi-squared test of association - jamovi

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  • Опубліковано 6 вер 2024

КОМЕНТАРІ • 10

  • @irlaura1424
    @irlaura1424 Рік тому +1

    Dudeeeee, you just saved my life !!!

  • @haroldasraz
    @haroldasraz Рік тому

    Super explanation. Cheers.

  • @biggersmoother
    @biggersmoother 10 місяців тому

    What is our P is not significant but our Cramers V shows moderate association. Can both be true?

  • @VexingVictor
    @VexingVictor 4 роки тому +5

    How would you report the results in APA?

    • @biggersmoother
      @biggersmoother 10 місяців тому +1

      Noone ever shows how to report APA results. Drives me crazy...

    • @ecoarena
      @ecoarena 6 місяців тому

      The chi-square revealed that there was no link between psychregions and governor, X2(2) = 4.89, P = 0.087. (and yes, that X2 should be a superscript 2)!

  • @akshitanarad1401
    @akshitanarad1401 4 місяці тому

    Hi pls help on my jamovi it is showing

  • @muhammadivandrariswidita7806
    @muhammadivandrariswidita7806 4 роки тому

    If I want to find out the effectiveness of two types of information labels (treatment vs no treatment) on a consumer's purchase behavior (the number of products purchased under different labels), is it appropriate to use a chi square test of independence? If so, how to perform it using Jamovi?

    • @AbdullahN8
      @AbdullahN8 Рік тому

      Is the test still applicable despite having observed frequencies less than 10?
      Big thanks for the tutorial

  • @liutrvcyrsui
    @liutrvcyrsui Рік тому

    +1