Dil dooba // slowed + reverb // 𝘚𝘢𝘯𝘨𝘪𝘵 𝘱𝘦𝘦𝘳𝘳𝘦𝘦𝘮𝘪 ♪
Вставка
- Опубліковано 2 жов 2024
- Hey peerreemi's 💕 !!!!
Listen to this amazing song " Dil dooba " ✨
Use earphone for better experience 🎧
Hope you will enioy 🛐
Tags :
#audiosforedits #editingaudios #reverb, #edits #edit #btsedits #btsedit #editaudio #editaudios, #instagramedits #instagramaudios #hindi, #aestheticaudios #popular #popularedits #popularaudios, #remixaudios #aesthetic, #hindiaudios #hindisongs #desiedits #pakistaniaudios #hollywood, #myheadisspinningxrichboy #richboy #money
Thanks for listening 🛐
Dil doobaa...hmmmhmmm🌝
asiqh hun deewana hun tere liye kuch bhi kar jaunga gaa 😌💕🫂
@@sangitpeerreemi1901 🌝isshh
@@eccedentesiast_s elabu 🙈💕
🧐
Are Sorry...
Galat jagah aa gaya
Aap apna chemistry jari rakhiye
@@sangitpeerreemi1901 Bua go tamar pyaar♥️♥️
Any one here 2024 😂❤
Hayeee♥️😩
Mera dil toh doob gaya♥️😩
Ooho❤
Seh ma yaar
Doob Jane do😅
Bhai bhai bhai kya perfect slowed hai 🎉🎉🎉🎉🎉🎉🎉🎉
I.. like... So.. much... Slow.. and... reversed... song.. it's really osm....✌️💥
ooo realy🤣🤣
🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥 kya song hai yrre 🔥🔥🔥🔥 I have no words for this song 🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥💓💓💓💓💓💓
Awwwwwwww oye hoye kya songa he yarrr❤
Kon kon hai jo 2024 main ye song sun raha hai
🙋♂️
Me
Me❤❤❤❤❤😊😊😊
Ma abi son raha 😂😂😂
😂
Nice❤
Heaven❤️😌
Addicted 😩✨
Master piece ✨🦋🌃💞
sera song bro....
I'm addicted 😩
Areee bro ☺🤍
Same 🌼
Amio 🙂
@@jordenammy6168 Bengali?
bhai piles h kya?
Awe cute song😩🤞🏾
This is just amazing bro❤❣️
I like this song 💓💓
Dill dooba❤️🔥
❤❤ I love this song
In word : Amazing 🤩
Perfect slowed n reverb ❤️😌
Dil doobaa...hmmmhmmm🌝
Vibe 💫⚡️✨
Anyone watch 2024 like now
40k.😳😳
🥳🥳🥳
Hehe 😄🤍
Mein tere jashe ma na aaugi...ore diwane ja..aaye Haye
This lyrics 🖤 ...vibe
Ahhh!😫 How it is too good 😵💫 best! ❤️🔥
❤
love thus song😊😊😊😊😊
Love this song❤❤❤❤❤
Oye hoye...what a song!! I always loved!!
ayee hyee kya hai
Kon kon 2023 mai ye song sun raha hai❤
Mai
Me toh hu na 😂
Ff 👀♥️
Matlab
Hum🤣😂😂
Mad For this song ❤
😍😚🥰💕💞💗💓💝😘💝💓💗💞💕🥰😚😍💕💞💗💓💝😘😘💝💓💗💞💕🥰😚😍😍😚🥰💕💞💗💓💝😘💝💓💗💞💕🥰😚😍😍😚🥰💕💞💗💓💝😘💝💓💗💞💕🥰😚😍
Dil Doobah......!❤️
Superb❤❤
i love slowed music 💖😊
Me to bro
Me too bro
I love old song so much ❤❤❤
So cute song ❤❤❤❤❤❤
I hate slowed & reverb songs but this one is masterpiece ❤❤❤😊
Amazing song I love this song
Best❤
Love❤😊
Uffffff 🙈☺️❣️
I love slowed song
Nice song
Ma to har din sunti hu❤😂
I love this song🎵
😵💫😵💫😵💫😵💫😵💫😵💫
Speed=1.25..❤️❤️
Shabash
🤣
Thanks
😂😂😂
😂🔫
Play this masterpiece at 0.75x ❤
❤️🧡💛💚💙💜🤎🖤🤍💌💕💞💓💗💖💝💘♥️❣️💟
Video at 2minute:30 second
🤍💃
Hm bhi doob gye h❤😂
Dil doba❤❤❤❤❤❤😊😊😊😊is the best on bts pa❤❤
What a song hyyyyye😊
My ❤be like - 1000 time complete one more time plz
My 👂be like - Gand fat giya bs*k😂 sound low kar 😅
Kon kon 2024 mai ye song sunega😅
me
Nice song 🥳🗿
Love From Bangladesh 🇧🇩❤🥳
haram
Uffffgg yar ya song
Oh 😣😣😣 it's touch my heart 💕❤️ i love this song so much 🥰💝💝💝😍💝💝💝💝💝💝💝💝💝💝
Owwwww 🙈🙈🙈🙈🙈🙈🙈🙈
awwwww lululu
Ay hy ye gana........ 🤭🤒
Hey peereemi's 🦋 !!! Hope you will enjoy this beautiful song 💕 !! follow me on insta for updates
Vibes to hai is gaane ma ia to manna padega
Jhrana mera dil duba tuj prrr😘
Perfec song lover❤❤❤
Mind blowing song....❤️🥰💘💝😌
PERFECT IN NORMAL SPEED BUT
IN 0.75 SPEED OYHOY I SWEAR YOU'RE GONNA LOVE IT
MAADHAR HOODDDD
Thanks ❤
Awesome 🎶
❤
Addicted ❤
Kon abhi class 8 me hai or ye gana sun raha hai😂
🙌
What a beautiful song❤
Nice song 😊😊
❤❤❤❤❤
Wah 125
Try at 2x speed 😂u😂😂😂 mast feeling aati hai puri shadi wali band ki feeling aati hai
In December 2023 am listening this ❤❤❤❤❤❤❤❤❤❤❤❤❤
kon kon 2024 ma son rha ha
Who are listening this song in 2024
, raised your hand up.. ❤🎉
2024 in listen❤
My love is 1:25
Nice slowed &reverb (l like it very much❤❤❤)
Yha tu niba nibi kakhe chal rha hai 😢tu yha single ladko ka kya Kam chalo aur me bhi jata ho 😢😢😢😢😢
2024 me ye song kon kon sun raha hai 😂😂😂. Attendance please 😂
😂❤💘
2:30 🤤 Hyeee kashish 💘
🎧💘
Kashish idhr Aao 😍
Oh my god I love it❤❤❤ 😆🤤
2025 ME kon kon Sun raha hai 😂😂
👍 nice song
Thank you
I love slowed song and sad song ❤❤❤
same your fav song
❤❤❤ 1:50
Speed- 1.75😂
Just addicted to dil dooba ♥️
❤❤❤😂
Yeah broo
Yeah broo
Love this song 😊
Inner radius of cylindrical pipe, say r1 = diameter1/ 2 = 24/2 cm = 12cm
Outer radius of cylindrical pipe, say r2 = diameter2/ 2 = 28/2 cm = 14 cm
Height of pipe, h = Length of pipe = 35cm
Now, the Volume of pipe = π(r22-r12)h cm3
Substitute the values.
Volume of pipe = 110×52 cm3 = 5720 cm3
Since Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720×0.6) g = 3432 g or 3.432 kg.
3. A soft drink is available in two packs - (i) a tin can with a rectangular base of length 5cm and width 4cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7cm and height 10cm. Which container has greater capacity and by how much? (Assume π=22/7)
Solution:
(i) Tin can will be cuboidal in shape

The dimensions of the tin can are
Length, l = 5 cm
Breadth, b = 4 cm
Height, h = 15 cm
Capacity of tin can = l×b×h= (5×4×15) cm3 = 300 cm3
(ii) Plastic cylinder will be cylindrical in shape.

Dimensions of the plastic can are:
Radius of the circular end of the plastic cylinder, r = 3.5cm
Height , H = 10 cm
Capacity of the plastic cylinder = πr2H
Capacity of the plastic cylinder = (22/7)×(3.5)2×10 = 385
Capacity of the plastic cylinder is 385 cm3
From results (i) and (ii), the plastic cylinder has more capacity.
Difference in capacity = (385-300) cm3 = 85cm3
4. If the lateral surface of a cylinder is 94.2cm2and its height is 5cm, then find
(i) radius of its base (ii) its volume.[Use π= 3.14]
Solution:
CSA of cylinder = 94.2 cm2
Height of cylinder, h = 5cm
(i) Let the radius of the cylinder be r.
Using the CSA of the cylinder, we get
2πrh = 94.2
2×3.14×r×5 = 94.2
r = 3
radius is 3 cm
(ii) Volume of cylinder
Formula for volume of cylinder = πr2h
Now, πr2h = (3.14×(3)2×5) (using the value of r from (i))
= 141.3
Volume is 141.3 cm3
5. It costs Rs 2200 to paint the inner curved surface of a cylindrical vessel 10m deep. If the cost of painting is at the rate of Rs 20 per m2, find
(i) inner curved surface area of the vessel
(ii) radius of the base
(iii) capacity of the vessel
(Assume π = 22/7)
Solution:
(i) Rs 20 is the cost of painting 1 m2 area.
Rs 1 is the cost to paint 1/20 m2 area
So, Rs 2200 is the cost of painting = (1/20×2200) m2
= 110 m2 area
The inner surface area of the vessel is 110m2.
(ii) Radius of the base of the vessel, let us say r.
Height (h) = 10 m and
Surface area formula = 2πrh
Using the result of (i)
2πrh = 110 m2
2×22/7×r×10 = 110
r = 1.75
Radius is 1.75 m.
(iii) Volume of vessel formula = πr2h
Here r = 1.75 and h = 10
Volume = (22/7)×(1.75)2×10 = 96.25
Volume of the vessel is 96.25 m3
Therefore, the capacity of the vessel is 96.25 m3or 96250 litres.
6. The capacity of a closed cylindrical vessel of height 1m is15.4 liters. How many square meters of metal sheet would be needed to make it? (Assume π = 22/7)
Solution:
Height of the cylindrical vessel, h = 1 m
Capacity of the cylindrical vessel = 15.4 litres = 0.0154 m3
Let r be the radius of the circular end.
Now,
Capacity of the vessel = (22/7)×r2×1 = 0.0154
After simplifying, we get r = 0.07 m
Again, the total surface area of vessel = 2πr(r+h)
= 2×22/7×0.07(0.07+1)
= 0.44×1.07
= 0.4708
Total surface area of the vessel is 0.4708 m2
Therefore, 0.4708 m2 of the metal sheet would be required to make the cylindrical vessel.
7. A lead pencil consists of a cylinder of wood with solid cylinder of graphite filled in the interior. The diameter of the pencil is 7 mm and the diameter of the graphite is 1 mm. If the length of the pencil is 14 cm, find the volume of the wood and that of the graphite. (Assume π = 22/7)
Solution:

Radius of pencil, r1 = 7/2 mm = 0.7/2 cm = 0.35 cm
Radius of graphite, r2 = 1/2 mm = 0.1/2 cm = 0.05 cm
Height of pencil, h = 14 cm
Formula to find the volume of wood in pencil = (r12-r22)h cubic units
Substituting the values we have
= [(22/7)×(0.352-0.052)×14]
= 44×0.12
= 5.28
This implies the volume of wood in pencil = 5.28 cm3
Again,
The volume of graphite = r22h cubic units
Substituting the values, we have
= (22/7)×0.052×14
= 44×0.0025
= 0.11
So, the volume of graphite is 0.11 cm3.
8. A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7cm. If the bowl is filled with soup to a height of 4cm, how much soup the hospital has to prepare daily to serve 250 patients? (Assume π = 22/7)
Solution:
Diameter of the cylindrical bowl = 7 cm
Radius of cylindrical bowl, r = 7/2 cm = 3.5 cm
Bowl is filled with soup to a height of4cm, so h = 4 cm

Volume of soup in one bowl= πr2h
(22/7)×3.52×4 = 154
Volume of soup in one bowl is 154 cm3
Therefore,
Volume of soup given to 250 patients = (250×154) cm3= 38500 cm3
= 38.5litres.
We hope this information on “NCERT Solution for Class 9 Maths Chapter 13 - Surface Areas and Volumes is useful for students preparing for exams. Stay tuned for further updates on CBSE and other competitive exams. To access interactive Maths and Science Videos, download the BYJU’S App and subscribe to UA-cam Channel.
Key Features of NCERT Solutions for Class 9 Maths Chapter 13 - Surface Areas and Volume Exercise 13.6
Solving these solutions help students to:
Students can self-assess their knowledge of the conceptHelps to solve the cylinder concept problemsIt helps the student to find the inner curved surface area of the vessel, the radius of the base of the vessel and determine the capacity of the vesselImprove efficiency in solving the problemsRemember the formulas in an easy wa
Bro why
haan lov day na bhojyam yehi krle sab tu
WTF Bro u on drugs?
Bro ye KYa h
❤
Most favorite tareen song 💕❤✨💘🌙😩💯❤️✨💗👀🌼💕
When he says tere liye hi mar jaounga ❤️❤️
DARK ROOM + HEDPHONE = MOOD FRESH
Kon kon 2024 me sun raha he 😂
I like this song 🤩😍
I more love this song ❤❤❤❤
Gana best song hai❤❤❤
night vibes 🌃🌃🌃🌃😑😑😑