Shortcut tricks to solve cubic Equation in maths
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- Опубліковано 26 тра 2018
- Lec 1 shortcut tricks for tgt maths
Important for all exam : b.sc m.sc b.tech m.sc entrance exam tgt pgt Lt grade Dsssb ...by direct formula you can solve any questions in easy manner...it will also help you in competitive exam...objective questions will be given at the end of each chapter.......for more videos u can access link below lecture 1
• Geometry conic sections
lecture 4
• Conic section:vertex f... l
Lecture 3
• Conic section: Nature ...
Lecture 2
• Conic section: Asympto...
Lecture 5
• Conic section:centre :...
Fantastic technique!👌👌👌👍👍👍 Thanks for enlightening us!👍👍👍😊😊😊😊💐💐💐💐
Jabardast lecture h mdm ji
You are using the formula (x+a)(x+b)(x+c). Here the coefficient of x square is the sum of a,b and c i.e a+b+c
Next, the coefficient of x is (ab+bc+ca).
Superb trick
Thanks a lot, we want more of these.
Thank u for giving such a beautiful trick 😍😍😍
If alfa= A beeta =B and gamma =C
And the coefficient of x^3 is 1 then.....
A×B×C= constant term
A+B+C= coefficient of x^2
AB+BC+CA= coefficient of x
Old rule as in case of a quadratic equation.
Hehe
Like u class I'm first time watched ur videos
Is trick se phle me normal method se answer nikal dun
so beautifull and easy way to solve these questions.
Question no. 3 m factor + - 1 or + - 5 hoga or isme s choose karke -7 banana hoga or iska product ka addition 11 ke equal lana hoga
This is the process to solving these types of problems
Thank you mam🙏💕
Mam u help me. Lot,I don't care what people say,I wish I could talk with u personally and get many more such tricks in my head
Join telegram channel t.me/tsinghwal
bahut acchi video h apki ek baar me hi samajh aa gaya 😘😘😘😘
ans- 6) +2 , -(1/2) , -3
ans- 7) -2 , -3 , -4
ans- 8) I think question is wrong , there should be -50 instead of + 50 and then the ans will be , -2 , -5 , +5
N.B. Thank you for this awesome short trick , it helped me a lot ! 🙏
Thanks MA,its really helpful.
Philip Adonis
Thankyou sooo soo sooo much mam my all doubt are clear about cubic equations thanks a lot
This technique is actually reduced from the relation between roots & co-efficients of an algebraic equation..
Thank you so much mam 🙏🙏🙏🙏🙏
Thanks mam , bi quadratic equation upload kijiye
Explained very nicely and comfortable way to understand
Very best mem and thanks aapne bahut achhe se samjhaya
thanks for the trick and no of different questions .
Nice mam 🤘
Keep going 😊😊😊
Thank u so much
V.gd explnd tq its so use full
Thank you so much for this mam keep it up
u are silly dont say mam old man say madam
Thanks for encouraging me.
Very nice 👌👌👌 Miss, Aapne Samajhaya
Amazing trick mam ,suprb thankq
Don't get nervous.....Keep it upp...but
It doesn't use in another cubic ploynomial.
Nice
Thanks meam 4year se dought tha aaj clear ho gaya
Mam, its very understanding and informative video
You are too good..
Very excellent mam Bhut fast technique hay.
Guys don't depress her she has started making math videos after some time she will surely master it... Keep trying 😉😉😅🙂
Nice appreciation
Superb mam it was nice explanation and trick also
Wow i have no word to say🙏🙏
Thanks ma'am 👍
Ñyç trick video
Very helpful video for every one student 👍👍
Nice mam good trick
Best explanation 😍
Thanku so much for this trivk
Good job🙂too easy
Vry nc mam
nice. mam.. it. is. very helpful video
Very nice trick ma'am
Superb trick ma'am
Thank you so much
Thank you ma'am
There are two substitutions for cubics
Niccolo Fontana proposed x=u+v substitution
Francois Viete proposed y^2+xy=a to solve cubic equation
in the form x^3+3ax=2b
Thank you very much for this short trick. But what about higher order ie x^5+---------+x=0 or x^6+-----------+x=0 etc.?
expand (x+a)(x+b)(x+c)(x+d)(x+e)=0 then you will get the solution but it will be so hard because you will get a lot of letters.
Wow mam nice teacher
Mam no.4 me ham 16 ka cofactor 1,2 & 8 lene se aayga yaa nehi. nehi aa raha he mam. Kyu?
Same doubt..
Thank u for the trick that u showed me🤗
Very good trick dear
Super idea teacher
Very nice mam very easy trick
Waw amazing
U r genius
Very nice video ma'am
Gajab
in question 5 how anybody can think three random values.......the factor of 1 and also the sum will be -5/6...
Thank you for the video. In question 4 one could also choose the factor- 1 x 2x8=16, instead of repeating 4 again. Or is there a special rule behind choosing 4 again to match -16x in the equation.! Could you explain.
you can't get +1 for coefficient of x^2 in that combo of 1,2,8. that's why mam took her combination.
#Gajab trick mam
Hahahahhaa....this is easy whenever no sign change in the coefficient of the equation...
But you can't get in otherwise case...
So conclusion is here :- this is not applied for shortcut rule
You can refer b.s.grewal's numerical analysis book if you want to explore this
Md amir hamza
@Ankit Kumar nhi hota bhai
Well understood but... Plz provide trick for root type polynomial
Good trick
Mam which pen u use?.. explanation awesome lovely.
You are understanding better mam
*very nice video*
Thnx a lot
This is great. I only wish it was in English.
Very nice trick mem
Good job........
Best trick !!
Nice Lecture
Thanks mam
Thanx ma'am.
Very good trick
Great ma'am 👌👌
Thanks allot 😊 mam
great job mem ji
Ya its applicable for some special type question...
😏 saab kw liye ha bhai
chutiya
6) 2, -3, -1/2
7) -6, -12, -8
8) -2, -5, 5
Sol. 7: -2, -3, -4
Thank you
Jabardast.....
Is there any trick to solve biquad equation that is x to the power 4 ?
Happy teacher's day,mam
Amazing trick
Hit and trial method is more convenient.
Let us try: try X=1
Both LHS =\ r h s
Try with X= - 1
This is one solution
We can solve it
Yes.
Ds s...
Great mam nice trick
Hey ,you this is given in NCERT book only , this is called hit and trial not a trick
can you solve that unsolved examples i have difficult y
Please give the trick to find roots of polynomial of degree 4
Thanks didi
Bharat ke flag ko dekhta hu koun like karta ha🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳🇮🇳
Irrelevant
Good for children
Thans mam
How to solve d eq if there is no x^2 term?
Thanks
Mam 4 root vale equation ko solve karne ka shortcuts or longcut mathad ka vedio bana dijiyega please 🙏🙏🙏
we can't use this method to solve all cubic equations, pls tell some other method
I had difficulty using this trick when there are coefficients involved