Linear Algebra: Linear Combinations and Span

Поділитися
Вставка
  • Опубліковано 28 лис 2024

КОМЕНТАРІ • 8

  • @-mwolf
    @-mwolf 3 роки тому +5

    17:55, watching at 69 views ^^
    Btw, do you have a patreon or something like that? Because your videos are really helping me with learning the math for a machine learning book I'm currently reading and I'd be happy to support you in some way :] (I've been looking a long time for structured, complete and well explained courses about linear algebra and calculus and am happy I finally found them!)

    • @MathforThought
      @MathforThought  3 роки тому +1

      I'm setting up one when I get around to doing it :) .

  • @jonathanE-do6ss
    @jonathanE-do6ss 6 місяців тому

    What is the difference between the span of d and U in example 8?Is the span of d not equal to U? Don't they both share the same line through the origin? If this is the case, why did you have to say the span of d belongs to U if we already know U has the same span as the span of d.
    I am confused because @41:28 , you state that the span of vector d belongs to U.

  • @chloehagen5782
    @chloehagen5782 2 роки тому +2

    The second example is incorrect, if you do the k3 for both of the equations it needs to work for there is not a single number that can be found, also if you check what is said at the end of the problem, the vectors don't add up.

    • @MathforThought
      @MathforThought  2 роки тому

      I'm sure there is a small typo somewhere but the method is still fine. I'll correct the typo and reupload the video when I have time so thank you for pointing it out.

  • @jkgan4952
    @jkgan4952 Рік тому +1

    Example 3 has solutions though right? All points lie on y=5x and the span of v1 and v2 is y=5x

    • @jkgan4952
      @jkgan4952 Рік тому

      Oh ya so because we got 0=0, that implies anything that solves one of the equation will solve the other one.
      So, let us take 4=2(c1)-3(c2)
      Using some algebra, (c1) = 2+(3/2)*(c2) which gives us a function that can determine the constants for linear combinations.

    • @MathforThought
      @MathforThought  Рік тому +1

      @@jkgan4952 Yeah I get it. I guess I was meaning to say that there is no unique solution to this system.