Objects in depth in javascript in hindi | chai aur

Поділитися
Вставка
  • Опубліковано 23 кві 2023
  • Visit chaicode.com for all related materials, community help, source code etc.
    #javascript #hindi
    Sara code yaha milta h
    github.com/hiteshchoudhary/
    Discord pe yaha paaye jaate h:
    hitesh.ai/discord
    Instagram pe yaha paaye jaate h:
    / hiteshchoudharyofficial
  • Наука та технологія

КОМЕНТАРІ • 303

  • @quickSilverXMen
    @quickSilverXMen 11 місяців тому +31

    @1:13 objects intro
    @7:20 object key using symbol datatype
    @9:30 adv.
    @11:00 freezer( ) method in object
    @12:00 symbol snip again

  • @razashah7881
    @razashah7881 Місяць тому +3

    Sir bundle of thanks, yahan tk pohnch kar mujhe wakeyhi lag ra hey k ye course bohat keemti hey, is sey pehley me 2 bar JS ko doosrey mentors sey bhi kar chuka hun, ab third time aapse seekh raha hun, yahan aa kar mujhe aik bat ki zroor realization hui hey, wo ye k ab me ye dekhta hun k jis mentor sey me seekh raha hun, usey khud ko JS ka kitna pata hey, me sabhi mentor ki izzat karta hun, lakin in depth kabhi na kabhi student k dil esa phase zroor ata hey k wo critical way me sochney lagta hey, aik to aapkey teaching style bohat unique hey, or friendly hey, secondly aap apni tarf sey bharpoor try kartey hen k me jo bat samjha raha hun, wo student k dimagh me literally ghuss jaey.

  • @ayaniegain
    @ayaniegain 11 місяців тому +21

    The uniqueness of your course, you not only teach the topic but also learn the exact use of it.🥰

  • @HydroJudge
    @HydroJudge 10 місяців тому +7

    Iss lecture mein jo sir ne concepts bataaye hain woh sach mein in depth hain. Notes banaake aur ache se samajh aata hai. This series is lit.

  • @user-eq6mj3fk9x
    @user-eq6mj3fk9x 11 місяців тому +7

    finally found a great teacher on youtube , really really helpful

  • @Quickkit
    @Quickkit Рік тому +16

    @15:15 hello sir,undefined is the return value of the function greeting( ).

    • @farazahmed1668
      @farazahmed1668 11 місяців тому +2

      Q k humne dar-asal value ko print karwaya hai na k return, to jab kuch b return nahi hoga... to by default undifined he return hoga.

  • @abdush5830
    @abdush5830 Рік тому +9

    love you sir..ye Internet ki best series hai JS ki..Jitna aap deep explain kr rahe hain utna kisi ne ni kia hai Yt pr...very thanks Sir

  • @user-ob8cv5wy7g
    @user-ob8cv5wy7g 7 місяців тому

    omg i've seen such a high quality oontent like this on yt , i'm just getting jealous that many people can have access to this video and they'll be getting more info....damnn bro,this playlist is lit

  • @Sgsbakers
    @Sgsbakers 9 місяців тому +28

    in greeting & greetingTwo functions you log messages to the console but don't return anything, so they implicitly return undefined as an output after every console. But when we use return keyword in functions instead of console.log it will not output 'undefined'.

    • @agentNirmites
      @agentNirmites 6 місяців тому

      Why he didn't get it?

    • @parvahuja7618
      @parvahuja7618 4 місяці тому

      true, because whenever we are using { } we have to explicitly write return whereas when simply using ( ) we do do not need to write it

  • @vlogs4u968
    @vlogs4u968 11 місяців тому

    Thank you sir ji main thoda research kiya ki UA-cam pr available js ki jyadatar playlisto pr really sir ji sabse alak hai aapki playlist concept ko apne alak hi tarike se bataya hai bahut bahut dhanyavad sir ji

  • @tusharsachdeva3654
    @tusharsachdeva3654 7 місяців тому +5

    Thanks! Awesome way of explanation man. Damn

  • @cherishkansara7851
    @cherishkansara7851 4 місяці тому +7

    Sir woh last mein undefined isliye araha hai kyuki function Console log kar raha hai na ki kuch return kar raha hai or an function ko console log mein print karwa rahe hai toh isliye undefined araha hai

  • @vasudev3744
    @vasudev3744 4 місяці тому +4

    sir the undefined value that is being printed on the screen is bcoz u r printing the return of the function which is not defined
    console.log(JsUser.greeting()) is wrong instead use JsUser.greeting() for calling the function

  • @babarshabbir2554
    @babarshabbir2554 2 місяці тому +1

    "Excellent tutorial, covers JavaScript objects' depths neatly! Loved the chai tea and code puns. #JavaScript"
    Note: This comment is written in Hindi script, which would look like - "पर excellant ट्यूटोरियल है, सक्षम JavaScript objects की depths निग्रानी करता है! Chai tea और code शब्दों से प्यार लगाया। #JavaScript"

  • @tech_channel110
    @tech_channel110 11 місяців тому +1

    Best video on internet
    Shandar lecture
    Keep making such an amazing video lecture for us
    These lectures are very helpful for us

  • @learning-shaharyar550
    @learning-shaharyar550 2 місяці тому +6

    10:00
    The syntax of declaring a symbol inside object still does not seem to be correct because upon
    console.log(typeof JsUser[mySym]);
    // It returns *string* , whereas ideally it should return Symbol as its dataType.

    • @hobabu7066
      @hobabu7066 2 місяці тому

      Same doubt, have you got any answer ?

    • @shaharyaransari4887
      @shaharyaransari4887 21 день тому

      @@hobabu7066 The Explaination was quite confusing.
      However following code prints type of symbol:
      // Objects
      let mysymbol = Symbol('Key1');
      let myobj = {
      name: "Shaharyar Ansari",
      id: 1232,
      [mysymbol] : mysymbol
      }
      console.log(typeof myobj[mysymbol]);

    • @shaharyaransari4887
      @shaharyaransari4887 21 день тому

      The only reason for using Square brackets inside an object is to assign a dynamic key.
      Forexample:
      let key = 'dynamicKey';
      let value = 'This is a dynamic value';
      let obj = {
      [key]: value
      };
      console.log(obj); // Output: { dynamicKey: 'This is a dynamic value' }

    • @user-np8rk3nh7q
      @user-np8rk3nh7q 21 день тому

      i think jaldbazi mei sir bhool gye

    • @VivekSharma-ef1um
      @VivekSharma-ef1um 5 днів тому

      @@shaharyaransari4887 thanks man it woked

  • @biswaranjansahu66
    @biswaranjansahu66 5 місяців тому

    There are no words for your teaching skill and knowledge sir.

  • @milindchaturvedi9770
    @milindchaturvedi9770 4 місяці тому

    The best series on the internet !

  • @AmitRaj.2
    @AmitRaj.2 10 місяців тому +11

    The full name has space in between and thus it cannot be acessed using . Notation but if there is no space and if we type the key in string expression like 'fullname' it can be accesed using . Notation

  • @md.talibansari7388
    @md.talibansari7388 8 місяців тому +8

    @14:51 "undefined" is appearing because the function is not returning anything, and you have called the function inside the console.

  • @NiteshChaudhary07.
    @NiteshChaudhary07. 8 місяців тому +1

    Mene bahut video's dekhi par maja nahi aya apki video dekhta hu to sach me apke video's achhe lagte he aur helpfull he thank you

  • @AbdulHameed-to3sg
    @AbdulHameed-to3sg 10 місяців тому +1

    no doubt sir you are great teacher

  • @harishankarthakur388
    @harishankarthakur388 9 місяців тому +1

    This series is very addictive❤

  • @rizwansaifi3590
    @rizwansaifi3590 2 місяці тому +1

    7:02 the issue with the object property "first name" when trying to access it as (object.first name ) is because of space , if the property name was "first" then in that case it is easily accessible as object.first or object["first"] both will work . As any property name is coerced as string

  • @set1675
    @set1675 9 місяців тому

    THIS SERIES IS SO ADDICTIVE , MY GOD😍😌

  • @aaaaaannnnnnnaaaaaannnnnnn
    @aaaaaannnnnnnaaaaaannnnnnn 4 місяці тому +1

    *Sir really React complete karney kay baad dekh raha ho concepts ko clear karney kai liyay ab samjh araha hai in depth course ka matlab😃*

    • @saadkashif880
      @saadkashif880 4 місяці тому

      same bhai react course complete kia hay or ab ye dekhna start kia or boht maza aaraha

  • @formeusgamer4327
    @formeusgamer4327 Місяць тому

    Buhat achy sy apny explain kra Hai,🥰

  • @CodeWithDhruv-sy5bs
    @CodeWithDhruv-sy5bs 5 місяців тому +1

    The reason of undefined is because the greeting function is not returning anything it is just priniting thats why the return type is undefined

  • @SyedAsif08
    @SyedAsif08 7 місяців тому

    understood objects in js very well.....................................

  • @usama5619
    @usama5619 9 місяців тому

    thank you!
    great teacher !

  • @shouviksarkar7900
    @shouviksarkar7900 Місяць тому

    14:51 undefined is bcz in greeting function we already had console.log('message') ...but while calling the function you used console.log(greeting()) again. due to to console.log() we are getting an undefined. Just write gretting() and there will be no undefined.
    same goes for 17:05

  • @Bca.Wallah
    @Bca.Wallah 4 місяці тому

    This is literally The best javascript playlist on UA-cam.
    Hope the way you guide the students will truly bring a revolution.
    Lots of love Sir😍❤❤

  • @nivilsangwan7352
    @nivilsangwan7352 4 місяці тому

    his eyes have that dark thing around them indicating the tiredness. BTW I am loving your videos and I am actually a 9th grade student and am able to understand almost everything. This course is better than any other course I've seen on YT. Thank You Sir.

  • @SuryaKarigar
    @SuryaKarigar 10 місяців тому

    Wow [ ] can take my job 😂😂 I better need to be ready for Interview Sir. It’s creating fear and confidence at the same time

  • @ranjeetchoudhary112
    @ranjeetchoudhary112 11 місяців тому

    I was waiting this type of video

  • @mansoorafzal4344
    @mansoorafzal4344 6 місяців тому

    Excellent Work Done bro

  • @YamrajShrestha
    @YamrajShrestha 10 місяців тому +4

    I've been fortunate to have incredible guidance on my journey to becoming a full-stack programmer. Learning with the help of this amazing tutorial, I've been steadily mastering JavaScript, and it's been an enlightening experience. A big thank you to my learning companion for being there every step of the way.

  • @user-kk9if6ru1l
    @user-kk9if6ru1l 12 днів тому

    @7:02 you can also access by dot method
    let a={ "name":"ahmed",
    'age':20}
    console.log(a.name) // ahmed
    console.log(a[name]) // ahmed
    conclusion:
    if you give "key" in string or without string it wiill access by both two methods

  • @shashankkumarpandey4184
    @shashankkumarpandey4184 6 місяців тому +2

    15:00 , you are using console.log(console.log()) thing thats why undefined coming, just like python when you do print(print("Hi")), it gives hi then none. print statement inside print statement.
    i don't know if my logic is correct but i can think of this only right now.

    • @lokinagure
      @lokinagure 5 місяців тому +1

      Bilkul sahi he.

  • @munawarminhas7982
    @munawarminhas7982 9 місяців тому +2

    in my case also there is 12:29 am haha,,, you are doing great sir, I eagerly await the backend series.

    • @chaiaurcode
      @chaiaurcode  9 місяців тому +10

      Kya din, kya raat. Agr mza aa rha to kaam krenge hi

    • @munawarminhas7982
      @munawarminhas7982 9 місяців тому

      sir the best thing is that we never get bored by your videos,, main ny bht sary courses starrt kiye is sy phly but end kbhi nahi hua koi bhi , but jb sy apka js course dekhna start kiya hai aj 35th video hai within one week,almost 4-6 hours+ daily screen k samny gzr jaty hain time ka pta nahi chlta ,smj b aa jati or practice b ho jati@@chaiaurcode

  • @ManishGupta-qd8fl
    @ManishGupta-qd8fl 8 днів тому

    'undefined' is shown , because we call the method in console.log(jsUser.greeting()) and we console also in greeting method. It will removed if we directly call method without console. eg; jsUser.greeting()

  • @vaibhavpalaria5821
    @vaibhavpalaria5821 11 місяців тому

    Sir ji pranam
    Thanks for a superb video

  • @JavidSumra786
    @JavidSumra786 Рік тому +9

    Sir I think greeting function giving undefined because of we are printing this function so it expect some value

    • @KrishnaArt13
      @KrishnaArt13 Рік тому

      console.log("=======jsUser.greeting()====",jsUser.greeting());
      console.log("=====jsUser.greetingTwo()======",jsUser.greetingTwo());

  • @prakhargupta4347
    @prakhargupta4347 Рік тому

    maza aagaya. thank you so much sir.

  • @shashankmishra9014
    @shashankmishra9014 2 місяці тому

    undefined @15:10 is due to the fact that console.log print what is returned when so in this case when greeting is used nothing is returned so fun returns undefined which is printed.

  • @srijareddy1088
    @srijareddy1088 Місяць тому

    Thank you very much sir

  • @fawaz_exe
    @fawaz_exe 22 дні тому

    @ 14.46 It gives undefined as we did not use return keyword there. If we use return it will not print undefined.

  • @hamvlogwale
    @hamvlogwale 4 місяці тому

    love this playlist

  • @Abhinav-ep7vb
    @Abhinav-ep7vb Місяць тому

    Gold Js Content ON YT . keep Creating more content sir

  • @BitFire007
    @BitFire007 4 місяці тому

    "Chai aur Code, you've successfully turned me into a JavaScript enthusiast. Your tutorials are gold!"

  • @user-np8rk3nh7q
    @user-np8rk3nh7q 21 день тому

    all the comments solve my residual doubts thank you guys

  • @kazitanim007
    @kazitanim007 7 місяців тому +2

    When u call the function directly instead of console.log - "undefined" doesn''t show on the console.

  • @krishnavamsi1126
    @krishnavamsi1126 2 місяці тому

    THANKS A LOT BRO

  • @abdulajim9633
    @abdulajim9633 10 місяців тому

    Very nice js Course ✔✔❤❤❤❤❤❤

  • @codethics4033
    @codethics4033 3 місяці тому +1

    @10:09 the methode that you told still shoing that in string even i dicleared it correct way .

  • @vivekbhakhri735
    @vivekbhakhri735 6 місяців тому

    Awesome!!

  • @jrahul42
    @jrahul42 12 днів тому

    Great video

  • @technoyash2970
    @technoyash2970 9 місяців тому

    Thank you so much bhaiya

  • @Solanki493
    @Solanki493 Рік тому

    Chai aur code main mera swagat hi

  • @WatchNotchK2S
    @WatchNotchK2S 5 місяців тому

    Sir , JsUser.greeting(); should be used to call the function and print the value in it. as you console.log(JsUser.greeting()) & console.log(JsUser.greetingTwo()); it want function to return a value and give the answer , thus you get udefined in the browser ( Correct me if i am wrong )

  • @nitishsingh925
    @nitishsingh925 9 місяців тому +1

    Symbol is new to me 💯

  • @nikulkumar6224
    @nikulkumar6224 Рік тому

    Finally Back ❤

  • @ammarsiddiqui6486
    @ammarsiddiqui6486 11 місяців тому

    sir is tutorial very help full for me jo me chz ki sekhe oski practise kasie kare for eg aj hum ne object seekh hai?

  • @MonikaKumari-er4de
    @MonikaKumari-er4de 4 місяці тому

    Thank you sir❤️

  • @aryangaur228
    @aryangaur228 11 місяців тому

    Thank you very much sir!!

  • @ritushrivatri6865
    @ritushrivatri6865 4 місяці тому

    Awesome 😶‍🌫

  • @saumyadipdutta5419
    @saumyadipdutta5419 4 місяці тому

    Hello @Hitesh Sir, I think undefined in the last , is coming from console.log(). If we write JsUser.greeting() only then undefined will not show

  • @deepakmishra96
    @deepakmishra96 Рік тому

    Great video!

  • @kamilsiddiqui4252
    @kamilsiddiqui4252 5 місяців тому

    symbol is getting accessed without using square brackets in both the places in 2024 has the syntax for symbol changed ? I guess so as I used typeof() without square brackets it shows that it is a symbol datatype.

  • @user-ut8wp3uw7y
    @user-ut8wp3uw7y 4 місяці тому

    @6:55 its giving access by full name by using dot

  • @Mahin_katariya
    @Mahin_katariya 3 місяці тому

    As of 2024 the part where sir wrote at 6:33 " fullname " : " hitesh choudhary " and while we were trying to access it using the dot method it wasn't accessing but now we can access it using the dot method.✅

  • @FairyhunterGG
    @FairyhunterGG 10 місяців тому

    Why can't I use the 'this' keyword in an object method with an arrow function?

  • @BABABENNETT
    @BABABENNETT 4 місяці тому

    hitesh sir op

  • @lovetriangle3232
    @lovetriangle3232 3 місяці тому

    Thankyou for theamazing video sir but at 17:05 ,the output undefined occurrs bcoz in the line no 38 you used console.log to print a function(jsuser.greeting()), function directly excute when it called just by jsuser.greeting(),why we need to write console.log(jsuser.greeting()). i guess you miss that part sir.

  • @supernovaveda211
    @supernovaveda211 Місяць тому

    10:20 me jo sir , key ka syntax shi kiye hai taki uska type symbol aa jae. Lekin syntax shi krke firse check kiye to type string hi hai.

  • @rjsuraj1205
    @rjsuraj1205 9 місяців тому

    hey can anyone explain as Sir said constructor creates singleton objects , But constructors are used to create instances of objects, not specifically singleton objects.I am confused can anyone explain plz

  • @sanjoyal_world_07
    @sanjoyal_world_07 Рік тому +1

    Guru jee ..next video upload kijiye js chapter 49 k baad se ...

  • @f50achievers10
    @f50achievers10 7 місяців тому

    We are getting undefined value because of function log,
    When we just call the function..it won't be undefined...😊

  • @robot6716
    @robot6716 Місяць тому

    @17:09 undefined in console becuase at line number 37 and 38 in console log greeting() and greetingTwo function are called a
    which do not return anything explicitly and by default "undefined". is returned.

  • @RiteshKumar-yq4cx
    @RiteshKumar-yq4cx 5 місяців тому

    wts the meaning of Array.from() , does it mean we are calling a from() method from Array object

  • @ECommerceNews
    @ECommerceNews 8 місяців тому

    Function execute hone k baad jo "undefined" print ho raha hy wo function ki return value hy. am i right?

  • @pratiklondhe3696
    @pratiklondhe3696 3 місяці тому

    at 10:37 if i write console.log(typeof jsUser[mySym]); this then it also give me string type?

  • @sahilgupta7001
    @sahilgupta7001 3 місяці тому +1

    the function was showing undefined because you logged a function which was not returning anything, how could you not get this simple thing

  • @krishnaanandiswaraa
    @krishnaanandiswaraa 10 місяців тому +37

    im sorry to say sir , but problem , you alwasy said that , you explain in depth , but here in object sometime in vedio you type some syntax but dont explain them

    • @apnipathshala7866
      @apnipathshala7866 6 місяців тому +6

      You can't learn objects is just 19 mins...you have to give 1 to 2 week for this... practice
      Vdo is only to take an overview of objects

    • @abirroy1978
      @abirroy1978 6 місяців тому +1

      Bro If you want to depth understanding please go search harsith vasisth javascript full length video you will get depth in every thing..

    • @Bca.Wallah
      @Bca.Wallah 4 місяці тому +1

      Bhai If you really want to learn JavaScript, you will have to work hard yourself. Read documentations. as sir says in all the lectures.
      Because there is no concept of spoon feeding here.
      hope all your doubts are cleared.

    • @user-ub2ol5ou7e
      @user-ub2ol5ou7e 4 місяці тому

      Objects in javasript....
      Thuje objects hee patga nahi tho kya faidha bhai..
      OOPSnahi patha hai kya??

    • @GOJOANDSUKUNAFAN
      @GOJOANDSUKUNAFAN 6 днів тому

      Yea you all are glazers he doesn't explain shit

  • @bngdtutorial2947
    @bngdtutorial2947 3 місяці тому

    when i am writting jsuser.greeting(); then it simply printing the result but, while writting console.log( jsuser.greeting()); then it printing the result along with undefine. It may due to we are not returning any value and still trying to console.log() .

  • @akshaybadwaik-nl5ng
    @akshaybadwaik-nl5ng 3 місяці тому

    thank you

  • @manemanoj3068
    @manemanoj3068 Рік тому

    Just insane..

  • @pushpendra10001
    @pushpendra10001 9 місяців тому +1

    sir tell me one thing after using square brackets it still give me type of symbol is string why ???? it only show under the object but if check the sybol type of on console it shows it is string

    • @varchasvh02
      @varchasvh02 4 місяці тому

      I was thinking the same.

  • @md.abidullahmuhib
    @md.abidullahmuhib 3 місяці тому

    Hi there, in this lecture we are getting undefined because we are executing a function inside console.log();. By executing JsUser.greeting(); we are printing "Hello JS user". And the execution value of JsUser.greeting() = undefined. Which we are printing by console.log(JsUser.greeting());.
    Waiting for a reply. Correct me if I am wrong. Love from Bangladesh 🇧🇩 .

  • @karanbhandari1534
    @karanbhandari1534 9 місяців тому

    the undefined in the last part was occurring because he was logging the invocation of the function..?

  • @soumadip_skyy_banerjee
    @soumadip_skyy_banerjee 11 місяців тому +1

    🔥

  • @amansayer4943
    @amansayer4943 11 місяців тому +3

    15:15 We are not returning to print it, we just need to call the function with object name ex: User.greeting();

    • @MCA_HimanshuSeth
      @MCA_HimanshuSeth 10 місяців тому +1

      yeah & the point is that , the function doesn't return any value that is why it is printing undefined

  • @mahadevprasadpal7829
    @mahadevprasadpal7829 4 місяці тому +1

    Did not get the "symbol" part. Can anyone please help me understand?!

  • @ShudhanshuShree
    @ShudhanshuShree 5 місяців тому

    undefined is coming because the function greeting and greetingtwo is not returning anything and you are printing the output inside console.log(greeting());

  • @kholaseerat2385
    @kholaseerat2385 2 місяці тому

    When i searched google about singleton , i found out that object literals are singleton ut you are saying they are not can u please clear this doubt

  • @mrinvisible4095
    @mrinvisible4095 5 місяців тому

    10:31 Sir, to use Symbol as a key, what if we use Map data structure!?

  • @anonymous6501
    @anonymous6501 Місяць тому

    const ob1 = {
    name : "Prateek",
    age : 30,
    "add" : "Prayagraj"
    }
    console.log(ob1["add"]);
    console.log(ob1.add);
    I checked today Now both syntax is working.

  • @shanksiuu
    @shanksiuu 5 місяців тому

    15:00 maybe it's becuz of the absence of return value
    JsUser.greeting = function(){
    return "Hello JS user";
    }
    JsUser.greetingTwo = function(){
    return `Hello JS user, ${this.name}`;
    }
    console.log(JsUser.greeting());
    console.log(JsUser.greetingTwo());
    OR
    function jsUser (name) {
    console.log(`Hello JS user, ${name}`)
    }
    jsUser("Hitesh")

  • @All-about-lea_rning
    @All-about-lea_rning Місяць тому

    the reason of undefined kyu ki aap ne function me console kiya hai aur execute ke time per bhi aap console kar rhe hai ya to execute ke time console mat kijiye ha to function me se console ko hata ke return kardo

  • @user-hf6om6ts1q
    @user-hf6om6ts1q 2 місяці тому

    15:09 ye undefined line 34 se aa raha h qki at line 30, function greeting is not returning anything.