De Broglie Hypothesis | De Broglie Wavelength

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  • Опубліковано 3 гру 2024

КОМЕНТАРІ • 94

  • @desmonderickson2232
    @desmonderickson2232 9 місяців тому +13

    I want to use this opportunity and thank the management of Manocha Academy because of them I did exceptional 🎉in my physics WASCCE paper words can’t explain how grateful I am ❤️🙏🏾 once again mammoth thanks to you Sir 🙏🏾

    • @ManochaAcademy
      @ManochaAcademy  9 місяців тому +4

      Congratulations!! Great to hear that you did in your Physics paper! Do share our channel with your friends!

    • @desmonderickson2232
      @desmonderickson2232 9 місяців тому +1

      @@ManochaAcademy Yes Sir and they also did well

    • @franklinemix8048
      @franklinemix8048 24 дні тому

      Woooow

  • @marycatherine296
    @marycatherine296 9 місяців тому +4

    Pls add more videos in math..it is very helpful to my son..you have taught in depth which the school fails to

  • @ManochaAcademy
    @ManochaAcademy  4 місяці тому

    For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
    👉Our Website: bit.ly/2KBC0l1
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  • @Mmpoyalo
    @Mmpoyalo 3 місяці тому +15

    λ = h / p
    where h is Planck's constant.
    Since kinetic energy (KE) is related to momentum by:
    KE = p^2 / (2m)
    where m is the mass of the electron, we can express the change in kinetic energy as:
    ΔKE = (p2^2 - p1^2) / (2m)
    Given that the kinetic energy increases by 96%, we can write:
    ΔKE = 0.96KE1
    where KE1 is the initial kinetic energy.
    Substituting the expression for KE in terms of momentum, we get:
    (p2^2 - p1^2) / (2m) = 0.96(p1^2 / (2m))
    Simplifying, we get:
    p2^2 = 1.96p1^2
    Taking the square root of both sides:
    p2 = √1.96p1 ≈ 1.4p1
    Now, using the de Broglie equation, we can find the change in wavelength:
    λ2 = h / p2
    = h / (1.4p1)
    ≈ 0.71λ1
    So, the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

  • @franklinemix8048
    @franklinemix8048 24 дні тому +1

    God will continue to bless you as long as you exist both you and your family and generations.

  • @janakicjoby7607
    @janakicjoby7607 Місяць тому

    OMG guys my 10 years in STEM in one video omg this person deserves so much more recognition!!! lots of love and gratefulness

  • @বাঙালি_মানেই_বুদ্ধিমান

    Thanks 🙏 from Bangladesh 🇧🇩. Does that means that all object r high Frequency least wavelength? 2. All objects r frozen light?

  • @24dipika
    @24dipika 2 місяці тому +1

    the wavelength decreases by about 29% (1 - 0.71 ≈ 0.29).

  • @kottekotravikumar8906
    @kottekotravikumar8906 9 місяців тому +1

    It's energy that was thought to be continuous, not matter.

  • @sriritwikshastry9603
    @sriritwikshastry9603 9 місяців тому +5

    The quality of these videos! My god! Fantastic! 11th videos are very intresting even to the 10th graders!

  • @franklinemix8048
    @franklinemix8048 24 дні тому

    Change in wavelength is (9x10-¹¹) that's exactly 27.3% decrease. This when you truncate the numbers while solving.
    But, when you decide not to truncate, estimate or approximate. The percentage change is 28.57142857143% exactly.

    • @franklinemix8048
      @franklinemix8048 24 дні тому

      The wavelength originally is 3.3×10-¹⁰m but as K.E(2.202x10-¹⁸) increased by 96% it changed the wavelength down to 2.4×10-¹⁰m that's a difference of 0.9×10-¹⁰ in correct standard form 9.0x10-¹¹. 23.7%. K.E is 1/2mv² where m(mass) is 9.1x10-³¹kg and v(velocity)=2.2x10⁶m/s.

  • @anthonymckinney8173
    @anthonymckinney8173 2 місяці тому

    Let's dive deeper into the concept of "systems" and their role in the context of de Broglie wavelengths and quantum mechanics.
    What is a system in physics?
    In physics, a system is simply a collection of objects or entities that we choose to focus our attention on. It's a way of mentally separating a part of the universe from the rest, so we can analyze its behavior and interactions more easily.
    Types of Systems
    * Isolated System: No exchange of matter or energy with its surroundings. A perfectly isolated system is an idealization, but some systems come close (e.g., a well-insulated thermos).
    * Closed System: Can exchange energy but not matter with its surroundings (e.g., a sealed container with a hot liquid).
    * Open System: Can exchange both matter and energy with its surroundings (e.g., a living organism).
    Why Systems Matter in Quantum Mechanics
    When we talk about a particle's de Broglie wavelength interacting with a system, we're essentially talking about how the particle's wave function interacts with the potential energy landscape or boundaries defined by that system.
    * Confinement: Systems can confine particles to specific regions of space, altering their wave functions and energy levels. This leads to phenomena like quantum confinement in nanostructures, where the particle's behavior is strongly influenced by the system's boundaries.
    * Scattering and Diffraction: When a particle interacts with a system, its wave function can be scattered or diffracted, revealing information about the system's structure. This is the basis for techniques like electron microscopy and neutron scattering.
    * Tunneling: In quantum mechanics, particles can "tunnel" through potential energy barriers, even if they don't have enough classical energy to do so. The probability of tunneling depends on the particle's de Broglie wavelength and the shape of the barrier, which is often determined by the system's properties.
    Choosing the Right System
    The choice of system depends on the specific problem or phenomenon we're interested in.
    * Single Particle in a Potential: We might consider a single particle (e.g., an electron) interacting with a potential well or barrier created by some external field or structure. This allows us to focus on the particle's wave function and energy levels within that specific environment.
    * Many-Particle Systems: In more complex systems, we need to consider the interactions between multiple particles, which can lead to collective phenomena like Bose-Einstein condensation or superconductivity.
    * Open Systems: In some cases, we need to account for the exchange of matter and energy with the surroundings, which can lead to decoherence and other effects that influence the quantum behavior of the system.
    Key Takeaway
    The concept of a "system" provides a framework for analyzing the behavior of particles in quantum mechanics. By defining the system and its boundaries, we can understand how a particle's de Broglie wavelength interacts with its environment, leading to a wide range of quantum phenomena.
    Let me know if you'd like to explore any specific examples or aspects of systems in more detail. I'm here to help!

  • @pukhrajmansion8445
    @pukhrajmansion8445 9 місяців тому +1

    Good 👍
    Next video on
    What is matter
    What is Physics definition area dimensions scope philosophy Physical world and it's measurements Physics day Physics history
    Physics Father

  • @simegnewtesfaye4455
    @simegnewtesfaye4455 9 місяців тому

    If we let the first kenetic energy is KE1 and The second kenetic energy is KE2 then the answer will be -0.2hKE1m
    h =Planck's constant
    m=the mass of an electron
    KE1=the first kenetic energy
    I hope you will give me a correction if I'm wrong 🙏
    Thanks for the video I swear this video is so amazing

    • @MukulSaini-iv7fr
      @MukulSaini-iv7fr 6 місяців тому

      bro answer is -.03 aa raha h mera to
      kya tum bataoge kaise kiya tumne

  • @srinivasanv7951
    @srinivasanv7951 4 місяці тому

    Sir, you have helped me so much through all you videos. Thank you so much!🎉🎉

  • @RasheduzzamanRuhid
    @RasheduzzamanRuhid 2 місяці тому

    It was a very helpful video. Love from Bangladesh. ❤

  • @angadsahoo2357
    @angadsahoo2357 9 місяців тому +1

    Thanks you sir for your kindly information to students ❤❤❤🎉🎉🎉😅😅😊😊😊

  • @m.rakeshroshan9601
    @m.rakeshroshan9601 9 місяців тому +1

    What is Quantum sir ?
    Is it something like quantified or will it can be other way said as made into mathematically expressible once Sir ?

  • @Varunzzz
    @Varunzzz 9 місяців тому +13

    Sir ....i watched your video when I was in 9th standard
    That was so clear
    After 5 years....
    I got your video from suggestions ❤
    So I'm an old student of your UA-cam class😂❤

  • @shiekh366
    @shiekh366 7 місяців тому +1

    Sir from 11 lakh to 12 lakh congratulations

  • @AnicheIjeomaJennifer
    @AnicheIjeomaJennifer 6 місяців тому +2

    5.0127×10^-19

  • @bhaktabachalabehera2654
    @bhaktabachalabehera2654 9 місяців тому +30

    I wanna become quantum scientist thanks sir for this video

    • @ManochaAcademy
      @ManochaAcademy  9 місяців тому +12

      Awesome to hear that ☺️

    • @bhaktabachalabehera2654
      @bhaktabachalabehera2654 9 місяців тому +1

      Can u tell me the roadmap to become along with marine biologist?

    • @OG_Solar_Edit
      @OG_Solar_Edit 5 місяців тому +1

      Niga it ain't that much easy as said

    • @sunilrai500
      @sunilrai500 3 місяці тому +1

      I guess you don't know the dot of quantum. Sir ki video toh khud sur confuse lag raha hae. Theory is not physics it's understanding.

    • @MafiabossELdijas
      @MafiabossELdijas 3 місяці тому

      😂​@@OG_Solar_Edit

  • @iron-cut6436
    @iron-cut6436 9 місяців тому +3

    the lecture i wanted thank you

  • @AtemkengSonna-im6rg
    @AtemkengSonna-im6rg 9 місяців тому

    Please can help me on how to identify colour in chemistry 9:55

  • @BELAGALI4U
    @BELAGALI4U 9 місяців тому

    Great class about quantum mechanics ❤

  • @givemoremutswiri8541
    @givemoremutswiri8541 9 місяців тому +1

    You are a star sir

  • @adityalokhande6484
    @adityalokhande6484 Місяць тому

    Sir the answer would be 5.01×10^-19 .

  • @ಅರ್ಪಿತಾ-ತ4ಷ
    @ಅರ್ಪಿತಾ-ತ4ಷ 4 місяці тому

    Are number of electrons reduced when metal was exposed to light ?

  • @KumarUtkarsh-u2y
    @KumarUtkarsh-u2y 2 місяці тому

    Great explanation❤ liked this video

  • @RinahNdombi
    @RinahNdombi 17 днів тому

    Can you do relationship between schrodinger wave equation and de broglie equation?

  • @vaibhavprajapati1835
    @vaibhavprajapati1835 9 місяців тому +2

    Wavelength will decrease by 28.5 %
    Sir please pin if ans is correct ❤

  • @zakmatew
    @zakmatew 4 місяці тому

    The fact that the energy levels are quantized doesn’t mean that there are particles. Rather, it is all waves but “quantized waves” as I call them. They give the false impression of particles but do account for the so called “dual nature of particles”.

  • @deku_ik_7
    @deku_ik_7 9 місяців тому

    Change in wavelength=2/5 and %change in wavelength= 40%

  • @RinahNdombi
    @RinahNdombi 17 днів тому

    Nice one!

  • @AvishekYadav-j6m
    @AvishekYadav-j6m 9 місяців тому +4

    Sir one video on weightless

  • @TejashriSwami
    @TejashriSwami 5 днів тому

    Thank you sir

  • @nathanakpome6401
    @nathanakpome6401 8 місяців тому

    Sir Please do a video on electromagnetic induction

  • @gotobawa
    @gotobawa 8 місяців тому +3

    28.57% dicreases

  • @Chemysterious10
    @Chemysterious10 9 місяців тому

    Sir from which website you use simulations like you use photoelectric effect in this video ??

  • @panthaganiniharika3208
    @panthaganiniharika3208 7 місяців тому

    the percentage change in wavelength is 2.14%.

  • @srinivasanv7951
    @srinivasanv7951 4 місяці тому

    Amazing🎉

  • @maheshwarisingh6295
    @maheshwarisingh6295 Місяць тому

    1.58×10^-15

  • @fathimahafsausman
    @fathimahafsausman 5 місяців тому

    Clear explanation sir :) Sir can i please know the answer for the homework question? Thanks in advance sir.

  • @MARADONA_20
    @MARADONA_20 9 місяців тому

    Sir I want you to teach the topic "state of matter". Thank you.

  • @dank3470
    @dank3470 9 місяців тому +1

    what is the answer for the question? please help ?

  • @SayaniChattaraj
    @SayaniChattaraj 7 місяців тому

    Thank you.... your explanation is crystal clear

  • @divyaanji2361
    @divyaanji2361 9 місяців тому +1

    Could you explain structure of atom lesson sir😅😅😅

    • @BhaskarGupta.
      @BhaskarGupta. 9 місяців тому

      Exams aa gaye h aur tujhe Lecture chahiye 🤣🤣🤣🤣😂😑

  • @KamathamSanthoshKumar
    @KamathamSanthoshKumar 14 днів тому +1

    Sir question ki answer kuda cheppandi

  • @umeshkumartiwari9431
    @umeshkumartiwari9431 4 місяці тому

    0.13383×10-34

  • @AvishekYadav-j6m
    @AvishekYadav-j6m 9 місяців тому +2

    ❤❤❤❤❤

  • @Nathyfunnyplanet
    @Nathyfunnyplanet 7 днів тому

    Please i can't get it explain for me

  • @Lily20008
    @Lily20008 9 місяців тому

    Sir is the change in wavelength 92.8%

  • @oluwajobaOkewole
    @oluwajobaOkewole 3 місяці тому

    27%

  • @THEGOATS90
    @THEGOATS90 9 місяців тому

    we want the bloopers 😛

  • @ayushkumar27703
    @ayushkumar27703 9 місяців тому +1

    Sir very nice video..heart please ❤

  • @nitasharma8308
    @nitasharma8308 4 місяці тому

    The answer is:
    1.4 times the initial wavelength.
    i.e.,
    Final wavelength=1.4 initial wavelength
    or,
    λ'=1.4λ.
    Hope it's true.
    Please let me know.

  • @ahmettiti1459
    @ahmettiti1459 8 місяців тому

    kral bir türk olarak alt yazıya cevirip kesintisiz izledim :)

  • @Bullseyeanime
    @Bullseyeanime 8 місяців тому

    0.287 decrease

  • @KieKie-lj8ks
    @KieKie-lj8ks 7 місяців тому

    I got 51%....i.e the wavelength decreases by 51%

  • @Sigma__Mathematics
    @Sigma__Mathematics 9 місяців тому

    Sir please Give tha answer of last Question

  • @k2creation481
    @k2creation481 4 місяці тому

    98% decrease

  • @SHURPARMAR
    @SHURPARMAR 5 місяців тому

    kk

  • @ShyamaliWijesinghe-t1o
    @ShyamaliWijesinghe-t1o 4 місяці тому

    71.428% increase in wave length.

  • @Neymar_JR713
    @Neymar_JR713 9 місяців тому +2

    First

    • @ManochaAcademy
      @ManochaAcademy  9 місяців тому

      Thanks for watching so fast :)

    • @sholaadeyemi6846
      @sholaadeyemi6846 9 місяців тому +1

      This is awesome. How can I have to these topics in physics that difficult to explain theoretically

  • @SARKET670
    @SARKET670 8 місяців тому

    কী গাবাই।

  • @Theblackchannel01
    @Theblackchannel01 9 місяців тому

    Aby jaldi bol kal subah palvey nikalna ha

  • @murad2177
    @murad2177 9 місяців тому

    There are so many students who are not able to understand english so please make your lectures in hindi❤❤❤❤❤

  • @milandjordjevic2408
    @milandjordjevic2408 8 місяців тому +1

    Decrease 28.571428571 %