SSLC EXAM | MATHS | CHAPTER 2 | CIRCLES | വൃത്തങ്ങൾ | FULL CHAPTER REVISION | EXAM WINNER
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- Опубліковано 8 жов 2024
- Welcome to Exam Winner, your ultimate destination for SSLC Maths tutorials! In this video, we dive into Chapter 2, focusing on the intriguing topic of Circles, also known as വൃത്തങ്ങൾ in Malayalam.
Our expert instructors provide a comprehensive tutorial on Circles, covering essential concepts in SSLC Maths. Exam Winner is dedicated to helping you understand and master these important topics.
Join us as we explore the fascinating world of geometry, delving into circle theorems, arcs and chords, tangents and secants, central and inscribed angles, properties of circles, circle equations, and geometric constructions. Discover the fundamental principles that govern circles and their relationships with other geometric elements.
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Ans -4 cm
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Homework
PA= 8cm, PB= 2cm
Find PC?
PA×PB=PC^2
8×2=PC^2
16=PC^2
√16=PC
4=PC
7:03 class starts from here
Thanks bro ❤️❤️❤️❤️
Thanks
Thanks 😊
AP=8cm
PB=2cm
PC=?
PA×PB=PC square
8×2= PC square
16 = PC square
Therefore : PC square = root 16
PC=4 cm
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Pa ×pb=pc2 =8×2=pc2 16=pc2 pc=√16=4
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PA ×PB =PC square
8×2 =√16
PC =4cm
Adipoli class ayirunu sir nanayi manassilayikk 🥳😍
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Pa×pb=pc²
8×2=pc²
16=pc²
Pc=√16
So, pc=4cm
Good class Allen sir 👍🔥
Adipoli allen sir very usful class
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PA×PB=PC²
8×2=PC²
PC²=16
PC=√16
PC=4cm
THANK YOU ALLEN SIR 💝☺️
GOOD CLASS
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Note
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Ans AP =8
Pb=2
Find pc =?
Pa×pb=pcsquare
8×2=pc ⬜
16 = pc ⬜
Pc = 4
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Pc=4cm
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Homework question answer 4cm
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Answer = 4cm
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Answer =4cm
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PA ×PB = PC²
8×2=PC²
16= PC²
PC=root 16= 4cm
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Homework
PA= 8cm, PB= 2cm
Find PC?
PA×PB=PC^2
8×2=PC^2
16=PC^2
√16=PC
4=PC
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Polikkum
PA×PB=PC square
8×2=√16= 4 cm
Thank you so much alen sir for this beautiful class🥰❤️🥰
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PA×PB=PC square
8×2 = root 16
= 4 cm
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Answer :- 4 c.m
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Awesome class allen sir . I did not understand the chapter circles for all this time and was wondering what to do . When I watched this class I understood all the concepts . Thanks sir
PC =4cm
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pc=4cm💫🎀
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Awesome class Allen sir , I did not understand this chapter very well I had so many confusions . but now after watching the class I understood the chapter , thank you very much Allen sir.
pc=4cm
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Answer : PA×PB = PC ²
8 × 2 = PC²
PC² = 8×2
PC² = 16²
PC = 4 cm
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എനിക്ക് ഇതു വരെ എത്ര പഠിച്ചിട്ടും circles മനസിലായില്ലായിരുന്നു but ippol allen സാറിന്റെ class കണ്ട് എനിക്ക് എല്ലാം അടിപൊളിയായി മനസിലായി, ചെയ്തു നോക്കി എല്ലാം thank you so much allen sirr❤️❤️❤️❤️❤️❤️❤️❤️
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Superclass❤
PC = 4 cm nice class sirr❤️
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pa×pb=pc^
8×2=pc^
16=pc^=√16
pc=4 cm
Class adipoli an ee chapter nallonam🥰 manasilayi thank u Allen sir ❤️❤️and exam winner team 🥰🥰🥰
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PA×PB=PC²
8×2=PC²
16=PC²
PC=√16
PC=4cm
Thankyou sir🥰❤️
Prove cheyyunna questions enikk ariyillayurunnu. But ippo perfect aay🥺💕
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Answer
PA x PB = PC²
8 x 2 = 16
That is , PC = √16 = 4cm
Innathe class adipoli ayirunnu❤️🔥 Your methods of explaining the topics are so easy to understand 😊Thank you Sir❤️
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4cm
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Sir class poli ❤
2025 SSLC BATCH
PA×PB =PC*
8×2 =PC*
✓16 = PC*
4 = PC
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2024
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Set
Class നല്ലപോലെ മനസിലായി 😁
Very helpful
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PA × PB = PC²
8 × 2 = √16
PC = 4 cm
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Thank u soo much allen sir for the beautiful class.....nd for the information about comet... Soo excited to see the comet!😁💓
Answer PA*PB=PCsquare
=8*2=PCsquare
ie PC=4cm
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