Exampless of Maximizing Profit and Revenue using Calculus (MTH 145 Section 5- 6)

In this video, we use maximization and the second derivative test to find the maximum weekly profit given a specific situation. This also uses the idea of absolute or global extrema.
Note: This video is from a course I am teaching through my college but I share it in case others find it helpful! The section numbers match up with the textbook "Calculus for Business, Economics, Life Sciences, and Social Science 12th edition - Barnett".

[@cylin4052]

My math teacher never explains anything; but now i understand everything :) you helped me a lot thank you very much!

[@Consolous]

Thank you for the great explanations! Beautiful voice by the way :)

[@Sylvia_Mwai]

Thank you so much....I was able to finish my assignment after watching this video.....Once again Thank you

[@Mizjis82]

I really appreciate the way that you explained this concept.

[@ShaRo-oe7qj]

You explained everything well. Thanks!

[@dready262]

very methodical and clearly explained well done you have been of great asssistance

[@zainnoman1698]

thank you so much :)

[@libetrashoko4421]

Suppose that the output, y, sells for $4.00 per unit and that x1 and x2 both sell for
$0.10 per unit? How much x1 and x2 would the farmer purchase in order to maximize profit?

[@tobiaschapinda6771]

G. A Mr. Malama wants to sell cheese. After a fixed set-up cost of k250, he can produce the cheese at a cost of k9 per kilogram. He is able to produce up to 400 kg, but he plans to take advance orders and produce only what he can sell. His market research suggests that the amount he would be able to sell depends on the price in the following way: the amount decreases proportionally with the price; if he charged k20 per kg he would not sell any, and if the cheese was free he would ‘sell’ the maximum 400 kg that he could produce. What price per kilogram should the farmer set in order to maximize his profit?

[@yagzyalcntas553]

Is there also SOC test in this vid?

[@tobiaschapinda6771]

A Mr. Peterson wants to sell cheese.After a fixed set-up cost of $250,
he can produce the cheese at a cost of $9 per kilogram.He is able to
produce up to 400kg,but he plans to take advance orders and
produce only what he can sell.His market research suggests that the
amount he would be able to sell depends on the price in the following
way:thea mount decreases proportionally with the price;if he
charged $20 per kg he would not sell any,and if the cheese was free
he would ‘sell’ the maximum 400kg that he could produce.What
price per kilogram should the farmer set in order to maximize his
profit?
Help me

[@ernestsand6425]

I think something's wrong with tje maximum profit..i got 66400 instead of 34000

[@ShaRo-oe7qj]

I think you calculated profit using .04x^2 instead of .4x^2