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Sir 22 binary equivalent is 10110 not 10111 (this would be 23 )
Clear cut explanation your super...
I think on case 1 you should first have splitted bucket 1, so they would have got LD = 2, that would have not needed the case 2 and also you are mapping 00 to a bucket which have 11 (01011), so this is wrong also.
Iam unable to understand local depth?
Local depth is based on bucket size which is 3
thanks a lot sir
Thankyou so much sir
👌👌👌👌👌👌
Sir 22 binary equivalent is 10110 not 10111 (this would be 23 )
Clear cut explanation your super...
I think on case 1 you should first have splitted bucket 1, so they would have got LD = 2, that would have not needed the case 2 and also you are mapping 00 to a bucket which have 11 (01011), so this is wrong also.
Iam unable to understand local depth?
Local depth is based on bucket size which is 3
thanks a lot sir
Thankyou so much sir
👌👌👌👌👌👌