Honestly, F is usually placed on that axis for the purpose of making the slope easier to understand, but it's typically the independent variable and should be on the x-axis. It's a case of bad etiquette for the purpose of helping students learn.
Hi, I'm kinda confused here, I understand the way you drew the graph with Force on the Y-axis is the only way for the gradient to be equal to the spring constant, but doesn't putting force on the y-axis suggest that the force is dependent on the extension, which i don't get cause the spring extends the amount it does due to the force applied, not the other way around, right?
Busted, you are right, dang independent / dependent variable stuff. Often though on the education side we set up the graph so that the slope is easily recognized. If we would have graphed it with displacement on the y-axis, then our slope would have been the inverse of the spring constant. Most students wouldn't catch that when they do their regression, so we manipulate the graph so the students can understand the results. If that makes sense.
![Hooke's Law Experiment [VID 1b] | Plotting Of Graph, Finding of Slope, Gradient & Intercept.](/img/n.gif)
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I'm glad your physics life is still intact. Wish youtube existed back in 97 when I was learning.
Thanks this will teally help me for my exam
I got lost at The part where you were looking for where the slope cut the x,y axis pls explain
probably too late to help now, but hopefully you figured it out. I had my notifications off.
Is it compulsory for F to be at the vertical
Honestly, F is usually placed on that axis for the purpose of making the slope easier to understand, but it's typically the independent variable and should be on the x-axis. It's a case of bad etiquette for the purpose of helping students learn.
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Hi, I'm kinda confused here, I understand the way you drew the graph with Force on the Y-axis is the only way for the gradient to be equal to the spring constant, but doesn't putting force on the y-axis suggest that the force is dependent on the extension, which i don't get cause the spring extends the amount it does due to the force applied, not the other way around, right?
Busted, you are right, dang independent / dependent variable stuff. Often though on the education side we set up the graph so that the slope is easily recognized. If we would have graphed it with displacement on the y-axis, then our slope would have been the inverse of the spring constant. Most students wouldn't catch that when they do their regression, so we manipulate the graph so the students can understand the results. If that makes sense.
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