There was a mistake in Question 4 step 2 when you started integration in the second term you forgot to put 1/4 due to this your answer gone wrong as it should be cos(6x+3)/24 but yours was cos(6x+3)/6. Please check it once . Thank You If anyone agrees then reply or like
1. श्री राम, जय राम, जय जय राम 2. श्री राम, जय राम, जय जय राम 3. श्री राम, जय राम, जय जय राम 4. श्री राम, जय राम, जय जय राम 5. श्री राम, जय राम, जय जय राम 6. श्री राम, जय राम, जय जय राम 7. श्री राम, जय राम, जय जय राम 8. श्री राम, जय राम, जय जय राम 9. श्री राम, जय राम, जय जय राम 10. श्री राम, जय राम, जय जय राम 11. श्री राम, जय राम, जय जय राम 12. श्री राम, जय राम, जय जय राम 13. श्री राम, जय राम, जय जय राम 14. श्री राम, जय राम, जय जय राम 15. श्री राम, जय राम, जय जय राम 16. श्री राम, जय राम, जय जय राम 17. श्री राम, जय राम, जय जय राम 18. श्री राम, जय राम, जय जय राम 19. श्री राम, जय राम, जय जय राम 20. श्री राम, जय राम, जय जय राम 21. श्री राम, जय राम, जय जय राम 22. श्री राम, जय राम, जय जय राम 23. श्री राम, जय राम, जय जय राम 24. श्री राम, जय राम, जय जय राम 25. श्री राम, जय राम, जय जय राम 26. श्री राम, जय राम, जय जय राम 27. श्री राम, जय राम, जय जय राम 28. श्री राम, जय राम, जय जय राम 29. श्री राम, जय राम, जय जय राम 30. श्री राम, जय राम, जय जय राम 31. श्री राम, जय राम, जय जय राम 32. श्री राम, जय राम, जय जय राम 33. श्री राम, जय राम, जय जय राम 34. श्री राम, जय राम, जय जय राम 35. श्री राम, जय राम, जय जय राम 36. श्री राम, जय राम, जय जय राम 37. श्री राम, जय राम, जय जय राम 38. श्री राम, जय राम, जय जय राम 39. श्री राम, जय राम, जय जय राम 40. श्री राम, जय राम, जय जय राम 41. श्री राम, जय राम, जय जय राम 42. श्री राम, जय राम, जय जय राम 43. श्री राम, जय राम, जय जय राम 44. श्री राम, जय राम, जय जय राम 45. श्री राम, जय राम, जय जय राम 46. श्री राम, जय राम, जय जय राम 47. श्री राम, जय राम, जय जय राम 48. श्री राम, जय राम, जय जय राम 49. श्री राम, जय राम, जय जय राम 50. श्री राम, जय राम, जय जय राम 51. श्री राम, जय राम, जय जय राम 52. श्री राम, जय राम, जय जय राम 53. श्री राम, जय राम, जय जय राम 54. श्री राम, जय राम, जय जय राम 55. श्री राम, जय राम, जय जय राम 56. श्री राम, जय राम, जय जय राम 57. श्री राम, जय राम, जय जय राम 58. श्री राम, जय राम, जय जय राम 59. श्री राम, जय राम, जय जय राम 60. श्री राम, जय राम, जय जय राम 61. श्री राम, जय राम, जय जय राम 62. श्री राम, जय राम, जय जय राम 63. श्री राम, जय राम, जय जय राम 64. श्री राम, जय राम, जय जय राम 65. श्री राम, जय राम, जय जय राम 66. श्री राम, जय राम, जय जय राम 67. श्री राम, जय राम, जय जय राम 68. श्री राम, जय राम, जय जय राम 69. श्री राम, जय राम, जय जय राम 70. श्री राम, जय राम, जय जय राम 71. श्री राम, जय राम, जय जय राम 72. श्री राम, जय राम, जय जय राम 73. श्री राम, जय राम, जय जय राम 74. श्री राम, जय राम, जय जय राम 75. श्री राम, जय राम, जय जय राम 76. श्री राम, जय राम, जय जय राम 77. श्री राम, जय राम, जय जय राम 78. श्री राम, जय राम, जय जय राम 79. श्री राम, जय राम, जय जय राम 80. श्री राम, जय राम, जय जय राम 81. श्री राम, जय राम, जय जय राम 82. श्री राम, जय राम, जय जय राम 83. श्री राम, जय राम, जय जय राम 84. श्री राम, जय राम, जय जय राम 85. श्री राम, जय राम, जय जय राम 86. श्री राम, जय राम, जय जय राम 87. श्री राम, जय राम, जय जय राम 88. श्री राम, जय राम, जय जय राम 89. श्री राम, जय राम, जय जय राम 90. श्री राम, जय राम, जय जय राम 91. श्री राम, जय राम, जय जय राम 92. श्री राम, जय राम, जय जय राम 93. श्री राम, जय राम, जय जय राम 94. श्री राम, जय राम, जय जय राम 95. श्री राम, जय राम, जय जय राम 96. श्री राम, जय राम, जय जय राम 97. श्री राम, जय राम, जय जय राम 98. श्री राम, जय राम, जय जय राम 99. श्री राम, जय राम, जय जय राम 100. श्री राम, जय राम, जय जय राम 101. श्री राम, जय राम, जय जय राम 102. श्री राम, जय राम, जय जय राम 103. श्री राम, जय राम, जय जय राम 104. श्री राम, जय राम, जय जय राम 105. श्री राम, जय राम, जय जय राम 106. श्री राम, जय राम, जय जय राम 107. श्री राम, जय राम, जय जय राम 108. श्री राम, जय राम, जय जय राम
In q9 in the last step while integrating the sec² term we will have 1/2 in the denominator also so the 1/2 1/2 canceled and thus we get the ans as x - tanx/2 + c
Sir there is mistake in q9 last step integration of sec^2 (x/2) is tan(x/2) / (1/2 ) so the answer final answer be x - tan (x/2) + C whis is also in ncert
Sir forgot to put the 1/4 to sin(6x+3) in the previous step before second last step. But at second step you can see the the entire equation is divided by 1/4 so atlast he took 1/4 common. But the answer is incorrect. He forgot to multiply 1/6 and 1/4, the correct answer is -3/8cos(2x+1)+1/24cos(6x+3)+C
Sir in question no. 9 when tan x/2 will be differentiated it will give 2 on numerator which will cancel the 2 on denominator. Minute changes are required
@@gagnikaur95 I just checked it in another video you can go in a different method like break (sinx^2)(sinx) and then solve you will get the exact answer but this is also right answer not just 1/2 cos is also different
Sir question 4 Mai cos(6x+3)/6 nahi cos (6x+3)/24 hoo gaa 4 se Aap NE multiple nahi kiya hai aap ne Ek hi term k sath kiya hai Vo doono k sath Hoo gaa multipy
Sir.... 3rd question me 2cox.coy=cos(x+y)+cos(x-y) Cos(2x+4x)+cos(2x-4x)= Cos6x+cos(-2x) Aana chahiye tha.... Apne addition 2x+4x ki hai or substraction 4x-2x ?????????????????
Sir pehle aap ek ek formula likh dete the side mein to jyada ache se samajh aata tha aur formula bhi revision ho jaata tha lekin ab aap direct bana dete the to dikkat hota hai thora sa....
@@tggames-4847bro then how in question 1 we're getting cos2(2x+5)= cos(4x+10). According to you we can't simply multiply it because it is of the form cos2(theta) instead we should use the formala of cos2(theta) but without even doing so we're getting the answer. So how's it happening? Please clarify my doubt...
Sir In question number 6 in the 4th step, the formula of 2cosA.sinB is sin(A+B)-sin(A-B) means it will be [cos4x-sin3x]but you had written sin(A+B)+sin(A-B).
@abhisarthak975 formula sin(A+B)-sin(A+B) hi he aur sir ne sin(A+B) sin(A+B) is liye likha kyoki x-3x =-2 hoga isi liye age nagetive he vo -*-=+ ho jayega😊
sir ques no.3 me apne starting me mistake ki hai //// sir 2 cos A . Cos B ka Cos (Cos A+B)+Cos(A-B) HOGA na //// apne Cos (2x+4x) to sahi kiya lekin apne Cos(2x-4x) ki jagah Cos(4x-2x) lekin tb bhi apka hi answer sahi hai kaise
Sir samjhne me bahut problem Hui. Aapko pahale simplify karna chahiye tha then sabse last me integration. But aapne toh har second step me integration ghusa diya, jisse samjhne me bahut hi problem Hui.
In q13 Sir:- Main tumhari pariksha le rha tha Me:- Sir aapki videos me se main aapni fair notebook complete karta hu aur jab aap aise pariksha lete ho wo bhi ek dum se toh mistake ho jati hai sir😅😅😅😅
Sir Qno 3 me mistake hai apne - mynus ke location par + plus ka sign rain diya hai or ans bhi match kar raha hai mujhe Sarah me bhi nhi aa raha hai Qno 3 ka line no 2or 3 samjha digiye sir ji 🙏🙏🙏🙏🙏🙏🙏🙏
sir aap bht saare question me kuch formulas aise laga dete hai jo hme yaad he nhi hotey fir smjh nhi ata aisa is exercise me bht baar hua hai please don't ignore this sir kyoki apki iye video bcchy har saal dekhte hai
Sir I think u have missed some small points to explain luke in question 3..... 1+cos2(6x)/2.... Sir in the next step u didn't tell where did the denominator 2 went i myself had a lot to trouble understanding the aum so i had to switch videos for better explanation.....
Sir Mai October Se Last October Tak 10 chapter complete Kar liya harr ek introduction harr ek exercise and finally I am confident to go for my Board Exam and Thanks A Lot Sir 🙏 🙏 🎉🎉
There was a mistake in Question 4 step 2 when you started integration in the second term you forgot to put 1/4 due to this your answer gone wrong as it should be cos(6x+3)/24 but yours was cos(6x+3)/6.
Please check it once .
Thank You
If anyone agrees then reply or like
Yes bro Mera bhi yanhi doubt hua
Thanks bro
Yes sir 😢😢
Thanks ❤
Absolutely @@nothingbeatzs
1. श्री राम, जय राम, जय जय राम
2. श्री राम, जय राम, जय जय राम
3. श्री राम, जय राम, जय जय राम
4. श्री राम, जय राम, जय जय राम
5. श्री राम, जय राम, जय जय राम
6. श्री राम, जय राम, जय जय राम
7. श्री राम, जय राम, जय जय राम
8. श्री राम, जय राम, जय जय राम
9. श्री राम, जय राम, जय जय राम
10. श्री राम, जय राम, जय जय राम
11. श्री राम, जय राम, जय जय राम
12. श्री राम, जय राम, जय जय राम
13. श्री राम, जय राम, जय जय राम
14. श्री राम, जय राम, जय जय राम
15. श्री राम, जय राम, जय जय राम
16. श्री राम, जय राम, जय जय राम
17. श्री राम, जय राम, जय जय राम
18. श्री राम, जय राम, जय जय राम
19. श्री राम, जय राम, जय जय राम
20. श्री राम, जय राम, जय जय राम
21. श्री राम, जय राम, जय जय राम
22. श्री राम, जय राम, जय जय राम
23. श्री राम, जय राम, जय जय राम
24. श्री राम, जय राम, जय जय राम
25. श्री राम, जय राम, जय जय राम
26. श्री राम, जय राम, जय जय राम
27. श्री राम, जय राम, जय जय राम
28. श्री राम, जय राम, जय जय राम
29. श्री राम, जय राम, जय जय राम
30. श्री राम, जय राम, जय जय राम
31. श्री राम, जय राम, जय जय राम
32. श्री राम, जय राम, जय जय राम
33. श्री राम, जय राम, जय जय राम
34. श्री राम, जय राम, जय जय राम
35. श्री राम, जय राम, जय जय राम
36. श्री राम, जय राम, जय जय राम
37. श्री राम, जय राम, जय जय राम
38. श्री राम, जय राम, जय जय राम
39. श्री राम, जय राम, जय जय राम
40. श्री राम, जय राम, जय जय राम
41. श्री राम, जय राम, जय जय राम
42. श्री राम, जय राम, जय जय राम
43. श्री राम, जय राम, जय जय राम
44. श्री राम, जय राम, जय जय राम
45. श्री राम, जय राम, जय जय राम
46. श्री राम, जय राम, जय जय राम
47. श्री राम, जय राम, जय जय राम
48. श्री राम, जय राम, जय जय राम
49. श्री राम, जय राम, जय जय राम
50. श्री राम, जय राम, जय जय राम
51. श्री राम, जय राम, जय जय राम
52. श्री राम, जय राम, जय जय राम
53. श्री राम, जय राम, जय जय राम
54. श्री राम, जय राम, जय जय राम
55. श्री राम, जय राम, जय जय राम
56. श्री राम, जय राम, जय जय राम
57. श्री राम, जय राम, जय जय राम
58. श्री राम, जय राम, जय जय राम
59. श्री राम, जय राम, जय जय राम
60. श्री राम, जय राम, जय जय राम
61. श्री राम, जय राम, जय जय राम
62. श्री राम, जय राम, जय जय राम
63. श्री राम, जय राम, जय जय राम
64. श्री राम, जय राम, जय जय राम
65. श्री राम, जय राम, जय जय राम
66. श्री राम, जय राम, जय जय राम
67. श्री राम, जय राम, जय जय राम
68. श्री राम, जय राम, जय जय राम
69. श्री राम, जय राम, जय जय राम
70. श्री राम, जय राम, जय जय राम
71. श्री राम, जय राम, जय जय राम
72. श्री राम, जय राम, जय जय राम
73. श्री राम, जय राम, जय जय राम
74. श्री राम, जय राम, जय जय राम
75. श्री राम, जय राम, जय जय राम
76. श्री राम, जय राम, जय जय राम
77. श्री राम, जय राम, जय जय राम
78. श्री राम, जय राम, जय जय राम
79. श्री राम, जय राम, जय जय राम
80. श्री राम, जय राम, जय जय राम
81. श्री राम, जय राम, जय जय राम
82. श्री राम, जय राम, जय जय राम
83. श्री राम, जय राम, जय जय राम
84. श्री राम, जय राम, जय जय राम
85. श्री राम, जय राम, जय जय राम
86. श्री राम, जय राम, जय जय राम
87. श्री राम, जय राम, जय जय राम
88. श्री राम, जय राम, जय जय राम
89. श्री राम, जय राम, जय जय राम
90. श्री राम, जय राम, जय जय राम
91. श्री राम, जय राम, जय जय राम
92. श्री राम, जय राम, जय जय राम
93. श्री राम, जय राम, जय जय राम
94. श्री राम, जय राम, जय जय राम
95. श्री राम, जय राम, जय जय राम
96. श्री राम, जय राम, जय जय राम
97. श्री राम, जय राम, जय जय राम
98. श्री राम, जय राम, जय जय राम
99. श्री राम, जय राम, जय जय राम
100. श्री राम, जय राम, जय जय राम
101. श्री राम, जय राम, जय जय राम
102. श्री राम, जय राम, जय जय राम
103. श्री राम, जय राम, जय जय राम
104. श्री राम, जय राम, जय जय राम
105. श्री राम, जय राम, जय जय राम
106. श्री राम, जय राम, जय जय राम
107. श्री राम, जय राम, जय जय राम
108. श्री राम, जय राम, जय जय राम
@kavitadhiman6982JAI SREE RAM 🔥🔥🔥🔥🚩🚩🚩🚩
जय राधे श्याम
Jai shree ram 🚩 🚩🚩🚩🚩🚩
@kavitadhiman6982muh me chahiye ka bolo dete hai 😂
Jai shree ram ❤🙏🏽🙃🙃♥️
In question 4 , there is mistake at last ... Cos ke niche jha aapne 6 likha h wah 24 aaega.......u r best teacher 👍
Yes ..but great explanation...
Chup
Nhi hoga be
@@DheerajSharma-r6y😂😂😂
@@SujuPusu-sl7dnkyu Nahi .😏
Sir question 9 me integration of sec²x/2 will be tanx/2 upon 1/2 and 2/2 will be cancelled out so the answer will be x- tanx/2 +c
same thought
Yes bro
The one and only channel best channel for mathematics class 12 which is supporting us for free
Great Work Sir.....
In q9 in the last step while integrating the sec² term we will have 1/2 in the denominator also so the 1/2 1/2 canceled and thus we get the ans as x - tanx/2 + c
Ya ur right
To khud kar la
Thanku
Are yar madharchod ke padhae naikhe aaot
Sir padha rhe hain
Tu tension na le
23:51 sir there is a minute mistake in answer sirf tan(x/2) hi likhna tha 2 se 2 cancel ho jaye ga
Differentiation intigration or trigno k formule toh aate h..lekin kha konse use kre ❤️🩹🤌
Sir in que4 the whole eqn is divided by 4 so the answer is -3/8cos(2x+1)+1/24cos(6x+3)+c
Yes
Yes
Yes I also noticed it...❤... comment kr ke achha kiye ❤bahut Jano ka fayda ho.jayega😊
True
Right bro I also noticed 😂
Sir there is mistake in q9 last step integration of sec^2 (x/2) is tan(x/2) / (1/2 ) so the answer final answer be
x - tan (x/2) + C whis is also in ncert
Thank you sir god bless you 🙏❤❤❤❤❤❤
Thanks 👍🙏🏻👍 Guru ji. For great efforts put by u. No one thinks of us means poor and needy students as much u think. Guru jee.
Na bsdk schl to jata. Nahi hai too
Wah re😂
Q3 ma second last line ma 1/4 common kasa la liya ,@naxaclass
@@rishabhshekhawat8376 wrong h woh lmao
@@pratyush346 kya bol ra h
11:11 Sir question no.4 is wrong 1/4 ka multiply bhi to hoga andar to vo 1/24 cos 6x+1 hoga
Yes
Yes
Yes
Vse bhi iska answer ncert m alg h
@@rachnascreation3815nahi bhai put krna wala method se kro ncert wala arha h😢
sir is there a mistake in q3? while using the fromula 2cosAcosB .. cos (2x-4x) it’s ans is -2x but you didn’t put the -sign.. little confuse
Cos ( - x) gives always a +ve cos x and same is sec
Bro cos(-x) = cos (x)
Cos (-) sign ko kha jata h
Tq....
@@RajKumar-ul3vx
Yes right
Sir ek doubt hai ?
Apne question number 2 me formula put karke minus sign sath me liya h ..
But question number 3 me apne minus sign nhi liya ...
Sameeeeee mujhe bhi
Apko pta chala kya ab toh 2 saal ho gye 🥲
sin(-x)= -sinx
cos(-x)= cosx
2024-2025 batch students like kre
Me❤
❤
24:04 it is tan(x/2)
34:39 it is 2(sinx+xcosalpha)+c
Sir forgot to put the 1/4 to sin(6x+3) in the previous step before second last step. But at second step you can see the the entire equation is divided by 1/4 so atlast he took 1/4 common. But the answer is incorrect. He forgot to multiply 1/6 and 1/4, the correct answer is -3/8cos(2x+1)+1/24cos(6x+3)+C
Which question?
@@Mentalks_69Q4
@@harmangaminggn7139 yes yu are right😮
Yes
Ha sir ne 4 ko 8 se multiplication nai ki may be bhul gye 😅
Sir in question no. 9 when tan x/2 will be differentiated it will give 2 on numerator which will cancel the 2 on denominator. Minute changes are required
Sahi bro tanx/2/x/2 then 2 comes to numerator it becomes 2/2 that is tanx
Hey 4 q me 11:12 yha pe -3/8 nikala hai sir NE Pr ncert me answer -1/2hai😢
@@gagnikaur95 I just checked it in another video you can go in a different method like break (sinx^2)(sinx) and then solve you will get the exact answer but this is also right answer not just 1/2 cos is also different
@@C1Cshivanshi krliya tha mene solve alg method se by the way thnku
@@C1Cshivanshidvvfdf
Thnku guruu jii ❤😊
thanku sir you are great teacher in world❤❤❤❤❤❤🎉🎉🎉🎉🎉
at 11:09 in question no.4 sir u forgot to multiply 4 with cox[6x+3]/6
Bhai ncert ka kya way hai
Sir formule learn krte h.... pr phir se bhul jaate h 😕 ky kre ??
rata maro 47:47
Mu m le
Kuch mat kar aur soja
Make a formula sheet and revise it everyday..(don't learn..just go through it everyday) formulas will become muscle memory of your brain👍
The more you solve you master the formulas
Thanks sir Ji for this ❤️❤️❤️❤️❤️
Birds chirping feels like jannat me ghar hai sir ka😂 setup tour plss
Yes❤❤ sir live in Village ❤
Best Math Teacher I had ever seen love you sir 🙏♥️
Sachin sir ko jaante ho kya mere bahi
🎉 congratulation sir for 1M (10 lakh) subscribers
1m = 1 korod
@@Class12th-nq4yp nhi bhai 1Million = 10 Lakh
your teaching style osm h you are tha best sir 🎉🎉🎉
Thanks you sir for helping students🙏❤️
Sir question 4 Mai cos(6x+3)/6 nahi cos (6x+3)/24 hoo gaa 4 se Aap NE multiple nahi kiya hai aap ne Ek hi term k sath kiya hai Vo doono k sath Hoo gaa multipy
Right bro thanks
Sir....
3rd question me 2cox.coy=cos(x+y)+cos(x-y)
Cos(2x+4x)+cos(2x-4x)=
Cos6x+cos(-2x)
Aana chahiye tha....
Apne addition 2x+4x ki hai or substraction 4x-2x
?????????????????
Yes bro
Cos(-3x) = Cos3x
Because negative sign show it is in 4th quadrant and in 4th quadrant cos is positive
Please explain sir
@@darktipsff9261 just go through unit circle once
Cos is positive in 4th quadrant
Cos(0°-X)=cos(-x)=cosx
It won't be -cosx
Hope it helps
@@prathammahadik3223 abe angle theorem isme kyu gushed rha wo alag chiz h
thank u so much for your free classes on you tube 😍😍😍😍 I scored 95 marks im maths class 12 in cbse board thank u so much sir u are great
Without reference book?
Kaise kia btao bhai tips do kuch hume bhi
@@Vipshorts118Abe padh le bsdk
Crystal clear pure 💡
Love from R.j❤
waah bro did u check the answers ?? stupid
Sir q4 mai 1/4 toh dono ke saath h
Tu hai kon bhai
Ya kya hai bhai
@@mohdraqibmotivation675 kya karega Jaan kar tu
Sir pehle aap ek ek formula likh dete the side mein to jyada ache se samajh aata tha aur formula bhi revision ho jaata tha lekin ab aap direct bana dete the to dikkat hota hai thora sa....
Sahi bola
Hm yr
Everyone focus carefully on q - 4 there we have to write 24 instead of 6
@@tggames-4847bro then how in question 1 we're getting cos2(2x+5)= cos(4x+10). According to you we can't simply multiply it because it is of the form cos2(theta) instead we should use the formala of cos2(theta) but without even doing so we're getting the answer. So how's it happening? Please clarify my doubt...
Sir In question number 6 in the 4th step, the formula of 2cosA.sinB is sin(A+B)-sin(A-B) means it will be [cos4x-sin3x]but you had written sin(A+B)+sin(A-B).
Ha yaar ,sir galat step se bhi sabi ans la de rahe hai
Bhai toh jab 2x-4x karega toh negative sign aayega na, sir ne direct positive likh diya hai usko
@@Shund0because cos nagetive ho to bhi use cos positive hi likhenge (cos(-x)=cosx ) ye basic formula he
@abhisarthak975
formula sin(A+B)-sin(A+B)
hi he aur sir ne sin(A+B) sin(A+B) is liye likha kyoki x-3x =-2 hoga isi liye age nagetive he vo -*-=+ ho jayega😊
For those who did not understand this step 35:46
Sin^2x + cos^2 = 1 and sin2x = 2sinxXcosx
Then bass sin^2x+cos^2x ko he kyu diff krke aage step ki 2sinxcosx ka kya kiya
sin^x+ cos^x=1 hota hai isliye sir ne likha
Sir you are the best teacher of the 🌍 world of mathematics
10:20
Sir, you forgot to put ¼ in front of ∫sin3(2x+1)dx
sir ques no.3 me apne starting me mistake ki hai //// sir 2 cos A . Cos B ka Cos (Cos A+B)+Cos(A-B) HOGA na //// apne Cos (2x+4x) to sahi kiya lekin apne Cos(2x-4x) ki jagah Cos(4x-2x) lekin tb bhi apka hi answer sahi hai kaise
Cos even function hai
Cos ka maan +ve hi aata hai
Cos of -x
= Cos x
Bro Cos(-A) = CosA hota hai isliye
Really nice explanation/teaching sir. It was really helpful. Thank you sirji 🙏
Sir Ka number bata du
Bta 😂
Sir makes every problem a halwa
Thank you sir 😊😊
Ghanta kush samaj nehi Aya
@@wold_gknowledgethode mistakes hai isme
At 34:46 the right answer is 2(Sin x + x Cos α ) bcs Cos α can't be integrate with respect to dx but dx is integrated that is X .
Dhanyawad Guru Ji 🙏🏽
Thanks sir jee😊
Sir
You did a mistake in question number 6 at 17:24 sin(a+b)-sin(a-b) hota hain formula
Exactly
Thank you sir I couldn’t express how I’m thankful to you i can only say that “you’re doing a wonderful work”
😂😂😂
Yeah bro 🤞
Bhai book me answer chak kar pahle
Thank you for this sir 🙂😌
Q 4 can also be solved as Q5
Integral Sin²x.Sinx dx
Intg(1-cos²x).sinx dx
Put cos(2x+1)=t
-sin(2x+1)2.dx=dt
Sin(2x+1)dx=-dt/2
....
Sir q 3 mein a-b hoga to-2x ayega
Yes
@@vxnsh08a=4x, b=2x 😐
Sir ek video banaiye TRICKS TO LEARN ALL TRIGONOMETRIC FORMULAE
Please sir🙏🙏🙏
Sir samjhne me bahut problem Hui. Aapko pahale simplify karna chahiye tha then sabse last me integration. But aapne toh har second step me integration ghusa diya, jisse samjhne me bahut hi problem Hui.
✔️ Wrong ✅ answer ✔️ in ✔️ the ✅ q4 ✔️...
Please ✔️ check ✔️✅
Yes you are right...
Thank you.
Aap bahut achcha samjhate Ho sir ❤
❤ hey
Q- 19 ❌
amazing sir thanku soo much
yes
Thanks you very very much sir aap jisse guru ji hoto uss ka koii kuch nhi kar sakta🙏🙏🙏🙏🙏
Hii
@vishalvashisht1016 bataoo jiii
@Rashmi_tyagi267 kitne percentage aaye apke?
Sir question no. 9 me tan x/2 me x/2 ka coefficient multiply ma jaayega to 2 cancel ho jaayega to right answer x-tan x/2 + c hoga
Amazing explained 😊thank you sir
Sir can you please give all the formulas necessary to make this questions pleasee
Search ex7.3 Introduction
100rs de mai deta fir saare formula
Visit my channel... In one short video ... I gave it
Get lost
@@princekumar-xw8xd🤡🤡
Kon chahta hai 85%
Yes bhai
filhaal toh 95% bol le
I want 97
Only 70%😊
Yes bro
Sir pehle aap na questions ko bilkul gehrai se samjhate the ab aap thora kam gehrai se samjhate ho jisse doubt clear nhi ho paate 🤔🤔🧐🧐🧐😫😭
Unhe aata hi nahj
How many are thinking
Most of the question are wrong after watching the comments 😢
Me..
Mee😂😂😂
me 😂😂
Meeee😂😂😂😂
In question 4 can we go with sin^3(2x+1) = sin(2x+1)sin^2(2x+1)
Yes
use cos 3x formula
Sir in Q/no. 5....... the value of sin²x should be (1-cos²x)/2
but you have only used (1-cos²x)
please explain about this......
Bhai formula hai sin²x+cos²x= 1 10th class wala
Thank you sir fir this exercise 👍👍
Hiii
34:19 cos(alpha) as a constant treat hoga aur bahar aa jayega, it will be cos(alpha)x.
Pr aisa kyu?
In question 6 , 2cosxsiny= sin(x+y)-sin(x-y)...
I find this comment😂😂
yess truee
Sir 4 question me mistake kar di apne 1/4 dono ke sath multiply me h apne age Wale ke sath Kiya h bs❤and thanku for making math easy for students 😊 ❤
11:02 Q no 4 wrong , haven't multipled 1/4 to 2nd term
Sir you have done minor mistake in question 9 that is you haven't written the coefficient of X in divide ❤❤❤
Sir ques 22 mai agar sin ki form mai ques aye toh phir hm kisko multiply aur divide kree ?
Cos se
In q13
Sir:- Main tumhari pariksha le rha tha
Me:- Sir aapki videos me se main aapni fair notebook complete karta hu aur jab aap aise pariksha lete ho wo bhi ek dum se toh mistake ho jati hai sir😅😅😅😅
Aapne sir 11:16 me 1/4 ka second expression se multiply nhi kiya sir
yeah
And that's y i was so confused 😂
re 2nd expression 1/2 se multiply hoga or 1st wala 1/4 se
Ap to Best phrate ho sir ji❤
Sir questions mei solutions ke Sath Sath sabhi formula bhi likhiye sir samajh mei Nahi aa pa Raha hai ki kaise huaa.. 🙏🙏🙏
Sir..
According to ncert answer sheet..
Answer is incorrect of question 4..!!
Please check..!!
Saare formula yaad hone ke baad bhi question nhi ban Raha hai
Bhai mujhe tho formula hi yaad nahi ho raha ha
@@GauravKumar-ep6ym 😂😂😂
Same yrr kya karu 😂
Batao phir sin(ax+b)ka whole cube
Good Job
Bhot bhot dhynabaad sir g aap bhot accha padate ho😊😊
Thanks sir aap ke vedio sa bhot help melte ha prepration ma or sir agar example sa khe solution aap kara data to or bhe acha ho jata sir
Sir In question no 9
The answer is X-tanx/2+C
Because INTEGRATION OF sec*2 X/2 IS 1/2.2tanX/2+C
Thanks
Try to cover if u could do Guru ji 2 exercise on tomorrow till Sunday 7.4 and 7.5 Guru ji
can u please tell me how -1 came 21:56
@@moonlight30952 it's ok don't feel bad , i will tell you it's formula of trigonometry
Sec²x + tan²x = 1
Hence we can write it as ,
Sec²x - 1 = tan²x
@@animeJod360 thanks buddy 🦋💗
Sir apne 1-2 saal me UA-cam pe Maths ka revolution la dia
11:16 Q number 4 ka jo denominator kaha gya bhai ?????
dono ko milna chahiya tha na ???/
Great work Sir 😊
For my side in this video have most of the mistakes so please dont watch.😢
Sir Qno 3 me mistake hai apne - mynus ke location par + plus ka sign rain diya hai or ans bhi match kar raha hai mujhe Sarah me bhi nhi aa raha hai Qno 3 ka line no 2or 3 samjha digiye sir ji 🙏🙏🙏🙏🙏🙏🙏🙏
Sir in que 4 , in last step i think we should also integrate 1 and 3 (placed in brackets)
No
sir aap bht saare question me kuch formulas aise laga dete hai jo hme yaad he nhi hotey fir smjh nhi ata aisa is exercise me bht baar hua hai please don't ignore this sir kyoki apki iye video bcchy har saal dekhte hai
in question 9 you have not divided the coefficient of x that is 1/2
Sir agar 2 cosa.cosb =cos (a+b).cos(a-b) hota hain to - ka simble aayega na sir 😢
When we multiplied cos6x from cos6x then why we have written again in multiply cos6x??
Sir I think u have missed some small points to explain luke in question 3..... 1+cos2(6x)/2....
Sir in the next step u didn't tell where did the denominator 2 went i myself had a lot to trouble understanding the aum so i had to switch videos for better explanation.....
Sir question number 9 ka X - tan x/2 + c hoga sir ❤
Sir paper me aane wale most quastion ko 1 video banao jisme sab chapter ke quastion ho please sir
Sir Mai October Se Last October Tak 10 chapter complete Kar liya harr ek introduction harr ek exercise and finally I am confident to go for my Board Exam and Thanks A Lot Sir 🙏 🙏 🎉🎉
Revision ? Bhai bohot kaam baaki hai
@@uditichibber3806 Revision Sath mai Kar Raha Tha ab Mera Physics Last Chal raha hai Revision English, Chemistry, Maths,Painting Ho gaya completed.
not the full size of the paper is visable so it is not possible to veiw the end of some question
Mene inki sari videos dekhi but hr video me koi na koi glti jrur hoti hai....
No hate but check kr liya kro sir😊
Congratulations🎉 sir finally 1M Subscriber completed👌💯
Sir qno4 me last me 1/4×6 hoga😊
Sir please make a video of all the formulaes of this chapter in one shot