basic algebra: a cubic equation has 3 solutions; most comments only mention x=5. there two more solutions. x = [-5 ± √(∆) ]/2 = [-5 ± √(-75) ]/2 = [-5 ± √(25 * -1 * 3) ]/2 = [-5 ± 5*i*√ 3]/2 where (by definition) i = √(-1)
WAY too fiddly. =5 is immediately obvious. There are 3 solutions since it is a cubic, symmetrical about the origin on the Argand plane. so x = 5, 5 cis(2π/3) and 5 cis(-2π/3). giving x = 5, 5(-1+i√3)/2, 5(-1-i√3)/2 And if this is the level I need for Harvard, let me at it!
yes, 5 is one of the three solutions guaranteed for a cubic equation you are forgetting the two complex solutions -- you have done most of the work. x = [-5 ± √(∆) ]/2 = [-5 ± √(-75) ]/2 = [-5 ± √(25 * -1 * 3) ]/2 = [-5 ± 5*i*√ 3]/2 where (by definition) i = √(-1)
и тут я обращаюсь ко всем идиотам, не являющимся героическими орками: поймите вы, наконец, как наша героическая армия орков под командованием верховного долбанного советского агента Орка Путлинки рассчитывает траектории ракет, летящих на проклятую Украину, которые не хочет бесплатно задирать большую матушку Россию, т. е. бандитский Оркостан!!!
you dumb? The first solution itself is x = 5. But there are solutions also in the complex world. x to the power of 3 must have three solutions thats what
That set zero multi zero. Zero multi not zero Not zero multi zeo Empty. And, zeo multi zero is zero necesary the proof Also zero multi not zero is zero proof.
basic algebra: a cubic equation has 3 solutions; most comments only mention x=5. there two more solutions.
x = [-5 ± √(∆) ]/2 = [-5 ± √(-75) ]/2 = [-5 ± √(25 * -1 * 3) ]/2 = [-5 ± 5*i*√ 3]/2
where (by definition) i = √(-1)
Thank you
(5×5)+(5×5)+(5×5)+(5×5)+(5×5)=
X*X*X=125
125÷x÷(x*x)=
x*x=125÷x
X=125÷x÷x
X=125÷5=25
X=25÷5=5
어떻한 수+같은수로 두번 나눠줘야 x에 3제곱이다?
X에 3제곱정의는 N 이 어떻한수로,
!!!어떻한수와 같은 동일한수로 2번!!! 나눠줘야 n 에 3제곱이다=!!!같은수로 3번곱해야 3제곱!!!이다.
125=1×125
5×25
5×5×5
나눌땐 동일한수로 2번 나눠지고, 곱할땐 같은수로 3번 곱하는거"3제곱
8÷2÷2=2
8=2×2×2
N을 동일한 x로 한번더 x =x가 되는게 n에 3제곱
#####10에 x÷x=x
10에x÷x=x는?######
이걸풀면 필즈상 아벨상 받는다ㅋㅋ
Thank you
Keep growing my fellow Mathematician ❤❤❤❤❤❤I have subscribed
WAY too fiddly.
=5 is immediately obvious. There are 3 solutions since it is a cubic, symmetrical about the origin on the Argand plane.
so x = 5, 5 cis(2π/3) and 5 cis(-2π/3).
giving x = 5, 5(-1+i√3)/2, 5(-1-i√3)/2
And if this is the level I need for Harvard, let me at it!
X^3=5^3
X=5
Thank You for comments
Totaly crazy guy
3x = 5^3
3x= 125
x = Log125 / Log3
x = 4.39492
3^4.39492 = 125
4.39492 no es jamás un número imaginario.
Thank you for comments
true, but that is unrelated to the problem given :: x^3 = 5^3
X³=5³; solution; X³-5³=0; (X-5)(X²+5X+25)=0; X-5=0; X=5; X²+5X+25=0; ∆=5²-4×1×25; ∆=25-100; ∆=-75;S={5}.
Thank you
yes, 5 is one of the three solutions guaranteed for a cubic equation
you are forgetting the two complex solutions -- you have done most of the work.
x = [-5 ± √(∆) ]/2 = [-5 ± √(-75) ]/2 = [-5 ± √(25 * -1 * 3) ]/2 = [-5 ± 5*i*√ 3]/2
where (by definition) i = √(-1)
Это задача не уровня Гарварда. Так, 8-9 класс школы максимум. Основная идея для решения - что корней такого уравнения - три по максимальной степени.
Thank you for comments
и тут я обращаюсь ко всем идиотам, не являющимся героическими орками: поймите вы, наконец, как наша героическая армия орков под командованием верховного долбанного советского агента Орка Путлинки рассчитывает траектории ракет, летящих на проклятую Украину, которые не хочет бесплатно задирать большую матушку Россию, т. е. бандитский Оркостан!!!
Muito bom, consegui resouver esse bicho cabeludo.
Thank you for comments
X^3=5^3 X*x*x= 5*5*5 Y=5
Thank you for your comments
Why doesn’t X = 5?
you dumb? The first solution itself is x = 5. But there are solutions also in the complex world. x to the power of 3 must have three solutions thats what
Thank you for comments, Three solutions
Because this is too symple
Cubic function. Can have up to 3 solutions. One real 2 imaginary.
X³=5³? X=5
Thank you for comment
IMAGINARIO
The solution is clearly obvious. Not sure why the creator took the marathon route through the jungle to solve this problem.
bro shut up. x = 5 is straightforward but im pretty sure you couldn't have found the other 2 complex answers bruuhhhh. Study some maths
Study complex numbers. Cubic equations have 3 solutions.
x=5
Thank you for comments
That set zero multi zero.
Zero multi not zero
Not zero multi zeo
Empty.
And, zeo multi zero is zero necesary the proof
Also zero multi not zero is zero proof.
Proof, the first.
Thank you for comments
@선플라워-s3u what are you trying to say ??? perhaps avoid any english and stick to the maths
5
Thank you for commnet
125
Thank you
Yep, x^3=125, but we need x, and x have 3 roots
in English ... "a*b" is read "a times b" not "a into b". very distracting.
Thank you for comments
5