I have a problem at 6:32 1*(001*)* in this RE a possible string is : 1000000 as 1* in first bracket is possible to not appear. then this string won't be accepted. So i think 2nd 0 should be connected to the starting state.
Apu in 9:12, the 3rd NFA 0*(01+10)1* If I put 0 only according to your NFA it will accept. But it says it should have atleast a 01 or 10. I am a bit confused.
i wish my lecturer explained u like this. don't know why my university pays this Mad Scientist for making us confused.. they should hire someone like u.
No, because we have (01+10) without asterisk(*). So the string wouldn't just pass without counteracting this term. The case your talking about would be [0*(01+10)* 1*]. here the initial state is also a final state.
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I have a problem at 6:32
1*(001*)*
in this RE a possible string is : 1000000 as 1* in first bracket is possible to not appear.
then this string won't be accepted.
So i think 2nd 0 should be connected to the starting state.
0oops it was 1*(001+)*
i read that wrong
your expanation is amazing i swear it is better than college million times
Apu in 9:12, the 3rd NFA 0*(01+10)1*
If I put 0 only according to your NFA it will accept. But it says it should have atleast a 01 or 10. I am a bit confused.
she did a mistake there.
i wish my lecturer explained u like this. don't know why my university pays this Mad Scientist for making us confused.. they should hire someone like u.
Meghan
thank you much! you are great! love the way you explain, so easy to understand!
For the 0*(01+10)1* nfa ,won't 0*(00+11)1* also be accepted?
jst saw the link below in the description section..thanks :)
shouldn't the initial state also be final? in the NFA of the regular expression: 0*(01+10)1*
No, because we have (01+10) without asterisk(*). So the string wouldn't just pass without counteracting this term.
The case your talking about would be [0*(01+10)* 1*]. here the initial state is also a final state.
Nicely and well explained.
for (aa)* what is the NFA ? ? ? ?
third one is wrong
What do you mean by Epsilon(Є) NFA ?
transition state without any cost
really good, thanks
Convert REX->(0+1+0) 0 1 (1+1+1) 1 (0+1) to Epsilon NFA.
tHANK yOU
hero!