De Broglie Hypothesis | De Broglie Wavelength

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  • Опубліковано 22 січ 2025

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  • @ManochaAcademy
    @ManochaAcademy  5 місяців тому

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  • @desmonderickson2232
    @desmonderickson2232 11 місяців тому +14

    I want to use this opportunity and thank the management of Manocha Academy because of them I did exceptional 🎉in my physics WASCCE paper words can’t explain how grateful I am ❤️🙏🏾 once again mammoth thanks to you Sir 🙏🏾

    • @ManochaAcademy
      @ManochaAcademy  11 місяців тому +4

      Congratulations!! Great to hear that you did in your Physics paper! Do share our channel with your friends!

    • @desmonderickson2232
      @desmonderickson2232 11 місяців тому +1

      @@ManochaAcademy Yes Sir and they also did well

    • @franklinemix8048
      @franklinemix8048 2 місяці тому

      Woooow

  • @marycatherine296
    @marycatherine296 11 місяців тому +4

    Pls add more videos in math..it is very helpful to my son..you have taught in depth which the school fails to

  • @janakicjoby7607
    @janakicjoby7607 3 місяці тому

    OMG guys my 10 years in STEM in one video omg this person deserves so much more recognition!!! lots of love and gratefulness

  • @franklinemix8048
    @franklinemix8048 2 місяці тому +1

    God will continue to bless you as long as you exist both you and your family and generations.

  • @kottekotravikumar8906
    @kottekotravikumar8906 11 місяців тому +1

    It's energy that was thought to be continuous, not matter.

  • @বাঙালি_মানেই_বুদ্ধিমান

    Thanks 🙏 from Bangladesh 🇧🇩. Does that means that all object r high Frequency least wavelength? 2. All objects r frozen light?

  • @sriritwikshastry9603
    @sriritwikshastry9603 11 місяців тому +5

    The quality of these videos! My god! Fantastic! 11th videos are very intresting even to the 10th graders!

  • @KamathamSanthoshKumar
    @KamathamSanthoshKumar 27 днів тому +1

    The answer for change in wave length is 40%
    Wavelength=h/(2mKE)1~²
    By using this we can calculate

  • @anthonymckinney8173
    @anthonymckinney8173 4 місяці тому +1

    Let's dive deeper into the concept of "systems" and their role in the context of de Broglie wavelengths and quantum mechanics.
    What is a system in physics?
    In physics, a system is simply a collection of objects or entities that we choose to focus our attention on. It's a way of mentally separating a part of the universe from the rest, so we can analyze its behavior and interactions more easily.
    Types of Systems
    * Isolated System: No exchange of matter or energy with its surroundings. A perfectly isolated system is an idealization, but some systems come close (e.g., a well-insulated thermos).
    * Closed System: Can exchange energy but not matter with its surroundings (e.g., a sealed container with a hot liquid).
    * Open System: Can exchange both matter and energy with its surroundings (e.g., a living organism).
    Why Systems Matter in Quantum Mechanics
    When we talk about a particle's de Broglie wavelength interacting with a system, we're essentially talking about how the particle's wave function interacts with the potential energy landscape or boundaries defined by that system.
    * Confinement: Systems can confine particles to specific regions of space, altering their wave functions and energy levels. This leads to phenomena like quantum confinement in nanostructures, where the particle's behavior is strongly influenced by the system's boundaries.
    * Scattering and Diffraction: When a particle interacts with a system, its wave function can be scattered or diffracted, revealing information about the system's structure. This is the basis for techniques like electron microscopy and neutron scattering.
    * Tunneling: In quantum mechanics, particles can "tunnel" through potential energy barriers, even if they don't have enough classical energy to do so. The probability of tunneling depends on the particle's de Broglie wavelength and the shape of the barrier, which is often determined by the system's properties.
    Choosing the Right System
    The choice of system depends on the specific problem or phenomenon we're interested in.
    * Single Particle in a Potential: We might consider a single particle (e.g., an electron) interacting with a potential well or barrier created by some external field or structure. This allows us to focus on the particle's wave function and energy levels within that specific environment.
    * Many-Particle Systems: In more complex systems, we need to consider the interactions between multiple particles, which can lead to collective phenomena like Bose-Einstein condensation or superconductivity.
    * Open Systems: In some cases, we need to account for the exchange of matter and energy with the surroundings, which can lead to decoherence and other effects that influence the quantum behavior of the system.
    Key Takeaway
    The concept of a "system" provides a framework for analyzing the behavior of particles in quantum mechanics. By defining the system and its boundaries, we can understand how a particle's de Broglie wavelength interacts with its environment, leading to a wide range of quantum phenomena.
    Let me know if you'd like to explore any specific examples or aspects of systems in more detail. I'm here to help!

    • @MrThemneboss
      @MrThemneboss Місяць тому

      @anthonymckinnev8173 Amazing comment, I really appreciate it! This sheds light on a very important and usually overlooked concept.

  • @franklinemix8048
    @franklinemix8048 2 місяці тому

    Change in wavelength is (9x10-¹¹) that's exactly 27.3% decrease. This when you truncate the numbers while solving.
    But, when you decide not to truncate, estimate or approximate. The percentage change is 28.57142857143% exactly.

    • @franklinemix8048
      @franklinemix8048 2 місяці тому

      The wavelength originally is 3.3×10-¹⁰m but as K.E(2.202x10-¹⁸) increased by 96% it changed the wavelength down to 2.4×10-¹⁰m that's a difference of 0.9×10-¹⁰ in correct standard form 9.0x10-¹¹. 23.7%. K.E is 1/2mv² where m(mass) is 9.1x10-³¹kg and v(velocity)=2.2x10⁶m/s.

  • @CorneliusDan
    @CorneliusDan Місяць тому

    Thanks so much now I can go on and do my assignment.

  • @RasheduzzamanRuhid
    @RasheduzzamanRuhid 3 місяці тому

    It was a very helpful video. Love from Bangladesh. ❤

  • @Varunzzz
    @Varunzzz 11 місяців тому +13

    Sir ....i watched your video when I was in 9th standard
    That was so clear
    After 5 years....
    I got your video from suggestions ❤
    So I'm an old student of your UA-cam class😂❤

  • @srinivasanv7951
    @srinivasanv7951 6 місяців тому

    Sir, you have helped me so much through all you videos. Thank you so much!🎉🎉

  • @angadsahoo2357
    @angadsahoo2357 11 місяців тому +1

    Thanks you sir for your kindly information to students ❤❤❤🎉🎉🎉😅😅😊😊😊

  • @bhaktabachalabehera2654
    @bhaktabachalabehera2654 11 місяців тому +35

    I wanna become quantum scientist thanks sir for this video

    • @ManochaAcademy
      @ManochaAcademy  11 місяців тому +12

      Awesome to hear that ☺️

    • @bhaktabachalabehera2654
      @bhaktabachalabehera2654 11 місяців тому +1

      Can u tell me the roadmap to become along with marine biologist?

    • @amreedit
      @amreedit 7 місяців тому +2

      Niga it ain't that much easy as said

    • @sunilrai500
      @sunilrai500 5 місяців тому +1

      I guess you don't know the dot of quantum. Sir ki video toh khud sur confuse lag raha hae. Theory is not physics it's understanding.

    • @MafiabossELdijas
      @MafiabossELdijas 5 місяців тому

      😂​@@amreedit

  • @pukhrajmansion8445
    @pukhrajmansion8445 11 місяців тому +1

    Good 👍
    Next video on
    What is matter
    What is Physics definition area dimensions scope philosophy Physical world and it's measurements Physics day Physics history
    Physics Father

  • @iron-cut6436
    @iron-cut6436 11 місяців тому +3

    the lecture i wanted thank you

  • @24dipika
    @24dipika 4 місяці тому +1

    the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

  • @shiekh366
    @shiekh366 8 місяців тому +1

    Sir from 11 lakh to 12 lakh congratulations

  • @johnboscochigoziem6921
    @johnboscochigoziem6921 Місяць тому

    God bless you sir ❤

  • @AnicheIjeomaJennifer
    @AnicheIjeomaJennifer 8 місяців тому +2

    5.0127×10^-19

  • @BELAGALI4U
    @BELAGALI4U 11 місяців тому

    Great class about quantum mechanics ❤

  • @simegnewtesfaye4455
    @simegnewtesfaye4455 10 місяців тому

    If we let the first kenetic energy is KE1 and The second kenetic energy is KE2 then the answer will be -0.2hKE1m
    h =Planck's constant
    m=the mass of an electron
    KE1=the first kenetic energy
    I hope you will give me a correction if I'm wrong 🙏
    Thanks for the video I swear this video is so amazing

    • @MukulSaini-iv7fr
      @MukulSaini-iv7fr 8 місяців тому

      bro answer is -.03 aa raha h mera to
      kya tum bataoge kaise kiya tumne

  • @givemoremutswiri8541
    @givemoremutswiri8541 11 місяців тому +1

    You are a star sir

  • @m.rakeshroshan9601
    @m.rakeshroshan9601 11 місяців тому +1

    What is Quantum sir ?
    Is it something like quantified or will it can be other way said as made into mathematically expressible once Sir ?

  • @KumarUtkarsh-u2y
    @KumarUtkarsh-u2y 3 місяці тому

    Great explanation❤ liked this video

  • @AvishekYadav-j6m
    @AvishekYadav-j6m 11 місяців тому +4

    Sir one video on weightless

  • @nathanakpome6401
    @nathanakpome6401 10 місяців тому

    Sir Please do a video on electromagnetic induction

  • @NtezeituAmbrose
    @NtezeituAmbrose Місяць тому

    Thank you very much sir

  • @ಅರ್ಪಿತಾ-ತ4ಷ
    @ಅರ್ಪಿತಾ-ತ4ಷ 5 місяців тому

    Are number of electrons reduced when metal was exposed to light ?

  • @RinahNdombi
    @RinahNdombi 2 місяці тому

    Can you do relationship between schrodinger wave equation and de broglie equation?

  • @Chemysterious10
    @Chemysterious10 11 місяців тому

    Sir from which website you use simulations like you use photoelectric effect in this video ??

  • @Mmpoyalo
    @Mmpoyalo 4 місяці тому +15

    λ = h / p
    where h is Planck's constant.
    Since kinetic energy (KE) is related to momentum by:
    KE = p^2 / (2m)
    where m is the mass of the electron, we can express the change in kinetic energy as:
    ΔKE = (p2^2 - p1^2) / (2m)
    Given that the kinetic energy increases by 96%, we can write:
    ΔKE = 0.96KE1
    where KE1 is the initial kinetic energy.
    Substituting the expression for KE in terms of momentum, we get:
    (p2^2 - p1^2) / (2m) = 0.96(p1^2 / (2m))
    Simplifying, we get:
    p2^2 = 1.96p1^2
    Taking the square root of both sides:
    p2 = √1.96p1 ≈ 1.4p1
    Now, using the de Broglie equation, we can find the change in wavelength:
    λ2 = h / p2
    = h / (1.4p1)
    ≈ 0.71λ1
    So, the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

  • @srinivasanv7951
    @srinivasanv7951 6 місяців тому

    Amazing🎉

  • @AtemkengSonna-im6rg
    @AtemkengSonna-im6rg 11 місяців тому

    Please can help me on how to identify colour in chemistry 9:55

  • @MARADONA_20
    @MARADONA_20 11 місяців тому

    Sir I want you to teach the topic "state of matter". Thank you.

  • @RinahNdombi
    @RinahNdombi 2 місяці тому

    Nice one!

  • @fathimahafsausman
    @fathimahafsausman 6 місяців тому

    Clear explanation sir :) Sir can i please know the answer for the homework question? Thanks in advance sir.

  • @adityalokhande6484
    @adityalokhande6484 3 місяці тому

    Sir the answer would be 5.01×10^-19 .

  • @TejashriSwami
    @TejashriSwami Місяць тому

    Thank you sir

  • @panthaganiniharika3208
    @panthaganiniharika3208 8 місяців тому

    the percentage change in wavelength is 2.14%.

  • @dank3470
    @dank3470 10 місяців тому +1

    what is the answer for the question? please help ?

  • @maheshwarisingh6295
    @maheshwarisingh6295 2 місяці тому

    1.58×10^-15

  • @zakmatew
    @zakmatew 5 місяців тому

    The fact that the energy levels are quantized doesn’t mean that there are particles. Rather, it is all waves but “quantized waves” as I call them. They give the false impression of particles but do account for the so called “dual nature of particles”.

  • @deku_ik_7
    @deku_ik_7 10 місяців тому

    Change in wavelength=2/5 and %change in wavelength= 40%

  • @ayushkumar27703
    @ayushkumar27703 11 місяців тому +1

    Sir very nice video..heart please ❤

  • @KamathamSanthoshKumar
    @KamathamSanthoshKumar 2 місяці тому +1

    Sir question ki answer kuda cheppandi

  • @SayaniChattaraj
    @SayaniChattaraj 9 місяців тому

    Thank you.... your explanation is crystal clear

  • @vaibhavprajapati1835
    @vaibhavprajapati1835 11 місяців тому +2

    Wavelength will decrease by 28.5 %
    Sir please pin if ans is correct ❤

  • @Nathyfunnyplanet
    @Nathyfunnyplanet Місяць тому

    Please i can't get it explain for me

  • @divyaanji2361
    @divyaanji2361 11 місяців тому +1

    Could you explain structure of atom lesson sir😅😅😅

    • @BhaskarGupta.
      @BhaskarGupta. 11 місяців тому

      Exams aa gaye h aur tujhe Lecture chahiye 🤣🤣🤣🤣😂😑

  • @AvishekYadav-j6m
    @AvishekYadav-j6m 11 місяців тому +2

    ❤❤❤❤❤

  • @umeshkumartiwari9431
    @umeshkumartiwari9431 6 місяців тому

    0.13383×10-34

  • @THEGOATS90
    @THEGOATS90 11 місяців тому

    we want the bloopers 😛

  • @oluwajobaOkewole
    @oluwajobaOkewole 5 місяців тому

    27%

  • @Sigma__Mathematics
    @Sigma__Mathematics 11 місяців тому

    Sir please Give tha answer of last Question

  • @Lily20008
    @Lily20008 11 місяців тому

    Sir is the change in wavelength 92.8%

  • @Bullseyeanime
    @Bullseyeanime 9 місяців тому

    0.287 decrease

  • @gotobawa
    @gotobawa 10 місяців тому +3

    28.57% dicreases

  • @ahmettiti1459
    @ahmettiti1459 10 місяців тому

    kral bir türk olarak alt yazıya cevirip kesintisiz izledim :)

  • @KieKie-lj8ks
    @KieKie-lj8ks 9 місяців тому

    I got 51%....i.e the wavelength decreases by 51%

  • @alexnjibu7232
    @alexnjibu7232 Місяць тому

    -28.6%

  • @nitasharma8308
    @nitasharma8308 6 місяців тому

    The answer is:
    1.4 times the initial wavelength.
    i.e.,
    Final wavelength=1.4 initial wavelength
    or,
    λ'=1.4λ.
    Hope it's true.
    Please let me know.

  • @SHURPARMAR
    @SHURPARMAR 7 місяців тому

    kk

  • @k2creation481
    @k2creation481 6 місяців тому

    98% decrease

  • @ShyamaliWijesinghe-t1o
    @ShyamaliWijesinghe-t1o 6 місяців тому

    71.428% increase in wave length.

  • @SARKET670
    @SARKET670 9 місяців тому

    কী গাবাই।

  • @Neymar_JR713
    @Neymar_JR713 11 місяців тому +2

    First

    • @ManochaAcademy
      @ManochaAcademy  11 місяців тому

      Thanks for watching so fast :)

    • @sholaadeyemi6846
      @sholaadeyemi6846 11 місяців тому +1

      This is awesome. How can I have to these topics in physics that difficult to explain theoretically

  • @Theblackchannel01
    @Theblackchannel01 11 місяців тому

    Aby jaldi bol kal subah palvey nikalna ha

  • @murad2177
    @murad2177 11 місяців тому

    There are so many students who are not able to understand english so please make your lectures in hindi❤❤❤❤❤

  • @milandjordjevic2408
    @milandjordjevic2408 9 місяців тому +1

    Decrease 28.571428571 %